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Question-69393

Question Number 69393 by 06 last updated on 23/Sep/19 Commented by Prithwish sen last updated on 23/Sep/19 $$\left(\mathrm{3}^{\mathrm{t}} +\mathrm{3}^{−\mathrm{t}} \right)^{\mathrm{3}} =\:\mathrm{5}^{\mathrm{3}} \Rightarrow\mathrm{27}^{\mathrm{t}} +\mathrm{27}^{−\mathrm{t}} +\mathrm{3}.\mathrm{3}^{\mathrm{t}} .\mathrm{3}^{−\mathrm{t}}…

How-many-dimention-s-does-the-point-have-

Question Number 3850 by Rasheed Soomro last updated on 22/Dec/15 $${How}\:{many}\:{dimention}/{s}\:{does}\:{the}\:{point}\:{have}? \\ $$ Commented by prakash jain last updated on 22/Dec/15 $$\mathrm{In}\:\mathrm{3D}\:\mathrm{cartesian}\:\mathrm{coordinate}\:\mathrm{you}\:\mathrm{need}\:\left({x},{y},{z}\right) \\ $$$$\mathrm{to}\:\mathrm{uniquely}\:\mathrm{describe}\:\mathrm{a}\:\mathrm{point}. \\…

Question-69385

Question Number 69385 by Maclaurin Stickker last updated on 23/Sep/19 Answered by Maclaurin Stickker last updated on 23/Sep/19 $${There}\:{is}\:{another}\:{way}\:{to}\:{solve}\:{this} \\ $$$${question}\:{just}\:{using}\:{algebra}: \\ $$$$\frac{{FD}}{\mathrm{1}}=\frac{{x}}{{x}+\mathrm{1}}\Rightarrow{FD}=\frac{{x}}{{x}+\mathrm{1}}\:{Now}\:{we}\:{can}\:{use} \\ $$$${Pythagorean}\:{theorem}\:{on}\:\bigtriangleup{FDE}:…

Let-the-side-of-the-following-mentioned-figures-is-s-The-area-of-square-is-s-2-the-3D-area-volume-of-a-cube-is-s-3-the-4D-area-volume-of-4D-hypercube-can-be-said-s-4-and-so-on-Now-if-radius-is

Question Number 3843 by Rasheed Soomro last updated on 22/Dec/15 $$\mathcal{L}{et}\:{the}\:{side}\:{of}\:{the}\:{following}\:{mentioned} \\ $$$${figures}\:{is}\:\boldsymbol{\mathrm{s}}: \\ $$$${The}\:{area}\:{of}\:{square}\:{is}\:\boldsymbol{\mathrm{s}}^{\mathrm{2}} ,\:{the}\:\mathrm{3}{D}\:{area}\left({volume}\right) \\ $$$${of}\:{a}\:{cube}\:{is}\:\boldsymbol{\mathrm{s}}^{\mathrm{3}} ,{the}\:\mathrm{4}{D}\:{area}/{volume}\:{of}\:\mathrm{4}{D} \\ $$$${hypercube}\:{can}\:{be}\:{said}\:\boldsymbol{\mathrm{s}}^{\mathrm{4}} \:{and}\:{so}\:{on}. \\ $$$$ \\…

Given-a-b-5ab-b-c-7bc-c-a-6ac-where-a-b-c-0-Find-abc-

Question Number 134912 by bramlexs22 last updated on 08/Mar/21 $$\mathrm{Given}\:\begin{cases}{\mathrm{a}+\mathrm{b}=\mathrm{5ab}}\\{\mathrm{b}+\mathrm{c}=\mathrm{7bc}}\\{\mathrm{c}+\mathrm{a}=\mathrm{6ac}}\end{cases} \\ $$$$\mathrm{where}\:\mathrm{a},\mathrm{b},\mathrm{c}\:\neq\:\mathrm{0}. \\ $$$$\mathrm{Find}\:\mathrm{abc} \\ $$ Answered by Ñï= last updated on 08/Mar/21 $$\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}=\mathrm{5}\Leftrightarrow{A}+{B}=\mathrm{5} \\…

Question-134915

Question Number 134915 by BHOOPENDRA last updated on 08/Mar/21 Answered by Olaf last updated on 08/Mar/21 $$\mathrm{Fourier}\:: \\ $$$${a}_{\mathrm{0}} \left({f}\right)\:=\:\frac{\mathrm{1}}{\mathrm{T}}\int_{−\frac{\mathrm{T}}{\mathrm{2}}} ^{+\frac{\mathrm{T}}{\mathrm{2}}} {f}\left({t}\right){dt} \\ $$$${a}_{\mathrm{0}} \left({f}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}\int_{−\mathrm{1}}…