Question Number 67852 by mr W last updated on 01/Sep/19 Commented by Prithwish sen last updated on 01/Sep/19 $$ \\ $$$$\boldsymbol{\mathrm{A}}=\left(\mathrm{0},\boldsymbol{\mathrm{a}}\right),\:\boldsymbol{\mathrm{B}}\:=\:\left(\frac{−\mathrm{4}}{\boldsymbol{\mathrm{a}}},\mathrm{0}\right),\boldsymbol{\mathrm{C}}=\left(\frac{\mathrm{20}}{\boldsymbol{\mathrm{a}}},−\mathrm{9}\boldsymbol{\mathrm{a}}\right),\boldsymbol{\mathrm{D}}=\left(\frac{\mathrm{2}}{\boldsymbol{\mathrm{a}}},\mathrm{0}\right) \\ $$$$\boldsymbol{\mathrm{E}}=\left(\mathrm{0},\frac{−\mathrm{3}\boldsymbol{\mathrm{a}}}{\mathrm{2}}\right)\: \\ $$$$\mathrm{Equation}\:\mathrm{of}\:\mathrm{line}\:\mathrm{passing}\:\mathrm{through}\:\mathrm{A}\:\mathrm{and}\:\mathrm{D}…
Question Number 67850 by mathmax by abdo last updated on 01/Sep/19 $${calculate}\:\int_{−\infty} ^{+\infty} \:\:\frac{{dx}}{{x}^{\mathrm{2}} −{z}}\:\:{with}\:{z}\:{from}\:{C} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 67851 by mathmax by abdo last updated on 01/Sep/19 $${find}\:\int\:\:\frac{{dx}}{{x}^{\mathrm{2}} −{z}}\:\:{with}\:{z}\:{from}\:{C}\:. \\ $$ Commented by MJS last updated on 01/Sep/19 $$\mathrm{what}'\mathrm{s}\:\mathrm{the}\:\mathrm{problem}/\mathrm{mistake}\:\mathrm{if}\:\mathrm{we}\:\mathrm{just} \\ $$$$\mathrm{calculate}\:\mathrm{it}\:\mathrm{as}\:\mathrm{if}\:{z}\in\mathbb{R}?…
Question Number 67849 by mr W last updated on 01/Sep/19 Commented by MJS last updated on 01/Sep/19 $$\mathrm{is}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{in}\:\mathrm{the}\:\mathrm{center}\:\mathrm{90}°? \\ $$ Commented by mr W last…
Question Number 133381 by Dwaipayan Shikari last updated on 21/Feb/21 $$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }\left(\frac{\mathrm{1}}{\mathrm{2}.\mathrm{1}!}\right)+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }\left(\frac{\mathrm{1}.\mathrm{3}}{\mathrm{2}^{\mathrm{2}} .\mathrm{2}!}\right)+\frac{\mathrm{1}}{\mathrm{5}^{\mathrm{2}} }\left(\frac{\mathrm{1}.\mathrm{3}.\mathrm{5}}{\mathrm{2}^{\mathrm{3}} .\mathrm{3}!}\right)+…=\frac{\pi}{\mathrm{2}}{log}\left(\mathrm{2}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 67844 by aliesam last updated on 01/Sep/19 $${x}^{\mathrm{2}} +\mid{x}\mid−\mathrm{6}=\mathrm{0} \\ $$ Commented by gunawan last updated on 01/Sep/19 $$\mathrm{case}\:\mathrm{1}\:{x}<\mathrm{0} \\ $$$${x}^{\mathrm{2}} −{x}−\mathrm{6}=\mathrm{0} \\…
Question Number 2304 by Ashis last updated on 14/Nov/15 $${if}\:\:{x}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{9}=\:\mathrm{0}\:\:{then}\:{x}=? \\ $$ Answered by prakash jain last updated on 14/Nov/15 $${x}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{9} \\ $$$${x}=\frac{−\mathrm{5}\pm\sqrt{\left(−\mathrm{5}\right)^{\mathrm{2}}…
Question Number 2300 by Syaka last updated on 14/Nov/15 $${if}\:{f}\left(\mathrm{4}{xy}\right)\:=\:\mathrm{2}{y}\left({f}\left({x}\:−\:{y}\right)\:+\:{f}\left({x}\:+\:{y}\right)\right)\:{and}\:{f}\left(\mathrm{5}\right)\:=\:\mathrm{3} \\ $$$${what}\:{is}\:{the}\:{value}\:{of}\:{f}\left(\mathrm{2015}\right)\:=\:? \\ $$ Commented by Rasheed Soomro last updated on 17/Nov/15 $$\mathcal{EXCELLENT}\:! \\ $$…
Question Number 133369 by mnjuly1970 last updated on 21/Feb/21 $$\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{calculus}\:\left(\mathrm{2}\right)….. \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{1}} ^{\:\mathrm{2}} \left(\frac{{ln}\left(\frac{{x}+\mathrm{2}}{{x}+\mathrm{1}}\right)}{{x}}\right){dx}\:=??? \\ $$$$ \\ $$ Commented by Dwaipayan Shikari last…
Question Number 133368 by otchereabdullai@gmail.com last updated on 21/Feb/21 $$\mathrm{Assuming}\:\mathrm{that}\:\mathrm{the}\:\mathrm{world}\:\mathrm{population} \\ $$$$\mathrm{is}\:\mathrm{6billion}\:\mathrm{and}\:\mathrm{total}\:\mathrm{world}\:\mathrm{trip}\:\mathrm{is} \\ $$$$\mathrm{4}.\mathrm{8billion}. \\ $$$$\left(\mathrm{a}\right)\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{country}\:\mathrm{potential}\: \\ $$$$\mathrm{generation}\:\mathrm{index}\:\left(\mathrm{CPGI}\right)\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{country} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{interprete}\:\mathrm{your}\:\mathrm{results}\:\mathrm{in}\:\left(\mathrm{a}\right)\:\mathrm{above}. \\ $$$$ \\…