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Question Number 133838 by I want to learn more last updated on 24/Feb/21 Commented by mr W last updated on 25/Feb/21 $${it}\:{is}\:{not}\:{clear}\:{what}\:{is}\:{meant}.\:{is}\:{the} \\ $$$${lineman}\:\mathrm{4}.\mathrm{6}\:{away}\:{from}\:{the}\:{goalposts} \\…
Question Number 2762 by Rasheed Soomro last updated on 26/Nov/15 $${Without}\:{using}\:\underset{−} {{induction}}\:{o}\underset{−} {{r}\:\:{arithmatic}\:{series}−{concept}\:\:\:} \\ $$$$\:{prove}\:{the}\:{following}: \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{n}=\frac{{n}\left({n}+\mathrm{1}\right)}{\mathrm{2}} \\ $$ Answered by prakash jain last updated…
Question Number 133829 by metamorfose last updated on 24/Feb/21 $${find}\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{x}^{{n}} {sin}\left({nx}\right)}{{n}}=…? \\ $$ Answered by Dwaipayan Shikari last updated on 24/Feb/21 $${log}\left(\mathrm{1}−{xe}^{{ix}} \right)={log}\left(\sqrt{\left(\mathrm{1}−{xcosx}\right)^{\mathrm{2}}…
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Question Number 2759 by RasheedAhmad last updated on 26/Nov/15 $${Without}\:{using}\:{arithmatic}\:{Series} \\ $$$${concept}\:{or}\:{formula}\:{prove}\:{the}\:{following}: \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{n}=\frac{{n}\left({n}+\mathrm{1}\right)}{\mathrm{2}} \\ $$ Answered by 123456 last updated on 26/Nov/15 $$\mathrm{induction} \\…
Question Number 133830 by metamorfose last updated on 24/Feb/21 $${find}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−{cos}\left({x}\right){cos}^{\mathrm{2}} \left(\mathrm{2}{x}\right){cos}^{\mathrm{3}} \left(\mathrm{3}{x}\right)…{cos}^{{n}} \left({nx}\right)}{{x}^{\mathrm{2}} }=…? \\ $$ Answered by EDWIN88 last updated on 24/Feb/21 $$\:\underset{{x}\rightarrow\mathrm{0}}…
Question Number 133825 by mnjuly1970 last updated on 24/Feb/21 Answered by mathDivergent last updated on 24/Feb/21 $$\frac{\mathrm{1}}{\mathrm{4}}\zeta\left(\mathrm{3}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 68289 by Rasheed.Sindhi last updated on 08/Sep/19 $$\mathrm{A}\:\mathrm{circle}\:\mathrm{is}\:\mathrm{divided}\:\mathrm{into}\:\mathrm{two}\:\mathrm{equal}\:\mathrm{parts} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{By} \\ $$$$\:\mathrm{An}\:\mathrm{arc}\:\mathrm{with}\:\mathrm{center}\:\mathrm{on}\:\mathrm{the}\:\mathrm{circle}. \\ $$$$\mathcal{D}{etermine} \\ $$$$\:\:\left({a}\right)\:{The}\:{length}\:{of}\:{the}\:{arc} \\ $$$$\:\:\left({b}\right){The}\:{ratio}\:{in}\:{which}\:{the}\:{arc} \\ $$$$\:\:\:\:\:\:\:\:{divides}\:{the}\:{diameter}\: \\ $$$$\:\:\:\:\:\:\:\:{meeting}\:{the}\:{center}\:{of}\:{the}\:{arc}. \\…
Question Number 133821 by bramlexs22 last updated on 24/Feb/21 $$\mathrm{There}\:\mathrm{are}\:\mathrm{5}\:\mathrm{positive}\:\mathrm{numbers}\: \\ $$$$\mathrm{and}\:\mathrm{6}\:\mathrm{negative}\:\mathrm{numbers}.\:\mathrm{Three}\: \\ $$$$\mathrm{numbers}\:\mathrm{are}\:\mathrm{chosen}\:\mathrm{at}\:\mathrm{random} \\ $$$$\mathrm{and}\:\mathrm{multiplied}\:.\:\mathrm{The}\:\mathrm{probability} \\ $$$$\mathrm{that}\:\mathrm{the}\:\mathrm{product}\:\mathrm{being}\:\mathrm{a}\:\mathrm{negative} \\ $$$$\mathrm{number}\:\mathrm{is}\: \\ $$$$\left(\mathrm{a}\right)\:\frac{\mathrm{17}}{\mathrm{33}}\:\:\:\left(\mathrm{b}\right)\:\frac{\mathrm{11}}{\mathrm{34}}\:\left(\mathrm{c}\right)\:\frac{\mathrm{16}}{\mathrm{33}}\:\:\:\left(\mathrm{d}\right)\:\frac{\mathrm{16}}{\mathrm{35}} \\ $$ Answered…