Menu Close

Author: Tinku Tara

P-n-1-k-n-n-P-

Question Number 7651 by FilupSmith last updated on 07/Sep/16 $${P}=\underset{{n}=\mathrm{1}} {\overset{{k}} {\prod}}{n}^{{n}} \\ $$$${P}=??? \\ $$ Commented by FilupSmith last updated on 07/Sep/16 $${P}=\mathrm{1}\left(\mathrm{2}×\mathrm{2}\right)\left(\mathrm{3}×\mathrm{3}×\mathrm{3}\right)\left(\mathrm{4}×\mathrm{4}×\mathrm{4}×\mathrm{4}\right)… \\…

advanced-math-prove-that-k-0-1-16-k-4-8k-1-2-8k-4-1-8k-5-1-8k-6-pi-Bailey-Borwein-formula-

Question Number 138723 by mnjuly1970 last updated on 17/Apr/21 $$\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:……..{advanced}…\:…\:…{math}…… \\ $$$$\:{prove}\:{that}\:_{\ast} ^{\ast} \:\::::: \\ $$$$\:\:\:\boldsymbol{\Omega}=\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\left\{\frac{\mathrm{1}}{\mathrm{16}^{{k}} }\left(\frac{\mathrm{4}}{\mathrm{8}{k}+\mathrm{1}}−\frac{\mathrm{2}}{\mathrm{8}{k}+\mathrm{4}}−\frac{\mathrm{1}}{\mathrm{8}{k}+\mathrm{5}}−\frac{\mathrm{1}}{\mathrm{8}{k}+\mathrm{6}}\right)\right\}=\pi \\ $$$$\:\:\:\:\:\:\:\:\:….{Bailey}−{Borwein}\:{formula}…. \\ $$$$\:\:\:…

the-sum-of-n-term-of-two-A-P-are-in-ratio-7n-1-4n-27-find-the-ratio-of-their-11-th-term-

Question Number 7649 by Rohit last updated on 07/Sep/16 $${the}\:{sum}\:{of}\:{n}\:{term}\:{of}\:{two}\:{A}.{P}\:{are}\:{in}\: \\ $$$${ratio}\:\frac{\mathrm{7}{n}+\mathrm{1}}{\mathrm{4}{n}+\mathrm{27}}\:.{find}\:{the}\:{ratio}\:{of}\:{their}\:\:\mathrm{11}^{{th}} \\ $$$${term}. \\ $$ Commented by Rohit last updated on 07/Sep/16 $${answer}\:{plese}….. \\…