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Author: Tinku Tara

x-cosh-x-sinh-x-2-dx-

Question Number 132473 by physicstutes last updated on 14/Feb/21 $$\int\:\frac{{x}\:\mathrm{cosh}\:{x}}{\left(\mathrm{sinh}\:{x}\right)^{\mathrm{2}} }\:{dx} \\ $$ Answered by mathmax by abdo last updated on 14/Feb/21 $$\mathrm{I}=\int\:\frac{\mathrm{xchx}}{\mathrm{sh}^{\mathrm{2}} \mathrm{x}}\mathrm{dx}\:\:\mathrm{by}\:\mathrm{parts}\:\:\mathrm{u}^{'} \:=\frac{\mathrm{chx}}{\mathrm{sh}^{\mathrm{2}}…

Question-66938

Question Number 66938 by Cmr 237 last updated on 20/Aug/19 Commented by mathmax by abdo last updated on 21/Aug/19 $$\left.\mathrm{8}\right){by}\:{parts}\:\:\int\:{ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right){dx}\:={xln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)−\int\:{x}\frac{\mathrm{2}{x}}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$$$={xln}\left(\mathrm{1}+{x}^{\mathrm{2}}…

Question-132469

Question Number 132469 by Algoritm last updated on 14/Feb/21 Answered by Olaf last updated on 15/Feb/21 $$\mathrm{Let}\:\Omega_{{i}} \:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{{x}_{{i}} \left(\mathrm{1}−\mathrm{ln}{x}_{{i}} \right)}{dx}_{{i}} \\ $$$$\mathrm{Let}\:{u}_{{i}} \:=\:\mathrm{1}−\mathrm{ln}{x}_{{i}}…

Arrange-8-coins-in-one-line-on-a-table-such-that-the-head-or-tail-will-be-facing-upward-Try-to-flip-two-neighboring-coins-that-are-not-with-identical-face-upside-down-After-several-operations-how-

Question Number 1397 by 314159 last updated on 28/Jul/15 $${Arrange}\:\mathrm{8}\:{coins}\:{in}\:{one}\:{line}\:{on}\:{a}\:{table} \\ $$$${such}\:{that}\:{the}\:{head}\:{or}\:{tail}\:{will}\:{be}\:{facing} \\ $$$${upward}.{Try}\:{to}\:{flip}\:{two}\:{neighboring}\:{coins}\: \\ $$$${that}\:{are}\:{not}\:{with}\:{identical}\:{face}\:{upside}\:{down}.{After}\: \\ $$$${several}\:{operations}\:,\:{how}\:{many}\:{different}\: \\ $$$${ways}\:{can}\:{the}\:{heads}\:{and}\:{tails}\:{be}\:{arranged} \\ $$$${in}\:{one}\:{line}\:{on}\:{the}\:{table}. \\ $$ Commented…

tan-3-x-dx-

Question Number 132470 by physicstutes last updated on 14/Feb/21 $$\int\:\mathrm{tan}^{\mathrm{3}} {x}\:{dx} \\ $$ Answered by mindispower last updated on 14/Feb/21 $$\int{tg}\left({x}\right)\left(\mathrm{1}+{tg}^{\mathrm{2}} \left({x}\right)\right){dx}−\int{tg}\left({x}\right){dx} \\ $$$$=\frac{{tg}^{\mathrm{2}} \left({x}\right)}{\mathrm{2}}+{ln}\mid{cos}\left({x}\right)\mid+{c}…