Question Number 68414 by behi83417@gmail.com last updated on 10/Sep/19 $$\mathrm{Is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{find}\:\mathrm{any}\:\mathrm{value}\:\mathrm{for} \\ $$$$\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}},\boldsymbol{\mathrm{c}}\:\mathrm{from}\:\mathrm{below}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equetions}? \\ $$$$\begin{cases}{\boldsymbol{\mathrm{sina}}+\boldsymbol{\mathrm{sinb}}=\boldsymbol{\mathrm{sinc}}}\\{\boldsymbol{\mathrm{cosa}}+\boldsymbol{\mathrm{cosb}}=\boldsymbol{\mathrm{cosc}}}\end{cases} \\ $$ Commented by kaivan.ahmadi last updated on 10/Sep/19 $$\begin{cases}{{sinacosa}+{sinbcosa}={sinccosa}}\\{−{sinacosa}−{sinacosb}=−{sinacosc}}\end{cases}\Rightarrow \\…
Question Number 2878 by Yozzi last updated on 29/Nov/15 $${How}\:{many}\:{ordered}\:{pairs}\:\left({m},{n}\right)\:{are}\:{there} \\ $$$${for}\:\mathrm{1}\leqslant{m},{n}\leqslant\mathrm{100}\:{such}\:{that}\:\mathrm{7}^{{m}} +\mathrm{7}^{{n}} \\ $$$${is}\:{divisble}\:{by}\:\mathrm{5}? \\ $$ Commented by prakash jain last updated on 29/Nov/15…
Question Number 133951 by liberty last updated on 25/Feb/21 $$\:\mathcal{V}\:=\:\int\:\mathrm{ln}\:\left(\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:\right)\:\mathrm{dx}\: \\ $$ Answered by mathmax by abdo last updated on 25/Feb/21 $$\Phi\:=\int\:\mathrm{ln}\left(\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\right)\mathrm{dx}\:\mathrm{we}\:\mathrm{do}\:\mathrm{the}\:\mathrm{changement}\:\mathrm{x}=\mathrm{sht}\:\Rightarrow \\…
Question Number 133950 by liberty last updated on 25/Feb/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{9}\pi}{\mathrm{10}}\right).\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{7}\pi}{\mathrm{10}}\right). \\ $$ Answered by bobhans last updated on 25/Feb/21 Terms of…
Question Number 2874 by RasheedAhmad last updated on 29/Nov/15 $${What}\:{is}\:{the}\:{meaning}\:{of} \\ $$$$\left({i}\right)\:{z}\rightarrow\mathrm{0}\:\:\:\left({ii}\right)\:{z}\rightarrow{z}_{\mathrm{0}} \:\:\:{z},{z}_{\mathrm{0}} \in\mathbb{C} \\ $$ Answered by Filup last updated on 29/Nov/15 $$\left(\mathrm{1}\right) \\…
Question Number 68409 by mathmax by abdo last updated on 10/Sep/19 $${calculate}\:\int_{\mathrm{0}} ^{+\infty} \:\:\frac{{arctan}\left({x}^{\mathrm{2}} \right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$ Commented by mathmax by abdo last updated…
Question Number 133943 by mnjuly1970 last updated on 25/Feb/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…….{advanced}\:\:\:\:\:{calculus}…… \\ $$$$\:\:\:\:\:\:{prove}\:\:{that}: \\ $$$$\:\:\:\:\:\:\boldsymbol{\phi}=\:\:\int_{\mathrm{0}} ^{\:\infty} \frac{{cos}\left({x}^{\mathrm{2}} \right)−{cos}\left({x}\right)}{{x}}{dx}=\frac{\gamma}{\mathrm{2}} \\ $$$$\:\:\:\gamma:\:{euler}−{mascheroni}\:{constant}… \\ $$ Terms of Service Privacy…
Question Number 133942 by mathocean1 last updated on 25/Feb/21 $${calculate}\:{L}=\int_{{e}^{\mathrm{2}} } ^{\:{e}^{\mathrm{3}} } \:\frac{{ln}\left({x}\right)−\mathrm{1}}{{xlnx}}\:{dx} \\ $$$${Please}\:{detail}\:{if}\:{possibl}\overset{} {{e}} \\ $$ Answered by Ñï= last updated on…
Question Number 68405 by Tinku Tara last updated on 10/Sep/19 $$\mathrm{There}\:\mathrm{are}\:\mathrm{a}\:\mathrm{few}\:\mathrm{problem}\:\mathrm{reported}. \\ $$$$\mathrm{Notification}:\:\mathrm{google}\:\mathrm{discontinued} \\ $$$$\mathrm{Google}\:\mathrm{Cloud}\:\mathrm{Messaging}\:\mathrm{so}\:\mathrm{notifications} \\ $$$$\mathrm{are}\:\mathrm{not}\:\mathrm{working}.\: \\ $$$$\mathrm{Other}\:\mathrm{Problems}: \\ $$$$\mathrm{There}\:\mathrm{has}\:\mathrm{been}\:\mathrm{several}\:\mathrm{new}\:\mathrm{phone} \\ $$$$\mathrm{models}\:\mathrm{and}\:\mathrm{android}\:\mathrm{version}\:\mathrm{updates}. \\ $$$$\mathrm{And}\:\mathrm{newer}\:\mathrm{android}\:\mathrm{version}\:\mathrm{or}\:\mathrm{phone}…
Question Number 133937 by rexford last updated on 25/Feb/21 Answered by EDWIN88 last updated on 25/Feb/21 $$\boldsymbol{{AB}}\:=\:\hat {\boldsymbol{\mathrm{i}}}+\mathrm{6}\hat {\boldsymbol{\mathrm{j}}}\:,\:\mathrm{let}\:\mathrm{vector}\:\boldsymbol{\mathrm{u}}\:=\:\boldsymbol{\mathrm{AC}}\:\mathrm{where}\:\mathrm{C}\left(\mathrm{x},\mathrm{y}\right) \\ $$$$\boldsymbol{\mathrm{u}}=\left(\mathrm{x}−\mathrm{1},\mathrm{y}+\mathrm{1}\right)\:=\left(\mathrm{x}−\mathrm{1}\right)\hat {\boldsymbol{\mathrm{i}}}+\left(\mathrm{y}+\mathrm{1}\right)\hat {\boldsymbol{\mathrm{j}}} \\ $$$$\Rightarrow\:\boldsymbol{\mathrm{u}}.\boldsymbol{\mathrm{AB}}\:=\mathrm{0}\:\Rightarrow\mathrm{x}−\mathrm{1}+\mathrm{6y}+\mathrm{6}\:=\:\mathrm{0}…