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Question-73222

Question Number 73222 by Tanmay chaudhury last updated on 08/Nov/19 Answered by Tanmay chaudhury last updated on 08/Nov/19 $$\left[\overset{\rightarrow} {{a}}\overset{\rightarrow} {{b}}\overset{\rightarrow} {{c}}\right]=\mathrm{2}=\left(\overset{\rightarrow} {{a}}×\overset{\rightarrow} {{b}}\right).\overset{\rightarrow} {{c}}…

lim-0-0-lim-0-

Question Number 73223 by malwaan last updated on 08/Nov/19 $$\boldsymbol{{lim}}\:\frac{\mathrm{0}}{\infty}\:\overset{?} {=}\:\mathrm{0}\:? \\ $$$$\boldsymbol{{lim}}\:\frac{\infty}{\mathrm{0}}\:\overset{?} {=}\:\infty\:? \\ $$ Commented by MJS last updated on 08/Nov/19 $$\mathrm{these}\:\mathrm{are}\:\mathrm{not}\:\mathrm{of}\:\mathrm{correct}\:\mathrm{syntax}\:\Rightarrow\:\mathrm{we}\:\mathrm{cannot} \\…

f-81-1-3-2-9-1-3-4-2-1-3-

Question Number 7686 by Alimudin last updated on 09/Sep/16 $${f}\:×=\left(\mathrm{81}\right)\frac{\mathrm{1}}{\mathrm{3}}+\mathrm{2}\left(\mathrm{9}\right)\frac{\mathrm{1}}{\mathrm{3}}+\mathrm{4} \\ $$$$\left(\mathrm{2}+\frac{\mathrm{1}}{×}\right)^{\mathrm{3}} =… \\ $$$$ \\ $$ Commented by Rasheed Soomro last updated on 09/Sep/16…

Question-73221

Question Number 73221 by aliesam last updated on 08/Nov/19 Answered by MJS last updated on 08/Nov/19 $${A}=\begin{pmatrix}{\mathrm{0}}\\{\mathrm{0}}\end{pmatrix}\:\:{B}=\begin{pmatrix}{{a}}\\{\mathrm{0}}\end{pmatrix}\:\:{C}=\begin{pmatrix}{{a}}\\{{a}}\end{pmatrix}\:\:{D}=\begin{pmatrix}{\mathrm{0}}\\{{a}}\end{pmatrix} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{E}=\begin{pmatrix}{{b}}\\{\mathrm{0}}\end{pmatrix}\:\:{F}=\begin{pmatrix}{{b}}\\{{b}}\end{pmatrix}\:\:{G}=\begin{pmatrix}{\mathrm{0}}\\{{b}}\end{pmatrix} \\ $$$${T}=\begin{pmatrix}{\frac{{a}+{b}}{\mathrm{2}}}\\{\mathrm{0}}\end{pmatrix}\:\:{I}=\begin{pmatrix}{\frac{{a}+{b}}{\mathrm{2}}}\\{\frac{{a}−{b}}{\mathrm{2}}}\end{pmatrix} \\ $$$${M}=\begin{pmatrix}{{b}}\\{\frac{{a}−{b}}{\mathrm{2}}}\end{pmatrix}\:\:{N}=\begin{pmatrix}{\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}\left({a}+{b}\right)+{b}}\\{\frac{\mathrm{3}{a}−{b}}{\mathrm{4}}}\end{pmatrix}\:\:{L}=\begin{pmatrix}{{b}}\\{{a}}\end{pmatrix} \\ $$$$\mathrm{radius}\:\mathrm{of}\:\mathrm{incircle}\:\mathrm{of}\:{ETIM}=\frac{{r}}{\mathrm{2}}=\frac{{a}−{b}}{\mathrm{4}}…

A-committee-of-3-members-is-to-be-formed-from-8-members-Find-the-number-of-committees-that-can-be-formed-if-two-particular-club-members-cannot-both-be-in-a-committee-

Question Number 138748 by physicstutes last updated on 17/Apr/21 $$\mathrm{A}\:\mathrm{committee}\:\mathrm{of}\:\mathrm{3}\:\mathrm{members}\:\mathrm{is}\:\mathrm{to}\:\mathrm{be}\:\mathrm{formed}\:\mathrm{from}\:\mathrm{8}\:\mathrm{members}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{committees}\:\mathrm{that}\:\mathrm{can}\:\mathrm{be}\:\mathrm{formed}\:\mathrm{if}\:\mathrm{two}\:\mathrm{particular} \\ $$$$\mathrm{club}\:\mathrm{members}\:\mathrm{cannot}\:\mathrm{both}\:\mathrm{be}\:\mathrm{in}\:\mathrm{a}\:\mathrm{committee} \\ $$ Answered by mr W last updated on 17/Apr/21 $${C}_{\mathrm{3}}…