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Author: Tinku Tara

calculateA-n-n-1-1-n-n-2-cos-n-andB-n-n-1-1-n-n-2-cos-npi-3-

Question Number 132496 by mathmax by abdo last updated on 14/Feb/21 $$\mathrm{calculateA}_{\mathrm{n}} =\:\sum_{\mathrm{n}=\mathrm{1}} ^{\infty} \:\frac{\left(−\mathrm{1}\right)^{\mathrm{n}} }{\mathrm{n}^{\mathrm{2}} }\mathrm{cos}\left(\mathrm{n}\right)\:\mathrm{andB}_{\mathrm{n}} =\:\sum_{\mathrm{n}=\mathrm{1}} ^{\infty} \:\frac{\left(−\mathrm{1}\right)^{\mathrm{n}} }{\mathrm{n}^{\mathrm{2}} }\mathrm{cos}\left(\frac{\mathrm{n}\pi}{\mathrm{3}}\right) \\ $$ Answered…

why-we-can-not-compare-any-tow-complex-number-how-a-cmplex-number-is-uses-a-complex-number-practically-please-giveanexample-

Question Number 1426 by tabrez8590@gmail last updated on 31/Jul/15 $${why}\:{we}\:{can}\:{not}\:{compare}\:{any}\:{tow}\:{complex}\:{number}\:\: \\ $$$${how}\:{a}\:{cmplex}\:{number}\:{is}\:{uses}\:{a}\:{complex}\:{number}\:{practically}\:{please}\:{giveanexample} \\ $$ Commented by Rasheed Ahmad last updated on 03/Aug/15 $${Things}\:{with}\:{respect}\:{to}\:{single}\: \\ $$$${characteristic}\:{are}\:{easy}\:{to}\:{compare}.…

Question-132494

Question Number 132494 by mnjuly1970 last updated on 14/Feb/21 Commented by MJS_new last updated on 14/Feb/21 $$\mathrm{sharing}\:\mathrm{these}\:\mathrm{transformations} \\ $$$$\mathrm{we}\:\mathrm{have}\:\mathrm{to}\:\mathrm{check}\:\mathrm{all}\:\mathrm{solutions}!!! \\ $$$$ \\ $$$${a}^{\mathrm{1}/\mathrm{2}} +{b}^{\mathrm{1}/\mathrm{2}} ={c}^{\mathrm{1}/\mathrm{2}}…

Solve-the-following-compound-inequation-in-interval-0-2pi-tan-x-2-1-and-tan-x-2-lt-0-

Question Number 1418 by Rasheed Ahmad last updated on 04/Aug/15 $${Solve}\:{the}\:{following}\:{compound} \\ $$$${inequation}\:{in}\:{interval}\:\left(\mathrm{0},\:\mathrm{2}\pi\right), \\ $$$${tan}\frac{{x}}{\mathrm{2}}\:\leqslant\:−\mathrm{1}\:\:{and}\:\:{tan}\frac{{x}}{\mathrm{2}}\:<\:\mathrm{0}\:. \\ $$ Commented by 123456 last updated on 31/Jul/15 $$\mathrm{tan}\:\frac{\pi}{\mathrm{4}}=−\mathrm{tan}\:\frac{\mathrm{3}\pi}{\mathrm{4}}=\mathrm{tan}\:\frac{\mathrm{5}\pi}{\mathrm{4}}=−\mathrm{tan}\:\frac{\mathrm{7}\pi}{\mathrm{4}}=\mathrm{1}…

sin-sin-x-cos-cos-x-x-0-2pi-

Question Number 1417 by 123456 last updated on 30/Jul/15 $$\mathrm{sin}\:\left(\mathrm{sin}\:{x}\right)\leqslant\mathrm{cos}\:\left(\mathrm{cos}\:{x}\right) \\ $$$${x}\in\left[\mathrm{0},\mathrm{2}\pi\right) \\ $$ Commented by Rasheed Ahmad last updated on 02/Aug/15 $${What}\:{to}\:{do}\:{with}\:{it}?\:{Is}\:{it}\:{an}\:{inequation} \\ $$$${to}\:{solve}?\:{Or}\:{is}\:{it}\:{an}\:{identity}\:{to}…

define-f-x-y-xy-x-2-y-2-x-2-y-2-if-x-y-0-0-0-if-x-y-0-0-show-that-f-f-x-and-f-y-are-continuous-on-R-2-show-that-2-f-x-y-and-

Question Number 132477 by KZ last updated on 14/Feb/21 $${define} \\ $$$${f}\left({x}.{y}\right)= \\ $$$$\left.\left\{\frac{\mathrm{xy}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{y}^{\mathrm{2}} \right)\:}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }\:{if}\:\left({x}.{y}\right)\neq\right)\mathrm{0}.\mathrm{0}\right) \\ $$$$\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{if}\:\left({x}.{y}\right)=\left(\mathrm{0}.\mathrm{0}\right) \\ $$$$ \\ $$$${show}\:{that}\:{f},\frac{\partial{f}}{\partial{x}}\:{and}\:\frac{\partial{f}}{\partial{y}\:\:}\:{are}\: \\…

Solve-the-following-inequality-sinx-1-cosx-1-where-0-x-lt-2pi-cosx-0-

Question Number 1407 by 112358 last updated on 29/Jul/15 $${Solve}\:{the}\:{following}\:{inequality} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{sinx}+\mathrm{1}}{{cosx}}\leqslant\mathrm{1} \\ $$$${where}\:\mathrm{0}\leqslant{x}<\mathrm{2}\pi\:,\:{cosx}\neq\mathrm{0} \\ $$ Commented by 123456 last updated on 29/Jul/15 $${f}\left({x}\right)=\frac{\mathrm{sin}\:{x}+\mathrm{1}}{\mathrm{cos}\:{x}} \\…