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Author: Tinku Tara

Solve-e-2z-3-i-z-x-iy-

Question Number 132834 by mohammad17 last updated on 16/Feb/21 $${Solve}\:{e}^{\mathrm{2}{z}} =\sqrt{\mathrm{3}}−{i}\:\:\:,{z}={x}+{iy} \\ $$ Answered by mathmax by abdo last updated on 20/Feb/21 $$\mid\sqrt{\mathrm{3}}−\mathrm{i}\mid=\mathrm{2}\:\Rightarrow\sqrt{\mathrm{3}}−\mathrm{i}=\mathrm{2}\left(\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{i}\right)\:=\mathrm{2e}^{−\frac{\mathrm{i}\pi}{\mathrm{6}}} =\mathrm{2e}^{\left(−\frac{\mathrm{i}\pi}{\mathrm{6}}+\mathrm{2ik}\pi\right)} \\…