Question Number 71986 by rajesh4661kumar@gmail.com last updated on 23/Oct/19 Answered by mind is power last updated on 23/Oct/19 $$\mathrm{not}\:\mathrm{unique}\:\mathrm{angle} \\ $$$$\mathrm{XY}=\left\{\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\in\mathbb{R}^{\mathrm{3}} :\mathrm{z}=\mathrm{0}\right\} \\ $$$$\mathrm{angle}\:\mathrm{between}\:\mathrm{vecror}\:\mathrm{and}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{not}\:\mathrm{defind}\: \\…
Question Number 137523 by SOMEDAVONG last updated on 03/Apr/21 $$\mathrm{L}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{x}!−\mathrm{1}}{\mathrm{x}} \\ $$ Answered by Dwaipayan Shikari last updated on 03/Apr/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\Gamma\left({x}+\mathrm{1}\right)−\mathrm{1}}{{x}}=\frac{\mathrm{1}−\gamma{x}−\mathrm{1}}{{x}}=−\gamma \\ $$$$\Gamma\left({x}+\mathrm{1}\right)\sim\mathrm{1}−\gamma{x}…
Question Number 71984 by Henri Boucatchou last updated on 23/Oct/19 $$\:{x},\:{y}\:\in\:{I}\:\subset\:\mathbb{R}\:\:{prove}\:\:{that}\:\:\mid{cosx}\:−\:{siny}\mid\:\leqslant\:\mid{x}\:−\:{y}\mid \\ $$ Answered by mind is power last updated on 23/Oct/19 $$\mathrm{x}=\mathrm{y}=\mathrm{0}\:\mathrm{mistack} \\ $$$$\Rightarrow\mathrm{1}\leqslant\mathrm{0}…
Question Number 6449 by Temp last updated on 27/Jun/16 $${x}=\mathrm{0}.\mathrm{112123123412345123456}… \\ $$$$\mathrm{decimal}\:\mathrm{pattern}:\:\mathrm{1},\:\mathrm{12},\:\mathrm{123},\:… \\ $$$$\mathrm{Can}\:\mathrm{this}\:\mathrm{be}\:\mathrm{represented}\:\mathrm{as}\:\mathrm{a}\:\mathrm{fraction}? \\ $$$$\mathrm{or}\:\mathrm{is}\:\mathrm{this}\:\mathrm{number}\:\mathrm{trancendental}? \\ $$ Commented by prakash jain last updated on…
Question Number 71983 by device4438043516@gmail.com last updated on 23/May/20 $$ \\ $$ Answered by Henri Boucatchou last updated on 23/Oct/19 $$\boldsymbol{{d}}\left(\boldsymbol{{e}}^{\boldsymbol{{vlnu}}} \right)\:=\:\boldsymbol{{u}}^{\boldsymbol{{v}}} \:\boldsymbol{{d}}\left(\boldsymbol{{vlnu}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\boldsymbol{{u}}^{\boldsymbol{{v}}}…
Question Number 137518 by Lordose last updated on 03/Apr/21 $$\Omega\:=\:\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{u}^{\mathrm{2}} +\mathrm{2}}{\mathrm{u}^{\mathrm{4}} +\mathrm{2u}^{\mathrm{2}} +\mathrm{2}}\mathrm{du} \\ $$ Answered by mathmax by abdo last updated on…
Question Number 6444 by sanusihammed last updated on 27/Jun/16 $${I}\:=\:\int\frac{{dx}}{{sinx}\:+\:{sin}\mathrm{2}{x}} \\ $$ Commented by Temp last updated on 27/Jun/16 $$\mathrm{Try}\:\mathrm{www}.\mathrm{WolframAlpha}.\mathrm{com} \\ $$$$\mathrm{search}: \\ $$$$“{int}\:\mathrm{1}/\left({sin}\left({x}\right)+{sin}\left(\mathrm{2}{x}\right)\right)\:{dx}'' \\…
Question Number 6443 by sanusihammed last updated on 27/Jun/16 $${Calculate}\:{the}\:{workdone}\:{by}\:{a}\:{force}\:{of}\:\:\mathrm{30}{kg}\:{whose}\:{line}\:{of}\:{action} \\ $$$${has}\:{direction}\:{cosines}\:\:\frac{\mathrm{2}}{\mathrm{5}},\:\frac{\mathrm{1}}{\mathrm{5}},\:{and}\:\:\frac{\mathrm{3}}{\mathrm{5}}\:{on}\:{a}\:{displacement}\:{from}\:\:\: \\ $$$${the}\:{point}\:\left(\mathrm{1},\mathrm{2},\mathrm{5}\right)\:{to}\:{the}\:{point}\:\left(\mathrm{7},\mathrm{5},\mathrm{2}\right) \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 6441 by Temp last updated on 27/Jun/16 $$\mathrm{After}\:\mathrm{looking}\:\mathrm{at}\:\mathrm{a}\:\mathrm{previous}\:\mathrm{question} \\ $$$$\mathrm{I}\:\mathrm{was}\:\mathrm{wondering}\:\mathrm{if}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{is}\:\mathrm{correct}: \\ $$$${I}\left({n}\right)=\int_{\mathrm{0}} ^{\:{n}} \left(−\mathrm{1}\right)^{{x}} {dx},\:\:{n}\in\mathbb{R} \\ $$$${I}\left({n}\right)=\int_{\mathrm{0}} ^{\:{n}} {e}^{{i}\pi{x}} {dx}\:\:\:\left(\mathrm{1}\right) \\…
Question Number 137509 by liberty last updated on 03/Apr/21 $$\int\:\frac{\mathrm{sin}\:\left(\sqrt{{x}}\:\right)+\mathrm{cos}\:\left(\sqrt{{x}}\:\right)}{\:\sqrt{{x}}\:\mathrm{sin}\:\left(\mathrm{2}\sqrt{{x}}\:\right)}\:{dx}\: \\ $$ Commented by liberty last updated on 04/Apr/21 Answered by Ñï= last updated on…