Question Number 139521 by mnjuly1970 last updated on 28/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:#\:\:\:{nice}\:…\:{calculus}# \\ $$$$\:\:\:\:\:\:\:\:{if}\:\:\:\:\left({pq}\right)^{{sin}^{\mathrm{2}} \left({x}\right)} +\left({pq}\right)^{{cos}^{\mathrm{2}} \left({x}\right)} ={p}+{q} \\ $$$$\:\:\:\:\:\:\:\:\:\:{then}\:\:\:\:{tan}\left({x}\right)=? \\ $$ Answered by qaz last updated…
Question Number 73982 by mhmd last updated on 17/Nov/19 $${if}\:{p}_{{r}} ^{{n}} =\mathrm{49}\:,\:{c}_{{r}} ^{{n}} =\mathrm{196}\:{find}\:{the}\:{valve}\:{of}\:{r}\:{and}\:{n}? \\ $$$${pleas}\:{sir}\:{help}\:{me} \\ $$ Commented by som(math1967) last updated on 17/Nov/19…
Question Number 73983 by mhmd last updated on 17/Nov/19 $${if}\:{p}_{{r}} ^{{n}} =\mathrm{49}\:,\:{c}_{{r}} ^{{n}} =\mathrm{196}\:{find}\:{the}\:{valve}\:{of}\:{r}\:{and}\:{n}? \\ $$$${pleas}\:{sir}\:{help}\:{me} \\ $$ Answered by $@ty@m123 last updated on 17/Nov/19…
Question Number 73974 by Raxreedoroid last updated on 17/Nov/19 $$\mathrm{Prove}\:\mathrm{this}\:\mathrm{equation} \\ $$$$\frac{\mathrm{2}^{{x}−\mathrm{1}} \left({x}−\frac{\mathrm{1}}{\mathrm{2}}\right)!}{\frac{\mathrm{1}}{\mathrm{2}}!}=\frac{\left(\mathrm{2}{x}−\mathrm{1}\right)!}{\mathrm{2}^{{x}−\mathrm{1}} \left({x}−\mathrm{1}\right)!} \\ $$ Answered by mind is power last updated on 17/Nov/19…
Question Number 139505 by bemath last updated on 28/Apr/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{3}} \: \\ $$$$\mathrm{when}\:\mathrm{3x}+\mathrm{4y}=\mathrm{5} \\ $$ Commented by mr W last updated on 28/Apr/21 $$\mathrm{3}{x}+\mathrm{4}{y}=\mathrm{5}\:\Rightarrow{y}\in\left(−\infty,\infty\right)…
Question Number 139506 by I want to learn more last updated on 28/Apr/21 Commented by I want to learn more last updated on 28/Apr/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{double}\:\mathrm{line}\:\mathrm{angle}.…
Question Number 139501 by aliibrahim1 last updated on 28/Apr/21 Answered by mr W last updated on 28/Apr/21 $$\left({x}+\mathrm{3}{i}\right)^{\mathrm{100}} =−\mathrm{1}={e}^{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi{i}} \\ $$$${x}_{{k}} +\mathrm{3}{i}={e}^{\frac{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi}{\mathrm{100}}{i}} \\ $$$${x}_{{k}} ={e}^{\frac{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi}{\mathrm{100}}{i}}…
Question Number 73964 by arkanmath7@gmail.com last updated on 17/Nov/19 $${if}\:{Im}\left({f}\:'\left({z}\right)\right)\:=\mathrm{6}{x}\left(\mathrm{2}{y}−\mathrm{1}\right)\:{and}\: \\ $$$${f}\left(\mathrm{0}\right)=\mathrm{3}−\mathrm{2}{i}\:,\:{f}\left(\mathrm{1}\right)=\mathrm{6}−\mathrm{5}{i}\: \\ $$$${find}\:{f}\left(\mathrm{1}+{i}\right)? \\ $$ Answered by mind is power last updated on 17/Nov/19…
Question Number 139502 by bemath last updated on 28/Apr/21 $$\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{8x}}\:\leqslant\:\mathrm{24}−\left(\mathrm{x}+\mathrm{2}\right)\left(\mathrm{x}+\mathrm{6}\right) \\ $$$$ \\ $$ Answered by TheSupreme last updated on 28/Apr/21 $${domain}:\:{x}<−\mathrm{8}\:\vee\:{x}>\mathrm{0} \\ $$$$\begin{cases}{\mathrm{24}−\left({x}+\mathrm{2}\right)\left({x}+\mathrm{6}\right)>\mathrm{0}\rightarrow\mathrm{12}−{x}^{\mathrm{2}}…
Question Number 8427 by tawakalitu last updated on 10/Oct/16 $$\mathrm{In}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{PQRST}\:\mathrm{center}\:\mathrm{O},\:\mathrm{PQRS}\:\mathrm{is}\:\mathrm{a}\: \\ $$$$\mathrm{cyclic}\:\mathrm{quadrilateral}\:\mathrm{and}\:\mathrm{T}\:\mathrm{is}\:\mathrm{on}\:\mathrm{the}\:\mathrm{circle}. \\ $$$$\mathrm{QS}\:\mathrm{is}\:\mathrm{a}\:\mathrm{diameter}\:\mathrm{and}\:\mathrm{angle}\:\mathrm{QOR}\:\mathrm{is}\:\mathrm{86}° \\ $$$$\mathrm{if}\:\mathrm{PTQ}\:\mathrm{is}\:\mathrm{28}°\:.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{quadrilateral}\:\mathrm{PQRS}. \\ $$ Answered by sandy_suhendra last updated…