Question Number 133027 by Engr_Jidda last updated on 18/Feb/21 $$\overset{\mathrm{2}} {\int}_{\mathrm{0}} {x}^{\mathrm{5}} \left(\mathrm{8}−{x}^{\mathrm{3}} \right)^{\frac{\mathrm{1}}{\mathrm{3}}} {dx} \\ $$ Answered by Olaf last updated on 18/Feb/21 $$\Omega\:=\:\int_{\mathrm{0}}…
Question Number 1952 by prakash jain last updated on 25/Oct/15 $$\mathrm{Inequality}\:\mathrm{relation}\:\mathrm{starting}\:\mathrm{a}\:\mathrm{new}\:\mathrm{thread} \\ $$$$\frac{{x}^{{p}} }{{p}\left({p}+\mathrm{1}\right)}−\frac{\mathrm{1}}{{p}}\geqslant\frac{{x}^{{q}} }{{q}\left({q}+\mathrm{1}\right)}−\frac{\mathrm{1}}{{q}} \\ $$$${p}=\mathrm{2},\:{q}=\mathrm{1},\:{x}=\mathrm{1} \\ $$$$\frac{{x}^{{p}} }{{p}\left({p}+\mathrm{1}\right)}=\frac{\mathrm{1}}{\mathrm{6}} \\ $$$$\frac{{x}^{{q}} }{{q}\left({q}+\mathrm{1}\right)}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\:\frac{{x}^{{p}}…
Question Number 133021 by liberty last updated on 18/Feb/21 $$\mathrm{A}\:\mathrm{multiple}\:−\mathrm{choice}\:\mathrm{quiz}\:\mathrm{has}\:\mathrm{200} \\ $$$$\mathrm{questions}\:\mathrm{each}\:\mathrm{with}\:\mathrm{4}\:\mathrm{possible}\: \\ $$$$\mathrm{answers}\:\mathrm{of}\:\mathrm{which}\:\mathrm{only}\:\mathrm{1}\:\mathrm{is}\:\mathrm{the}\:\mathrm{correct} \\ $$$$\mathrm{answer}\:.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\: \\ $$$$\mathrm{that}\:\mathrm{sheer}\:\mathrm{guesswork}\:\mathrm{yields}\: \\ $$$$\mathrm{from}\:\mathrm{25}\:\mathrm{to}\:\mathrm{30}\:\mathrm{correct}\:\mathrm{answer}\:\mathrm{for} \\ $$$$\mathrm{80}\:\mathrm{of}\:\mathrm{the}\:\mathrm{200}\:\mathrm{problems}\:\mathrm{about}\:\mathrm{which} \\ $$$$\mathrm{the}\:\mathrm{student}\:\mathrm{has}\:\mathrm{no}\:\mathrm{knowledge}?\: \\…
Question Number 67482 by Rasheed.Sindhi last updated on 27/Aug/19 $${I}\:{have}\:{tried}\:{to}\:{solve}\:{Q}#\mathrm{67299} \\ $$$${Please}\:{see}\:{and}\:{give}\:{critical}\:{remarks} \\ $$ Commented by mr W last updated on 28/Aug/19 $${your}\:{solution}\:{is}\:{correct}\:{sir}.\:{but}\:{i}'{m} \\ $$$${not}\:{sure}\:{if}\:{the}\:{solution}\:{is}\:{unique}.…
Question Number 133016 by metamorfose last updated on 18/Feb/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \left({tan}\left({x}\right)\right)^{\frac{\mathrm{1}}{{n}}} {dx}\:… \\ $$ Answered by Ar Brandon last updated on 18/Feb/21 $$\mathcal{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 67481 by Mohamed Amine Bouguezzoul last updated on 27/Aug/19 $${p}\:{is}\:{a}\:{prime}\:{number}\:{such}\:{that}\:\left(\mathrm{1}+{p}\right)^{{p}} \equiv\mathrm{2}\left[\mathrm{7}\right] \\ $$$${find}\:{all}\:{k}\:{such}\:{that}\:{p}\equiv{k}\left[\mathrm{42}\right] \\ $$ Commented by Rasheed.Sindhi last updated on 30/Aug/19 $$\boldsymbol{{Some}}\:{values}\:{of}\:{k}…
Question Number 1942 by Yozzi last updated on 25/Oct/15 $${Let}\:{N}\:{be}\:{a}\:{positive}\:{integer}\:{with}\:{prime} \\ $$$${factorisation}\: \\ $$$$\:\:{N}={p}_{\mathrm{1}} ^{{m}_{\mathrm{1}} } {p}_{\mathrm{2}} ^{{m}_{\mathrm{2}} } {p}_{\mathrm{3}} ^{{m}_{\mathrm{3}} } ×…×{p}_{{n}−\mathrm{1}} ^{{m}_{{n}−\mathrm{1}} }…
Question Number 133009 by shaker last updated on 18/Feb/21 Commented by liberty last updated on 18/Feb/21 $$?\:=\:\mathrm{1} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 1937 by Rasheed Soomro last updated on 25/Oct/15 $$\bullet{Is}\:\:\:'\Leftrightarrow'\:\:{necessary}\:{and}\:{suficient}\:{for}\:{two} \\ $$$${inequalities}\:{to}\:{be}\:{equivalent}? \\ $$$$\bullet{If}\:\:\boldsymbol{\mathrm{a}}>\boldsymbol{\mathrm{b}}\:: \\ $$$${Are}\:\:\boldsymbol{\mathrm{A}}>\boldsymbol{\mathrm{B}}\:{and}\:\boldsymbol{\mathrm{A}}+\boldsymbol{\mathrm{a}}\:>\:\boldsymbol{\mathrm{B}}+\boldsymbol{\mathrm{b}}\:{equivalent}? \\ $$ Answered by 123456 last updated on…
Question Number 133010 by rs4089 last updated on 18/Feb/21 $${for}\:{the}\:{extremum}\:{values}\:{of}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:{subject}\:{to}\:{the}\:{constraints} \\ $$$${ax}^{\mathrm{2}} +{by}^{\mathrm{2}} +{cz}^{\mathrm{2}} =\mathrm{1}\:{and}\:{lx}+{my}+{nz}=\mathrm{0}\:. \\ $$$${show}\:{that}\:{the}\:{stationary}\:{points}\:{setisfy}\:{the}\:{realation} \\ $$$$\frac{{l}^{\mathrm{2}} }{\mathrm{1}+{a}\lambda_{\mathrm{1}} }+\frac{{m}^{\mathrm{2}} }{\mathrm{1}+{b}\lambda_{\mathrm{1}}…