Question Number 68370 by mhmd last updated on 09/Sep/19 Answered by MJS last updated on 09/Sep/19 $$\int\frac{{dt}}{\:\sqrt{\mathrm{e}^{{t}} −\mathrm{1}}}= \\ $$$$\:\:\:\:\:\left[{u}=\sqrt{\mathrm{e}^{{t}} −\mathrm{1}}\:\rightarrow\:{dt}=\frac{\mathrm{2}\sqrt{\mathrm{e}^{{t}} −\mathrm{1}}}{\mathrm{e}^{{t}} }{du}\right] \\ $$$$=\mathrm{2}\int\frac{{du}}{{u}^{\mathrm{2}}…
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Question Number 68368 by naka3546 last updated on 09/Sep/19 $$\frac{\mathrm{1}}{{x}+\mathrm{1}}\:=\:{y} \\ $$$$\underset{{x}+\mathrm{1}\:\rightarrow\:\infty} {\mathrm{lim}}\:\:{x}\:\mathrm{tan}\:\left(\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{2}}\right) \\ $$ Commented by kaivan.ahmadi last updated on 09/Sep/19 $${x}+\mathrm{1}\rightarrow\infty\Rightarrow{x}\rightarrow\infty \\ $$$${and}\:\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{2}}\rightarrow\mathrm{0}\Rightarrow{tan}\left(\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{2}}\right)\approx\frac{\mathrm{1}}{\mathrm{2}{x}+\mathrm{2}}…
Question Number 133903 by shaker last updated on 25/Feb/21 Commented by mr W last updated on 25/Feb/21 $${what}\:{do}\:{mean}\:{with}\:{argth}\left({x}\right)?\:{is}\:{it} \\ $$$${the}\:{same}\:{as}\:{arctanh}\left({x}\right)\:{in}\:{your} \\ $$$${country}? \\ $$ Commented…
Question Number 133897 by bemath last updated on 25/Feb/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{least}\:\mathrm{positive}\:\mathrm{integer} \\ $$$$\mathrm{that}\:\mathrm{leaves}\:\mathrm{a}\:\mathrm{remainder}\:\mathrm{3}\:\mathrm{when}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{7} \\ $$$$,\:\mathrm{4}\:\mathrm{when}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{9}\:,\:\mathrm{and}\:\mathrm{8}\:\mathrm{when} \\ $$$$\mathrm{divided}\:\mathrm{by}\:\mathrm{11}. \\ $$ Answered by john_santu last updated on 25/Feb/21…
Question Number 133893 by mathlove last updated on 25/Feb/21 $$\:\:{if}\:\:\:\:\:\:\:{f}\left({x}\right)=\frac{\mathrm{10}^{{x}} −\mathrm{10}^{−{x}} }{\mathrm{10}^{{x}} +\mathrm{10}^{−{x}} }\:\:\:\:\:\:{then}\:\:{f}^{−\mathrm{1}} \left({x}\right)=? \\ $$ Answered by rs4089 last updated on 25/Feb/21 $${y}=\frac{\mathrm{10}^{{x}}…
Question Number 133892 by EDWIN88 last updated on 25/Feb/21 $$\mathrm{If}\:{u}\:\mathrm{and}\:{v}\:\mathrm{are}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{equation}\: \\ $$$$\mathrm{6x}^{\mathrm{2}} −\mathrm{6px}\:+\mathrm{14p}−\mathrm{2}=\mathrm{0},\:\mathrm{where}\:{u}\:;\:{v}\:\mathrm{non}\:\mathrm{integer} \\ $$$$\mathrm{and}\:{u},\:{v}\:\geqslant\:\mathrm{1}\:\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mid{u}−{v}\mid\:\mathrm{is} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{14}\:\:\:\:\:\left(\mathrm{b}\right)\:\mathrm{15}\:\:\:\:\:\left(\mathrm{c}\right)\:\mathrm{16}\:\:\:\:\:\left(\mathrm{d}\right)\:\mathrm{17}\:\:\:\:\left(\mathrm{e}\right)\:\mathrm{18} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 2820 by Yozzis last updated on 27/Nov/15 $${We}\:{have}\:{the}\:{idea}\:{of}\:{Phythagorian}\:{triples} \\ $$$${as}\:{solutions}\:\left({x},{y},{z}\right)\:{to}\:{the}\:{equation} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={z}^{\mathrm{2}} \\ $$$${where}\:{x},{y},{z}\in\mathbb{Z}^{+} .\: \\ $$$${How}\:{frequently}\:{do}\:{solutions}\:\left({x},{y},{z},{t}\right)\:\:{to}\:{the}\:{equation} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}}…
Question Number 133889 by EDWIN88 last updated on 25/Feb/21 $$\:\mathrm{y}'−\mathrm{y}.\mathrm{tan}\:\mathrm{x}\:=\:\mathrm{cos}\:\mathrm{x}−\mathrm{2x}\:\mathrm{sin}\:\mathrm{x} \\ $$$$\mathrm{y}\left(\frac{\pi}{\mathrm{6}}\right)\:=\:\mathrm{0}\:\Rightarrow\mathrm{y}\left(\mathrm{x}\right)=? \\ $$ Answered by bemath last updated on 25/Feb/21 Answered by Ñï= last…
Question Number 68354 by TawaTawa last updated on 09/Sep/19 $$\underset{{x},\mathrm{y}\rightarrow\left(\mathrm{0},\mathrm{0}\right)} {\mathrm{lim}}\:\frac{\mathrm{x}^{\mathrm{4}} \:−\:\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{4}} }{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{x}^{\mathrm{4}} \mathrm{y}^{\mathrm{4}} \:+\:\mathrm{y}^{\mathrm{2}} } \\ $$ Commented by kaivan.ahmadi last…