Question Number 137708 by mohammad17 last updated on 05/Apr/21 Commented by mohammad17 last updated on 05/Apr/21 $${prove} \\ $$ Answered by mr W last updated…
Question Number 72175 by mr W last updated on 26/Oct/19 $$\left(\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{3}} =\boldsymbol{{x}}^{\mathrm{2}} \boldsymbol{{y}}^{\mathrm{3}} \\ $$$$ \\ $$$${how}\:{large}\:\left({area}\right)\:{is}\:{your}\:{heart}\:\heartsuit\:? \\ $$ Commented by mr W…
Question Number 6638 by Tawakalitu. last updated on 07/Jul/16 $${The}\:{radius}\:{of}\:{curvature}\:{of}\:{a}\:{thin}\:{equiconvex}\:{lens}\:{is}\:\mathrm{40}.\mathrm{0}\:{cm} \\ $$$${the}\:{lens}\:{is}\:{made}\:{of}\:{glass}\:{of}\:{refractive}\:{index}\:\mathrm{1}.\mathrm{660}.\:\:{find}\:{the}\: \\ $$$${position}\:{of}\:{the}\:{image}\:{of}\:{an}\:{object}\:{placed}\:{on}\:{the}\:{axis}\:{of}\:{the}\: \\ $$$${axis}\:{of}\:{the}\:{lens}\:{at}\:{a}\:{distance}\:{of}\:\mathrm{50}.\mathrm{0}\:{mm}\:\:{from}\:{the}\:{pole}. \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 6635 by Rasheed Soomro last updated on 07/Jul/16 Commented by Rasheed Soomro last updated on 09/Jul/16 $${In}\:{other}\:{words}: \\ $$$${The}\:{median}\:{through}\:\mathrm{A}\:{in}\:\bigtriangleup\mathrm{ABC}\:{is}\:{equidistant} \\ $$$${from}\:\mathrm{B}\:\:{and}\:\:\mathrm{C}. \\ $$$${Or}…
Question Number 137707 by mohammad17 last updated on 05/Apr/21 Answered by Dwaipayan Shikari last updated on 05/Apr/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \sqrt{{tan}\theta}\:{d}\theta \\ $$$$=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\frac{\mathrm{1}}{\mathrm{2}}} \theta\:\:{cos}^{−\frac{\mathrm{1}}{\mathrm{2}}}…
Question Number 137706 by otchereabdullai@gmail.com last updated on 05/Apr/21 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{linear}\:\mathrm{momentum}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{5kg}\:\mathrm{object}\:\mathrm{moing}\:\mathrm{at}\:\mathrm{4ms}^{−\mathrm{1}} \:\mathrm{due}\:\mathrm{east}. \\ $$ Answered by Dwaipayan Shikari last updated on 05/Apr/21 $${linear}\:{momentum}\:={m}\overset{\rightarrow} {{v}}=\mathrm{5}×\mathrm{4}\:{kgms}^{−\mathrm{1}}…
Question Number 137700 by peter frank last updated on 05/Apr/21 Commented by mr W last updated on 05/Apr/21 $${it}'{s}\:{not}\:{true}! \\ $$$${example}: \\ $$$${b}={c}=−\mathrm{1},\:{a}=\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}} \\ $$$$\frac{\mathrm{1}}{{a}^{\mathrm{3}}…
Question Number 6630 by Tawakalitu. last updated on 06/Jul/16 $${A}\:{small}\:{source}\:{of}\:{sound}\:{emit}\:{energy}\:{uniformly}\:{in}\:{all}\: \\ $$$${direction}\:{for}\:{a}\:{particular}\:{frequency},\:{the}\:{intensity}\:{of}\:{sound}\: \\ $$$${at}\:{a}\:{distane}\:\mathrm{2}.\mathrm{0}{m}\:{from}\:{the}\:{source}\:{is}\:\mathrm{1}.\mathrm{0}\:×\:\mathrm{10}^{−\mathrm{5}} \:\:{and}\: \\ $$$${corresponds}\:{to}\:{amplitude}\:{of}\:{oscillation}\:{on}\:{the}\:{air}\:{molecules} \\ $$$${of}\:\:\mathrm{7}{u}\:.\:{assuming}\:{sound}\:{is}\:{propagated}\:{with}\:{any}\:{loss}\:{of}\:{energy} \\ $$$${calculate}: \\ $$$$\left(\mathrm{1}\right)\:{Intensity}\:{of}\:{sound} \\ $$$$\left(\mathrm{2}\right)\:{the}\:{amplitude}\:{of}\:{oscillation}\:{of}\:{the}\:{air}\:{molecules}…
Question Number 137702 by SOMEDAVONG last updated on 05/Apr/21 $$\mathrm{A}=\sqrt{\mathrm{5}+\sqrt{\mathrm{13}+\sqrt{\mathrm{5}+\sqrt{\mathrm{13}+……..}}}} \\ $$ Answered by MJS_new last updated on 05/Apr/21 $${A}>\sqrt{\mathrm{5}} \\ $$$$\left({A}^{\mathrm{2}} −\mathrm{5}\right)^{\mathrm{2}} −\mathrm{13}={A} \\…
Question Number 137697 by Mathspace last updated on 05/Apr/21 $${let}\:{f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{1} \\ $$$${find}\:\:\int\:\frac{{f}\left({x}\right)}{{f}^{−\mathrm{1}} \left({x}\right)}{dx}\:{and}\:\int\:\frac{{f}^{−\mathrm{1}} \left({x}\right)}{{f}\left({x}\right)}{dx} \\ $$ Commented by TheSupreme last updated on 07/Apr/21 $${f}^{−\mathrm{1}}…