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Author: Tinku Tara

known-x-y-3-ask-min-x-2-1-y2-4-

Question Number 211529 by MrGaster last updated on 12/Sep/24 $$\mathrm{known}:\boldsymbol{{x}}+\boldsymbol{\mathrm{y}}=\mathrm{3},\mathrm{ask}: \\ $$$$\boldsymbol{\mathrm{min}}\left(\sqrt{\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{1}}+\sqrt{\boldsymbol{\mathrm{y}}\mathrm{2}−\mathrm{4}}\right)=? \\ $$ Answered by MrGaster last updated on 12/Sep/24 $$\mathrm{1}.\boldsymbol{{f}}\left(\boldsymbol{{x}}\right)=\sqrt{\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{1}}+\sqrt{\left(\mathrm{3}+\boldsymbol{{x}}\right)^{\mathrm{2}} −\mathrm{4}}…

Solve-for-x-x-x-4x-

Question Number 211524 by Tawa11 last updated on 12/Sep/24 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}:\:\:\:\mathrm{x}^{\mathrm{x}} \:\:=\:\:\mathrm{4x} \\ $$ Answered by Frix last updated on 12/Sep/24 $$\mathrm{We}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate}. \\ $$$${x}\approx.\mathrm{183193} \\ $$$${x}\approx\mathrm{2}.\mathrm{50781}…

n-0-1-3n-2-1-3n-1-a-a-2-

Question Number 211558 by mnjuly1970 last updated on 12/Sep/24 $$ \\ $$$$ \\ $$$$\:\:\:\:\:−−−−−−−−−−−− \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\Omega}=\:\underset{\boldsymbol{{n}}=\mathrm{0}} {\overset{\infty} {\sum}}\:\left(\frac{\mathrm{1}}{\mathrm{3}\boldsymbol{{n}}+\mathrm{2}}\:−\frac{\mathrm{1}}{\mathrm{3}\boldsymbol{{n}}+\mathrm{1}}\:\right)=\:\boldsymbol{{a}\pi} \\ $$$$\:\:\:\:\:\:\:\Rightarrow\:\:\boldsymbol{{a}}^{\mathrm{2}} =\:? \\ $$$$\:\:\:\:\:\:\:−−−−−−−−−−−− \\ $$…

for-example-I-say-Bob-is-born-in-1900s-there-the-symbol-of-s-means-century-what-kind-of-word-it-taken-from-

Question Number 211515 by Davidtim last updated on 11/Sep/24 $${for}\:{example}\:{I}\:{say}\:{Bob}\:{is}\:{born}\:{in} \\ $$$$\mathrm{1900}{s},\:{there}\:{the}\:{symbol}\:{of}\:\left({s}\right)\:{means} \\ $$$${century}.\:{what}\:{kind}\:{of}\:{word}\:{it}\:{taken} \\ $$$${from}? \\ $$ Commented by Frix last updated on 11/Sep/24…

If-1-x-2-1-y-2-a-x-y-then-prove-that-dy-dx-1-y-2-1-x-2-

Question Number 211508 by MATHEMATICSAM last updated on 11/Sep/24 $$\mathrm{If}\:\sqrt{\mathrm{1}\:−\:{x}^{\mathrm{2}} }\:+\:\sqrt{\mathrm{1}\:−\:{y}^{\mathrm{2}} }\:=\:{a}\left({x}\:−\:{y}\right)\:\mathrm{then} \\ $$$$\mathrm{prove}\:\mathrm{that}\:\frac{{dy}}{{dx}}\:=\:\sqrt{\frac{\mathrm{1}\:−\:{y}^{\mathrm{2}} }{\mathrm{1}\:−\:{x}^{\mathrm{2}} }\:}\:. \\ $$ Commented by Frix last updated on 11/Sep/24…

Question-211509

Question Number 211509 by RojaTaniya last updated on 11/Sep/24 Answered by A5T last updated on 11/Sep/24 $$\frac{\mathrm{6}{a}+{b}}{\mathrm{6}{c}+{d}}={k}=\frac{\mathrm{5}{a}+{b}}{\mathrm{5}{c}+{d}} \\ $$$$\Rightarrow\mathrm{6}{a}+{b}=\mathrm{6}{ck}+{dk}…\left({i}\right);\mathrm{5}{a}+{b}=\mathrm{5}{ck}+{dk}…\left({ii}\right) \\ $$$$\left({i}\right)−\left({ii}\right)\Rightarrow{a}={ck};\mathrm{6}\left({ii}\right)−\mathrm{5}\left({i}\right)\Rightarrow{b}={dk} \\ $$$$\mathrm{7}{a}+{b}=\mathrm{8}\left(\mathrm{7}{c}+{d}\right)\Rightarrow\mathrm{7}{ck}+{dk}=\mathrm{8}\left(\mathrm{7}{c}+{d}\right) \\ $$$$\Rightarrow{k}=\frac{\mathrm{8}\left(\mathrm{7}{c}+{d}\right)}{\mathrm{7}{c}+{d}}=\mathrm{8}…