Question Number 1771 by hareem ali last updated on 19/Sep/15 $$\mathrm{2}{x}−{y}+\mathrm{2}{z}=\mathrm{4} \\ $$$${x}+\mathrm{10}{y}−\mathrm{3}{z}=\mathrm{10} \\ $$ Answered by 123456 last updated on 19/Sep/15 $$\begin{bmatrix}{\mathrm{2}}&{−\mathrm{1}}&{\mathrm{2}}\\{\mathrm{1}}&{\mathrm{10}}&{−\mathrm{3}}\\{\mathrm{0}}&{\mathrm{0}}&{\mathrm{0}}\end{bmatrix}\begin{bmatrix}{{x}}\\{{y}}\\{{z}}\end{bmatrix}=\begin{bmatrix}{\mathrm{4}}\\{\mathrm{10}}\\{\mathrm{0}}\end{bmatrix} \\ $$$$\begin{bmatrix}{\mathrm{2}}&{−\mathrm{1}}&{\mathrm{2}}&{\mathrm{4}}\\{\mathrm{1}}&{\mathrm{10}}&{−\mathrm{3}}&{\mathrm{10}}\end{bmatrix}…
Question Number 67307 by aliesam last updated on 25/Aug/19 Commented by mathmax by abdo last updated on 25/Aug/19 $${S}\:=\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{{cos}\left({n}\theta\right)}{\mathrm{2}^{{n}} }\:\Rightarrow\:{S}\:={Re}\left(\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{{e}^{{in}\theta} }{\mathrm{2}^{{n}}…
Question Number 1767 by Rasheed Ahmad last updated on 18/Sep/15 $${Determine} \\ $$$$\:\left({i}\right)\:\underset{{a}\rightarrow\infty} {{lim}}\:\left(\frac{\mathrm{1}}{{a}}\right)^{{a}} \:\:\:\left({ii}\right)\:\:\underset{{a}\rightarrow\mathrm{0}} {{lim}}\:\left(\frac{\mathrm{1}}{{a}}\right)^{{a}} \: \\ $$ Answered by 123456 last updated on…
Question Number 1766 by Rasheed Ahmad last updated on 18/Sep/15 $${Determine}\: \\ $$$$\:\:\left({i}\right)\:\:\underset{{a}\rightarrow\infty} {{lim}}\:{a}^{\frac{\mathrm{1}}{{a}}} \:\:\:\:\:\:\:\:\:\:\:\left({ii}\right)\:\underset{{a}\rightarrow\mathrm{0}} {{lim}}\:{a}^{\frac{\mathrm{1}}{{a}}} \\ $$ Answered by 123456 last updated on 19/Sep/15…
Question Number 132838 by Ahmed1hamouda last updated on 16/Feb/21 Answered by TheSupreme last updated on 17/Feb/21 $$\int\int\left({x}+{y}\right)^{\mathrm{2}} {sin}^{\mathrm{2}} \left({x}−{y}\right){dA} \\ $$$${R}=\left\{\left({x},{y}\right)\mid−\mathrm{1}<{x}−{y}<\mathrm{1},\:\mathrm{1}<{x}+{y}<\mathrm{3}\right\} \\ $$$${set}\:{u}={x}+{y},\:{v}={x}−{y} \\ $$$${R}'=\left\{\left({u},{v}\right)\mid−\mathrm{1}<{v}<\mathrm{1},\mathrm{1}<{u}<\mathrm{3}\right\}…
Question Number 67298 by Rio Michael last updated on 25/Aug/19 $${Find}\:\:{the}\:{third}\:{degree}\:{polynomial}\:{which}\:{vanishes}\:{when} \\ $$$${x}\:=−\mathrm{1}\:{and}\:{x}\:=\:\mathrm{2},\:{which}\:{has}\:{a}\:{value}\:\mathrm{8}\:{when}\:{x}\:=\mathrm{0}\:{and}\:{leaves}\:{a}\:{remainder}\:\frac{\mathrm{16}}{\mathrm{3}}\:{when} \\ $$$${divided}\:{by}\:\:\mathrm{3}{x}\:+\:\mathrm{2}. \\ $$ Commented by Prithwish sen last updated on 25/Aug/19…
Question Number 1763 by Gerlândio Almeida last updated on 18/Sep/15 $$ \\ $$ Commented by 123456 last updated on 18/Sep/15 $${p}_{\mathrm{0}} \left({n}\right)={xn} \\ $$$${r}\left({n}\right)=\alpha{xn} \\…
Question Number 132832 by mathocean1 last updated on 16/Feb/21 $${f}\left({x}\right)={xtan}^{\mathrm{2}} {x} \\ $$$${find}\:{one}\:{primitive}\:{of}\:{f}\left({x}\right). \\ $$ Answered by Olaf last updated on 17/Feb/21 $$\mathrm{F}\left({x}\right)\:=\:\int{f}\left({x}\right){dx} \\ $$$$\mathrm{F}\left({x}\right)\:=\:\int{x}\mathrm{tan}^{\mathrm{2}}…
Question Number 67299 by Rio Michael last updated on 25/Aug/19 $${G}\left({x}\right)=\:\left({x}+\mathrm{1}\right)\left({x}+\mathrm{3}\right){Q}\left({x}\right)\:+\:{px}\:+{q} \\ $$$$\left.{a}\right)\:{Given}\:{that}\:{G}\left({x}\right)\:{leaves}\:{a}\:{remainder}\:{of}\:\mathrm{8}\:{and}\:−\mathrm{24}\:{when}\:{divided}\:{by}\:\left({x}+\mathrm{1}\right)\:{and}\: \\ $$$$\left({x}+\mathrm{3}\right)\:{respectively},{find}\:{the}\:{remainder}\:{when}\:{G}\left({x}\right)\:{is}\:{divided}\:{by}\:\left({x}+\mathrm{1}\right)\left({x}+\mathrm{3}\right). \\ $$$$\left.{b}\right)\:\:{Given}\:{that}\:{x}+\mathrm{2}\:{is}\:{a}\:{factor}\:{of}\:{G}\left({x}\right)\:{and}\:{that}\:{the}\:{graph}\:{of}\:{G}\left({x}\right)\:{passes}\:{through} \\ $$$${the}\:{point}\:{with}\:{coordinates}\:\left(\mathrm{0},\mathrm{6}\right)\:{find}\:{G}\left({x}\right) \\ $$ Commented by Rasheed.Sindhi last…
Question Number 132835 by mohammad17 last updated on 16/Feb/21 $${prove}\:\mathrm{0}^{\mathrm{0}} =\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com