Question Number 135169 by bramlexs22 last updated on 11/Mar/21 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{when}\: \\ $$$$\mathrm{x}^{\mathrm{81}} +\mathrm{x}^{\mathrm{49}} +\mathrm{x}^{\mathrm{25}} +\:\mathrm{x}^{\mathrm{9}} +\:\mathrm{x}\:\mathrm{is}\:\mathrm{divided} \\ $$$$\mathrm{by}\:\mathrm{x}^{\mathrm{3}} +\mathrm{x}\: \\ $$ Terms of Service Privacy…
Question Number 135170 by bramlexs22 last updated on 11/Mar/21 $$\mathrm{1}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{3}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{4}}{\mathrm{3}^{\mathrm{3}} }+\frac{\mathrm{5}}{\mathrm{3}^{\mathrm{4}} }+\frac{\mathrm{6}}{\mathrm{3}^{\mathrm{5}} }+…\:=?\: \\ $$$$ \\ $$ Answered by bemath last updated on 11/Mar/21…
Question Number 135165 by Dwaipayan Shikari last updated on 10/Mar/21 $${Solve}\:{Brachistochrone}\:{Curve}\:{Problem} \\ $$ Commented by Dwaipayan Shikari last updated on 10/Mar/21 $${I}\:{have}\:{a}\:{combined}\:{solution}.\:{But}\:{i}\:{want}\:{to}\:{know}\:{others} \\ $$$$\left.{Solutions}\::\right) \\…
Question Number 135167 by mey3nipaba last updated on 10/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 4092 by Filup last updated on 28/Dec/15 $$\mathrm{Prove}: \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{n}!}{\left({n}−{k}\right)!\:{k}!}=\mathrm{2}^{{n}} −\mathrm{1} \\ $$ Answered by Yozzii last updated on 28/Dec/15 $${According}\:{to}\:{the}\:{Binomial}\:{Theorem},…
Question Number 69623 by aliesam last updated on 25/Sep/19 $$\int\frac{\mathrm{1}}{\:\sqrt{{x}}\:+\:\sqrt[{\mathrm{3}}]{{x}}}\:{dx} \\ $$ Answered by MJS last updated on 25/Sep/19 $$\mathrm{we}\:\mathrm{had}\:\mathrm{this}\:\mathrm{before}… \\ $$$$\int\frac{{dx}}{{x}^{\mathrm{1}/\mathrm{2}} +{x}^{\mathrm{1}/\mathrm{3}} }= \\…
Question Number 69620 by aseer imad last updated on 25/Sep/19 Commented by kaivan.ahmadi last updated on 26/Sep/19 $${b}\:{is}\:{answer}\:{since}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{5}}\left(\mathrm{4},\mathrm{0},−\mathrm{3}\right).\left(\mathrm{3},−\mathrm{1},\mathrm{4}\right)=\frac{\mathrm{1}}{\mathrm{5}}\left(\mathrm{12}+\mathrm{0}−\mathrm{12}\right)=\mathrm{0}\Rightarrow\overset{\rightarrow} {{b}}\:{is} \\ $$$${perpendicular}\:{to}\:\mathrm{3}{i}−{j}+\mathrm{4}{k} \\ $$$${and}…
Question Number 135158 by Hamid52 last updated on 10/Mar/21 $$\left\{\mathrm{2},\mathrm{3}\right\}\square\left\{\mathrm{1},\mathrm{5}\right\}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 69616 by azizullah last updated on 25/Sep/19 Commented by Prithwish sen last updated on 25/Sep/19 $$\mathrm{After}\:\mathrm{10}\:\mathrm{years}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{will}\:\mathrm{be}\:\mathrm{40}+\mathrm{20}=\mathrm{60}\:\mathrm{years} \\ $$$$\mathrm{After}\:\mathrm{10}\:\mathrm{years} \\ $$$$\:\:\:\mathrm{shabena}\:\mathrm{will}\:\mathrm{be}\:=\:\frac{\mathrm{1}}{\mathrm{3}}×\mathrm{60}\:=\:\mathrm{20}\:\mathrm{years} \\ $$$$\mathrm{maria}\:\mathrm{will}\:\mathrm{be}\:=\frac{\mathrm{2}}{\mathrm{3}}\:×\mathrm{60}\:=\:\mathrm{40}\:\mathrm{years} \\…
Question Number 4080 by Rasheed Soomro last updated on 27/Dec/15 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{inside}\:\mathrm{a}\:\mathrm{square},\:\mathrm{a}\:\mathrm{semi}-\mathrm{circle}, \\ $$$$\mathrm{which}\:\mathrm{touches}\:\mathrm{all}\:\mathrm{the}\:\mathrm{four}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{square},\:\mathrm{is}\:\mathrm{possible}\:\mathrm{with}\:\boldsymbol{\mathrm{ruler}}\:\mathrm{and}\:\boldsymbol{\mathrm{compass}}. \\ $$ Commented by Rasheed Soomro last updated on 29/Dec/15…