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Author: Tinku Tara

Four-integers-are-chosen-at-random-from-0-to-9-inclusive-Find-the-probability-that-no-more-than-2-integers-are-the-same-

Question Number 3881 by Yozzii last updated on 23/Dec/15 $${Four}\:{integers}\:{are}\:{chosen}\:{at}\:{random} \\ $$$${from}\:\mathrm{0}\:{to}\:\mathrm{9},\:{inclusive}.\:{Find}\:{the} \\ $$$${probability}\:{that}\:{no}\:{more}\:{than} \\ $$$$\mathrm{2}\:{integers}\:{are}\:{the}\:{same}.\: \\ $$$$ \\ $$ Commented by RasheedSindhi last updated…

Question-134949

Question Number 134949 by rexford last updated on 08/Mar/21 Answered by bobhans last updated on 30/Jan/22 $$\overset{\rightarrow} {\mathrm{b}}\:=\:\mathrm{2}\overset{\rightarrow} {\mathrm{c}}+\lambda\overset{\rightarrow} {\mathrm{a}}\:;\:\mid\overset{\rightarrow} {\mathrm{b}}\mid\:=\:\mid\mathrm{2}\overset{\rightarrow} {\mathrm{c}}+\lambda\overset{\rightarrow} {\mathrm{a}}\mid \\ $$$$\Rightarrow\:\mathrm{4}\:=\:\sqrt{\mid\mathrm{2}\overset{\rightarrow}…

What-is-the-area-of-overlapping-region-of-two-circles-having-radii-r-1-and-r-2-when-the-distance-between-their-centres-is-c-given-that-r-1-r-2-gt-c-

Question Number 3877 by Rasheed Soomro last updated on 23/Dec/15 $$\mathcal{W}{hat}\:{is}\:{the}\:{area}\:{of}\:\:{overlapping} \\ $$$${region}\:{of}\:{two}\:{circles}\:{having}\:{radii} \\ $$$$\boldsymbol{\mathrm{r}}_{\mathrm{1}} \:{and}\:\boldsymbol{\mathrm{r}}_{\mathrm{2}} \:{when}\:{the}\:{distance}\:{between} \\ $$$${their}\:{centres}\:{is}\:\:\boldsymbol{\mathrm{c}},\:{given}\:{that}\:\boldsymbol{\mathrm{r}}_{\mathrm{1}} +\boldsymbol{\mathrm{r}}_{\mathrm{2}} >\boldsymbol{\mathrm{c}}. \\ $$ Commented by…

Question-69413

Question Number 69413 by ahmadshah last updated on 23/Sep/19 Commented by kaivan.ahmadi last updated on 23/Sep/19 $$\frac{\left(\mathrm{5}×\frac{\mathrm{4}}{\mathrm{5}}\right)^{{log}_{\frac{\mathrm{5}}{\mathrm{4}}} \mathrm{4}} }{\mathrm{5}^{{log}_{\frac{\mathrm{5}}{\mathrm{4}}} \mathrm{5}} }=\frac{\mathrm{5}^{{log}_{\frac{\mathrm{5}}{\mathrm{4}}} \mathrm{4}} ×\left(\frac{\mathrm{4}}{\mathrm{5}}\right)^{{log}_{\frac{\mathrm{5}}{\mathrm{4}}} \mathrm{4}} }{\mathrm{5}^{{log}_{\frac{\mathrm{5}}{\mathrm{4}}}…