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Question-134890

Question Number 134890 by Khalmohmmad last updated on 08/Mar/21 Answered by bemath last updated on 08/Mar/21 $$\mathrm{let}\:{a}\:=\:\mathrm{16}.\mathrm{2}\overset{−} {\mathrm{7}}\:;\:\mathrm{10}{a}\:=\:\mathrm{162}.\overset{−} {\mathrm{7}} \\ $$$$\Rightarrow\:{a}\:=\:\frac{\mathrm{146}.\mathrm{5}}{\mathrm{9}} \\ $$$$\mathrm{let}\:{b}\:=\:\mathrm{15}.\mathrm{1}\overset{−} {\mathrm{7}}\:;\:\mathrm{10}{b}\:=\:\mathrm{151}.\overset{−} {\mathrm{7}}…

if-2x-3-2-a-x-f-t-dt-then-f-a-

Question Number 134884 by abdullahquwatan last updated on 08/Mar/21 $$\mathrm{if}\:\mathrm{2x}^{\mathrm{3}} −\mathrm{2}=\int_{{a}} ^{\mathrm{x}} \mathrm{f}\left(\mathrm{t}\right)\mathrm{dt},\:\mathrm{then}\:\mathrm{f}\:'\left({a}\right)=… \\ $$ Answered by bemath last updated on 08/Mar/21 $$\:\frac{\mathrm{d}}{\mathrm{dx}}\:\left[\:\mathrm{2x}^{\mathrm{3}} −\mathrm{2}\:\right]=\:\mathrm{f}\left(\mathrm{x}\right) \\…

If-a-well-is-dug-21m-deep-and-1-4m-in-radius-how-much-earth-is-dug-out-from-it-If-the-inner-wall-of-well-is-plastered-at-Rupees-20-per-m-2-WHAT-WILL-BE-ITS-COST-

Question Number 69347 by Askash last updated on 22/Sep/19 $${If}\:{a}\:{well}\:{is}\:{dug}\:\mathrm{21}{m}\:{deep}\:{and}\:\mathrm{1}.\mathrm{4}{m} \\ $$$${in}\:{radius},\:{how}\:{much}\:{earth}\:{is}\:{dug} \\ $$$${out}\:{from}\:{it}?\:{If}\:{the}\:{inner}\:{wall}\:{of} \\ $$$${well}\:{is}\:{plastered}\:{at}\:\:{Rupees}\:\mathrm{20}\: \\ $$$${per}\:{m}^{\mathrm{2}} .\:{WHAT}\:\:\mathbb{WILL}\:\:{BE}\:\:{ITS} \\ $$$$\mathcal{COST}\:? \\ $$$$ \\ $$$$…

A-chord-divides-the-circle-in-two-segments-having-areas-s-1-and-s-2-If-diameter-perpendicular-to-this-chord-is-cut-into-1-3-by-the-chord-what-is-s-1-s-2-

Question Number 3808 by Rasheed Soomro last updated on 21/Dec/15 $${A}\:{chord}\:{divides}\:\:{the}\:{circle}\:{in}\:{two} \\ $$$${segments},{having}\:{areas}\:{s}_{\mathrm{1}} \:{and}\:\:{s}_{\mathrm{2}} . \\ $$$${If}\:{diameter},\:{perpendicular}\:{to}\:{this} \\ $$$${chord}\:{is}\:{cut}\:{into}\:\mathrm{1}:\mathrm{3}\:{by}\:{the}\:{chord}\:,{what}\:{is}\:{s}_{\mathrm{1}} :{s}_{\mathrm{2}} \:? \\ $$$$ \\ $$…

n-0-2n-1-2-2n-1-

Question Number 3807 by Rasheed Soomro last updated on 21/Dec/15 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{2}{n}+\mathrm{1}}{\mathrm{2}^{\mathrm{2}{n}+\mathrm{1}} }=? \\ $$ Answered by Yozzii last updated on 21/Dec/15 $${s}=\underset{{n}=\mathrm{0}} {\overset{\infty}…

Question-134878

Question Number 134878 by bemath last updated on 08/Mar/21 Answered by EDWIN88 last updated on 08/Mar/21 $$\mathrm{B}\left(\theta\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}.\mathrm{100}.\mathrm{sin}\:\theta\:=\:\mathrm{50}\:\mathrm{sin}\:\theta\: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{radius}\:\mathrm{of}\:\mathrm{semi}\:\mathrm{circle}\:\mathrm{is}\:\mathrm{r}\:=\:\mathrm{10}.\mathrm{sin}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\theta\right) \\ $$$$\mathrm{so}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{semi}\:\mathrm{circle}\:\mathrm{A}\left(\theta\right)=\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\mathrm{100}.\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{2}}\theta\right)\right) \\ $$$$\mathrm{A}\left(\theta\right)\:=\:\mathrm{50}\pi\:\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{2}}\theta\right)…

Question-69338

Question Number 69338 by Rasheed.Sindhi last updated on 22/Sep/19 Commented by Prithwish sen last updated on 22/Sep/19 $$\mathrm{it}\:\mathrm{is}\:\mathrm{the}\:\mathrm{series}\:\mathrm{of} \\ $$$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{5}}−\frac{\mathrm{1}}{\mathrm{7}}+…… \\ $$$$\mathrm{tan}^{−\mathrm{1}} \mathrm{x}=\mathrm{x}−\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{3}}+\frac{\mathrm{x}^{\mathrm{5}} }{\mathrm{5}}−\frac{\mathrm{x}^{\mathrm{7}}…

Question-134875

Question Number 134875 by bemath last updated on 08/Mar/21 Commented by bemath last updated on 08/Mar/21 $$\mathrm{The}\:\mathrm{figure}\:\mathrm{shows}\:\mathrm{a}\:\mathrm{point}\:\mathrm{P}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{parabola}\:\mathrm{y}=\mathrm{x}^{\mathrm{2}} \:\mathrm{and}\:\mathrm{the}\:\mathrm{point}\:\mathrm{Q} \\ $$$$\mathrm{where}\:\mathrm{the}\:\mathrm{perpendicular}\:\mathrm{bisector} \\ $$$$\mathrm{of}\:\mathrm{OP}\:\mathrm{intersects}\:\mathrm{the}\:\mathrm{y}−\mathrm{axis}\:.\:\mathrm{As}\: \\…