Question Number 2564 by Rasheed Soomro last updated on 22/Nov/15 $${A}=\begin{bmatrix}{\mathrm{1}}&{\mathrm{2}}\\{\mathrm{2}}&{\mathrm{5}}\end{bmatrix},{B}=\begin{bmatrix}{\mathrm{3}}&{−\mathrm{1}}\\{\mathrm{4}}&{+\mathrm{2}}\end{bmatrix} \\ $$$${determine}\:{A}^{{B}} \\ $$ Answered by Yozzi last updated on 22/Nov/15 $$\mid{A}\mid=\mathrm{5}−\mathrm{4}=\mathrm{1}\neq\mathrm{0}\:\Rightarrow{A}\:{is}\:{non}−{singular}. \\ $$$${A}^{{B}}…
Question Number 133633 by jahar last updated on 23/Feb/21 $${how}\:{to}\:{back}\:{up} \\ $$ Commented by Tinku Tara last updated on 23/Feb/21 Commented by Tinku Tara last…
Question Number 2562 by Tinku Tara last updated on 22/Nov/15 $$\mathrm{App}\:\mathrm{Updates}: \\ $$$$\mathrm{We}\:\mathrm{have}\:\mathrm{updated}\:\mathrm{the}\:\mathrm{app}\:\mathrm{with}\:\mathrm{below}\:\mathrm{changes}: \\ $$$$\bullet\:\boldsymbol{\mathrm{ad}}\:\boldsymbol{\mathrm{banner}}\:\boldsymbol{\mathrm{removed}}\:\boldsymbol{\mathrm{from}}\:\boldsymbol{\mathrm{all}}\:\boldsymbol{\mathrm{screens}} \\ $$$$\:\:\:\:\mathrm{This}\:\mathrm{provides}\:\mathrm{larger}\:\mathrm{screen}\:\mathrm{area}\:\mathrm{for} \\ $$$$\:\:\:\:\:\mathrm{equation}\:\mathrm{writing}\:\mathrm{and}\:\mathrm{avoids}\:\mathrm{distraction}. \\ $$$$\bullet\:\boldsymbol{\mathrm{confirmation}}\:\boldsymbol{\mathrm{on}}\:\boldsymbol{\mathrm{delete}}\:\boldsymbol{\mathrm{posts}}\:\boldsymbol{\mathrm{on}}\:\boldsymbol{\mathrm{Q}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{forum}} \\ $$ Commented by…
Question Number 68096 by mhmd last updated on 04/Sep/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 68094 by mhmd last updated on 04/Sep/19 $$\int{dx}/\sqrt[{{x}}]{\left(\pi+{e}\right)^{{x}^{\mathrm{2}} } }\: \\ $$ Answered by MJS last updated on 05/Sep/19 $$\int\frac{{dx}}{\:\sqrt[{{x}}]{\left(\pi+\mathrm{e}\right)^{{x}^{\mathrm{2}} } }}=\int\frac{{dx}}{\left(\pi+\mathrm{e}\right)^{{x}} }=−\frac{\mathrm{1}}{\left(\pi+\mathrm{e}\right)^{{x}}…
Question Number 133628 by Ñï= last updated on 23/Feb/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{{n}^{\mathrm{2}} +\mathrm{1}}{{n}^{\mathrm{2}} }\right)=? \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{4}{n}+\mathrm{2}}{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{4}{n}+\mathrm{1}}\right)=? \\ $$ Answered by Dwaipayan…
Question Number 68095 by mhmd last updated on 04/Sep/19 $$\int\sqrt{{x}}/\mathrm{1}+\sqrt[{\mathrm{3}}]{{x}\:}\:{dx} \\ $$ Answered by MJS last updated on 05/Sep/19 $$\int\frac{{x}^{\mathrm{1}/\mathrm{2}} }{\mathrm{1}+{x}^{\mathrm{1}/\mathrm{3}} }{dx}= \\ $$$$\:\:\:\:\:\left[{t}={x}^{\mathrm{1}/\mathrm{6}} \:\rightarrow\:{dx}=\mathrm{6}{x}^{\mathrm{5}/\mathrm{6}}…
Question Number 133631 by liberty last updated on 23/Feb/21 $$\mathrm{y}'\:=\:\frac{\mathrm{bx}+\mathrm{ay}}{\mathrm{ax}+\mathrm{by}} \\ $$ Answered by TheSupreme last updated on 23/Feb/21 $${caso}\:\mathrm{1}:\:{b}=\mathrm{0}\: \\ $$$${y}'=\frac{{ay}}{{ax}}=\frac{{y}}{{x}} \\ $$$${ln}\left({y}\right)={ln}\left({x}\right)+{c} \\…
Question Number 68092 by TawaTawa last updated on 04/Sep/19 Commented by TawaTawa last updated on 05/Sep/19 $$\mathrm{I}\:\mathrm{understand}\:\mathrm{very}\:\mathrm{well}\:\mathrm{now}\:\mathrm{sir}. \\ $$ Commented by kaivan.ahmadi last updated on…
Question Number 68087 by Mikael last updated on 04/Sep/19 $${Hello}\:{friends}!\:{I}\:{ask}\:{name}\:{of}\:{a}\:{high} \\ $$$${level}\:{book}\:{of}\:{integral}\:{calculus}. \\ $$ Commented by mathmax by abdo last updated on 04/Sep/19 $${search}\:\:{Vuibert}\:{or}\:{ellipses}\:{collection}. \\…