Question Number 132878 by aurpeyz last updated on 17/Feb/21 $${is}\:{the}\:{surface}\:{of}\:{a}\:{mirror}\:{refractive} \\ $$$${or}\:{reflective}? \\ $$ Commented by Dwaipayan Shikari last updated on 17/Feb/21 $${Generally}\:{reflective}\:..\:{but}\:{sometimes}\:{refractive}.. \\ $$…
Question Number 1804 by 123456 last updated on 03/Oct/15 $$\left(\mathrm{1}−{u}\right)\frac{\partial{u}}{\partial{t}}={u}\frac{\partial{v}}{\partial{t}} \\ $$$$\left(\mathrm{1}−{v}\right)\frac{\partial{v}}{\partial{t}}={v}\frac{\partial{u}}{\partial{t}} \\ $$$$\frac{\partial}{\partial{t}}\left({uv}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 132873 by aurpeyz last updated on 17/Feb/21 $${is}\:{linear}\:{magnification}\:{positive}\:{or}\: \\ $$$${negative}\:{for}\:{a}\:{convex}\:{mirror}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 132872 by aurpeyz last updated on 17/Feb/21 $${linear}\:{magnification}\:{for}\:{convex} \\ $$$${mirror} \\ $$$$=\frac{{image}\:{height}}{{object}\:{height}}=\frac{−{image}\:{distance}}{{object}\:{distance}} \\ $$$$ \\ $$$${is}\:{this}\:{formula}\:{correct}?\:{what}\:{is}\:{the} \\ $$$${meaning}\:{of}\:{the}\:{negative}\:{sign}? \\ $$ Terms of Service…
Question Number 67336 by TawaTawa last updated on 25/Aug/19 $$\mathrm{If}\:\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{e}^{−\mathrm{t}} \:\:\frac{\mathrm{dy}}{\mathrm{dt}}\:\:,\:\:\:\:\:\:\mathrm{find}\:\:\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} } \\ $$ Commented by mr W last updated on 26/Aug/19 $${where}\:{did}\:{you}\:{get}\:{this}\:{question}? \\…
Question Number 132874 by aurpeyz last updated on 17/Feb/21 $${n}=\frac{\mathrm{360}}{\theta}−\mathrm{1}\:{or}\:{n}=\frac{\mathrm{360}}{\theta}\:{for}\:{plane} \\ $$$${mirrors}\:{inclined}\:{an}\:{angle}\:\theta\:{to} \\ $$$${eachother}.\:{which}\:{is}\:{correct}? \\ $$ Commented by Dwaipayan Shikari last updated on 17/Feb/21 $$\mu=\frac{\mathrm{360}°}{\theta°}−\mathrm{1}\:\:{or}\:\:\mu=\frac{\mathrm{2}\pi}{\theta}−\mathrm{1}\:\:\:\left({Radian}\right)…
Question Number 67337 by ajfour last updated on 25/Aug/19 $${m}\left({p}+\mathrm{1}\right)={a} \\ $$$$\frac{{q}\left({p}+\mathrm{1}\right)}{{r}+\mathrm{1}}={b}\:\:\&\:\:\frac{{p}\left({p}+\mathrm{1}\right)}{{q}+\mathrm{1}}={c} \\ $$$${and}\:\:\frac{{r}\left({p}+\mathrm{1}\right)}{{m}+\mathrm{1}}={d} \\ $$$${find}\:{either}\:{of}\:{p},{q},{r},{m}\:{in}\:{terms}\:{of} \\ $$$${a},{b},{c},{d}. \\ $$ Answered by mr W last…
Question Number 132869 by syamilkamil1 last updated on 17/Feb/21 Commented by syamilkamil1 last updated on 17/Feb/21 $${what}\:{is}\:{the}\:{radius}\:{of}\:{the}\:{circle}\:,\:{if}\:{length}\:{the}\:{square}\:\mathrm{2}\:{centimetres}? \\ $$ Commented by bramlexs22 last updated on…
Question Number 1799 by navajyoti.tamuli.tamuli@gmail. last updated on 30/Sep/15 $$\int\frac{{dx}}{{x}^{\mathrm{2}} .{e}^{−{x}^{\mathrm{3}} /\mathrm{3}} }=? \\ $$ Commented by 123456 last updated on 30/Sep/15 $$\mathrm{not}\:\mathrm{done}\:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{elementar}\:\mathrm{function} \\ $$…
Question Number 1797 by 112358 last updated on 29/Sep/15 $${Let}\:{f}\:{be}\:{a}\:{function}\:{defined}\:{on} \\ $$$${the}\:{domain}\:{D}_{{f}} =\mathbb{C}\:{and}\:{f}\left({z}\right)={cosz} \\ $$$${for}\:{z}\in{D}_{{f}} \:.\:{Is}\:{f}\left({z}\right)\:{a}\:{member} \\ $$$${of}\:\mathbb{C}?\:{Compute}\:{for}\:{example} \\ $$$${f}\left(\mathrm{2}+\mathrm{6}{i}\right). \\ $$$$ \\ $$ Answered…