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Author: Tinku Tara

This-isn-t-a-question-Just-wanted-to-say-that-since-I-joined-here-I-have-learnt-so-much-You-guys-are-awesome-

Question Number 2292 by Filup last updated on 14/Nov/15 $$\mathrm{This}\:\mathrm{isn}'\mathrm{t}\:\mathrm{a}\:\mathrm{question}. \\ $$$$\mathrm{Just}\:\mathrm{wanted}\:\mathrm{to}\:\mathrm{say}\:\mathrm{that}\:\mathrm{since}\:\mathrm{I}\:\mathrm{joined} \\ $$$$\mathrm{here}\:\mathrm{I}\:\mathrm{have}\:\mathrm{learnt}\:\mathrm{so}\:\mathrm{much}.\:\mathrm{You}\:\mathrm{guys} \\ $$$$\mathrm{are}\:\mathrm{awesome}! \\ $$ Answered by Rasheed Soomro last updated on…

Question-67826

Question Number 67826 by peter frank last updated on 31/Aug/19 Commented by gunawan last updated on 01/Sep/19 $${x}=\mathrm{1}+{a}+{a}^{\mathrm{2}} +{a}^{\mathrm{3}} +.. \\ $$$${x}=\frac{\mathrm{1}}{\mathrm{1}−{a}}\:\Rightarrow\mathrm{1}−\:{a}=\frac{\mathrm{1}}{{x}}\Rightarrow\:{a}=\mathrm{1}−\frac{\mathrm{1}}{{x}}=\frac{{x}−\mathrm{1}}{{x}} \\ $$$${y}=\mathrm{1}+{b}+{b}^{\mathrm{2}} +{b}^{\mathrm{3}}…

1-sec-x-dx-

Question Number 133360 by liberty last updated on 21/Feb/21 $$\int\:\sqrt{\mathrm{1}+\mathrm{sec}\:\mathrm{x}}\:\mathrm{dx}\:? \\ $$ Commented by som(math1967) last updated on 21/Feb/21 $$\int\sqrt{\frac{\mathrm{1}+{cosx}}{{cosx}}}{dx} \\ $$$$\sqrt{\mathrm{2}}\int\frac{{cos}\frac{{x}}{\mathrm{2}}}{\:\sqrt{\mathrm{1}−\mathrm{2}{sin}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}}{dx} \\ $$$$=\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{2}}}\int\frac{{cos}\frac{{x}}{\mathrm{2}}}{\:\sqrt{\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right)^{\mathrm{2}}…

suppose-that-f-0-1-R-lets-f-C-2-and-suppose-that-0-1-such-that-f-f-1-1-proof-or-give-a-counter-example-that-0-1-f-

Question Number 2289 by 123456 last updated on 14/Nov/15 $$\mathrm{suppose}\:\mathrm{that}\:{f}:\left[\mathrm{0},\mathrm{1}\right]\rightarrow\mathbb{R},\:\mathrm{lets}\:{f}\in\mathrm{C}^{\mathrm{2}} \\ $$$$\mathrm{and}\:\mathrm{suppose}\:\mathrm{that}\:\exists\alpha\in\left[\mathrm{0},\mathrm{1}\right]\:\mathrm{such}\:\mathrm{that} \\ $$$${f}\left(\alpha\right)+{f}\left(\mathrm{1}−\alpha\right)=\mathrm{1} \\ $$$$\mathrm{proof}\:\mathrm{or}\:\mathrm{give}\:\mathrm{a}\:\mathrm{counter}\:\mathrm{example}\:\mathrm{that} \\ $$$$\exists\xi\in\left[\mathrm{0},\mathrm{1}\right],{f}\left(\xi\right)=\xi \\ $$ Commented by Rasheed Soomro last…

Can-you-evaluate-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-

Question Number 2286 by Filup last updated on 14/Nov/15 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{evaluate}: \\ $$$$\frac{\mathrm{1}}{\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}}}+\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}}}}+…+\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{…}} \\ $$ Commented by Yozzi last updated on 14/Nov/15 $${u}_{\mathrm{1}} =\frac{\mathrm{1}}{\mathrm{1}},\:{u}_{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}}}=\frac{\mathrm{1}}{\mathrm{1}+{u}_{\mathrm{1}} }…