Question Number 67760 by ugwu Kingsley last updated on 31/Aug/19 $${y}'={y}^{\mathrm{2}} +\mathrm{2}\:;\:{y}\left(\mathrm{0}\right)=\mathrm{2} \\ $$$$ \\ $$$${solve}\:{by}\:{picards}\:{iteration}\:{method} \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 67761 by ugwu Kingsley last updated on 31/Aug/19 $${solve}\:{by}\:{laplace}\:{transform}\:{method} \\ $$$$ \\ $$$$\overset{\bullet\bullet\:} {{x}}\:+{w}_{\mathrm{0}} ^{\mathrm{2}} {x}={coswt}\:\:\:{x}\left(\mathrm{0}\right)={x}_{\mathrm{0}} \:\overset{\bullet} {{x}}\left(\mathrm{0}\right)={v}_{\mathrm{0}} \:\:\:\:\:{w}^{\mathrm{2}} \neq\:{w}_{\mathrm{0}} ^{\mathrm{2}} \\ $$…
Question Number 133293 by liberty last updated on 21/Feb/21 Commented by mr W last updated on 21/Feb/21 $${what}\:{is}\:{the}\:\mathrm{3}{rd}\:{category}? \\ $$$${office}\:{related}\:{books}, \\ $$$${literature}\:{book}, \\ $$$${and}\:{what}\:{else}? \\…
Question Number 67759 by ugwu Kingsley last updated on 31/Aug/19 $${using}\:{variation}\:{of}\:{parameters}\:{method} \\ $$$$ \\ $$$$\left({x}+\mathrm{2}\right)^{\mathrm{2}} {y}''−\left({x}+\mathrm{2}\right){y}'=\mathrm{2}{x}+\mathrm{4} \\ $$$$ \\ $$$$ \\ $$$${x}^{\mathrm{2}} {y}''+\mathrm{2}{xy}'−\mathrm{2}{y}={x}^{\mathrm{2}} {lnx}+\mathrm{3}{x} \\…
it-is-necessary-for-diffrentiable-function-itmust-becontinuty-why-and-how-please-explain-by-example-
Question Number 2219 by tabrez8590@gmail last updated on 09/Nov/15 $${it}\:{is}\:{necessary}\:{for}\:{diffrentiable}\:\:{function}\:{itmust}\:{becontinuty}\:{why}?{and}\:{how}\:{please}\:{explain}\:{by}\:{example} \\ $$$$ \\ $$ Answered by Filup last updated on 09/Nov/15 $$\mathrm{if}\:\begin{cases}{{y}={x}\:\:\:\mathrm{if}\:{x}>\mathrm{0}}\\{{y}=−{x}\:\:\:\mathrm{if}\:{x}<\mathrm{0}}\end{cases} \\ $$$$ \\…
Question Number 133291 by liberty last updated on 21/Feb/21 $$\:\int\:\frac{\left(\mathrm{x}^{\mathrm{4}} \right)^{\mathrm{2}} }{\left(\mathrm{1}+\mathrm{x}^{\mathrm{6}} \right)^{\mathrm{2}} }\:\mathrm{dx}\:=? \\ $$ Answered by EDWIN88 last updated on 21/Feb/21 $$\mathrm{integration}\:\mathrm{by}\:\mathrm{parts} \\…
Question Number 67749 by TawaTawa last updated on 31/Aug/19 Answered by JDamian last updated on 31/Aug/19 $${Assuming}\:{A},\:{B}\:{and}\:{C}\:{points}\:{are}\:{the}\:{centers} \\ $$$${of}\:{their}\:{circles}: \\ $$$$ \\ $$$${AC}={R}_{{A}} −{R}_{{C}} =\mathrm{11}−\mathrm{5}=\mathrm{6}…
Question Number 2212 by Yozzi last updated on 09/Nov/15 $$\int\frac{{dt}}{\left(\mathrm{1}−{kt}\right)\sqrt{\mathrm{1}−{t}^{\mathrm{2}} }}=?\:\:\mathrm{0}<{k}<\mathrm{1} \\ $$ Commented by 123456 last updated on 09/Nov/15 $$\frac{\mathrm{ln}\:\left(\sqrt{{k}^{\mathrm{2}} −\mathrm{1}}\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }+{k}−{x}\right)−\mathrm{ln}\:\left(\mathrm{1}−{kx}\right)}{\:\sqrt{{k}^{\mathrm{2}} −\mathrm{1}}} \\…
Question Number 133281 by aurpeyz last updated on 20/Feb/21 $${an}\:{object}\:{placed}\:\mathrm{20}{cm}\:{from}\:{a}\:{con}− \\ $$$${verving}\:{lens}\:{forms}\:{a}\:{mavnified}\:{clear} \\ $$$${image}\:{on}\:{the}\:{screen}.\:{when}\:{the}\:{lens} \\ $$$${is}\:{moved}\:\mathrm{20}{cm}\:{towards}\:{the}\:{screen} \\ $$$${a}\:{smaller}\:{clear}\:{image}\:{is}\:{formed}\:{on} \\ $$$${the}\:{screen}.\:{calculate}\:{the}\:{focal}\:{length} \\ $$$${of}\:{the}\:{lens} \\ $$ Terms…
Question Number 2210 by Yozzi last updated on 08/Nov/15 $${Evaluate}\: \\ $$$$\:\:\int_{\mathrm{0}} ^{\infty} \frac{{dx}}{{x}^{\mathrm{4}} +\mathrm{2}{x}^{\mathrm{2}} {cos}\alpha+\mathrm{1}}\:\:\left(\mathrm{0}<\alpha<\pi\right). \\ $$ Commented by 123456 last updated on 09/Nov/15…