Question Number 72824 by Rio Michael last updated on 03/Nov/19 $${fnd}\:{all}\:{integers}\:{n}\:{for}\:{which}\: \\ $$$$\:\mathrm{13}\mid\:\mathrm{4}\left({n}^{\mathrm{2}} \:+\:\mathrm{1}\right) \\ $$ Answered by mind is power last updated on 03/Nov/19…
Question Number 7289 by FilupSmith last updated on 21/Aug/16 $$\mathrm{For}\:\mathrm{any}\:\mathrm{number}\:{x}>\mathrm{1}:{x}\in\mathbb{Z} \\ $$$${x}\:\mathrm{can}\:\mathrm{be}\:\mathrm{expressed}\:\mathrm{as}\:\mathrm{a}\:\mathrm{combination} \\ $$$$\mathrm{of}\:\mathrm{numbers}\:\mathrm{multiplied}\:\mathrm{together}. \\ $$$$\mathrm{e}.\mathrm{g}. \\ $$$$\mathrm{10}=\mathrm{5}×\mathrm{2} \\ $$$$\mathrm{20}=\mathrm{5}×\mathrm{4}=\mathrm{5}×\mathrm{2}×\mathrm{2} \\ $$$$\mathrm{100}=\mathrm{10}×\mathrm{10}=\mathrm{5}×\mathrm{2}×\mathrm{5}×\mathrm{2} \\ $$$$\: \\…
Question Number 138362 by mohammad17 last updated on 12/Apr/21 $${prove}\:{that}\: \\ $$$$ \\ $$$$\left(\mathrm{1}+{i}\right)^{{n}} +\left(\mathrm{1}−{i}\right)^{{n}} =\mathrm{2}^{\frac{{n}+\mathrm{1}}{\mathrm{2}}} \\ $$ Commented by Dwaipayan Shikari last updated on…
Question Number 7287 by sarathon last updated on 21/Aug/16 $$\mathrm{7}{a}_{\mathrm{1}} +\mathrm{7}^{\mathrm{2}} {a}_{\mathrm{2}} +\centerdot\centerdot\centerdot+\mathrm{7}^{{n}} {a}_{{n}} =\mathrm{3}^{{n}} −\mathrm{1} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{a}_{{n}} }{\mathrm{3}^{{n}−\mathrm{1}} }=? \\ $$ Commented…
Question Number 72823 by Raxreedoroid last updated on 03/Nov/19 $$\mathrm{What}\:\mathrm{is}\:\mathrm{derivative}\:\mathrm{for}\:\mathrm{this}\:\mathrm{function} \\ $$$$\: \\ $$$${a}×{b}^{{x}−\mathrm{1}} ×{c}^{\frac{\mathrm{1}}{\mathrm{2}}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)} ×{d}^{\frac{\mathrm{1}}{\mathrm{6}}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)\left({x}−\mathrm{3}\right)} \\ $$ Answered by mind is power last updated…
Question Number 138355 by mohammad17 last updated on 12/Apr/21 Commented by mohammad17 last updated on 12/Apr/21 $${help}\:{me}\:{sir} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 138348 by EnterUsername last updated on 12/Apr/21 Commented by EnterUsername last updated on 12/Apr/21 Image courtesy of Anna Lachowska. Terms of Service Privacy…
Question Number 138350 by abenarhodym last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right) \\ $$ Answered by Ñï= last updated on 12/Apr/21 $$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} \left(\mathrm{2}^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{2}}} \right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{2}^{\mathrm{2}}…
Question Number 72813 by Learner-123 last updated on 03/Nov/19 $${Find}\:{the}\:{area}\:{of}\:{the}\:{region}\:{enclosed} \\ $$$${by}\:{the}\:{line}\:\mathrm{5}{y}={x}+\mathrm{6}\:{and}\:{the}\:{curve} \\ $$$${y}=\sqrt{\mid{x}\mid}\:. \\ $$ Commented by ajfour last updated on 03/Nov/19 Commented by…
Question Number 72806 by Rio Michael last updated on 03/Nov/19 $$\underset{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}\rightarrow\mathrm{0}} {\:{show}\:{that}\:\:\mathrm{lim}}\:\left[\:{x}\right]\:\:{does}\:{not}\:{exist}. \\ $$$${Hence}\:{define}\:\:\left[{x}\right]\:\:{and}\:{sketch}\:{a}\:{graph}\:{for}\: \\ $$$$\:{y}\:=\:\mathrm{3}{x}^{\mathrm{2}} \:+\:\left[{x}\right] \\ $$ Commented by mathmax by abdo last…