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Author: Tinku Tara

solve-the-system-of-congruence-x-1-mod-5-x-2-mod-7-x-3-mod-9-x-4-mod-11-

Question Number 66832 by Rio Michael last updated on 20/Aug/19 $${solve}\:{the}\:{system}\:{of}\:{congruence} \\ $$$$\:\:\:\left.\begin{matrix}{{x}\equiv\:\mathrm{1}\:\left({mod}\:\mathrm{5}\right)}\\{{x}\:\equiv\:\mathrm{2}\:\left({mod}\:\mathrm{7}\right)}\\{{x}\equiv\:\:\mathrm{3}\left({mod}\:\mathrm{9}\right)}\\{{x}\:\equiv\:\mathrm{4}\left(\:{mod}\:\mathrm{11}\right)}\end{matrix}\right\} \\ $$ Answered by mr W last updated on 26/Aug/19 $${x}=\mathrm{5}{h}+\mathrm{1}\:\:\:\:…\left(\mathrm{1}\right) \\…

Somewhere-there-are-scorpio-snake-and-mouse-We-ascertain-that-Every-morning-each-snake-eats-a-mouse-Every-afternoon-each-scorpio-kills-a-snake-And-every-night-each-mouse-eats-a-scorpio-

Question Number 66833 by ~ À ® @ 237 ~ last updated on 20/Aug/19 $${Somewhere}\:,\:{there}\:{are}\:{scorpio},\:{snake}\:{and}\:{mouse}. \\ $$$${We}\:{ascertain}\:{that}\:: \\ $$$${Every}\:{morning}\:,\:{each}\:{snake}\:{eats}\:{a}\:{mouse}\:. \\ $$$${Every}\:{afternoon}\:,{each}\:{scorpio}\:\:{kills}\:{a}\:{snake}. \\ $$$${And}\:{every}\:{night}\:,\:{each}\:{mouse}\:{eats}\:{a}\:{scorpio}. \\ $$$${Two}\:{weeks}\:{passed}\:{and}\:{we}\:{find}\:{that}\:{there}\:{was}\:{remaining}\:{only}\:{one}\:{animal}\:.…

lim-n-x-n-n-1-

Question Number 132367 by Raxreedoroid last updated on 13/Feb/21 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{{x}^{{n}} }{\Gamma\left({n}+\mathrm{1}\right)} \\ $$ Answered by TheSupreme last updated on 13/Feb/21 $${if}\:{n}\in\mathbb{N}\:\rightarrow\:\Gamma\left({n}+\mathrm{1}\right)={n}! \\ $$$$\mathrm{lim}\:\frac{\mathrm{x}^{\mathrm{n}} }{\mathrm{n}!}=\mathrm{0}\:\forall{x}\in\mathbb{R}_{\mathrm{0}}…

Question-66827

Question Number 66827 by mr W last updated on 20/Aug/19 Commented by mr W last updated on 20/Aug/19 $${the}\:{graph}\:{above}\:{shows}\:{the}\:{equation} \\ $$$$\frac{\mathrm{ln}\:\left({x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\right)}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}=\frac{\mathrm{ln}\:\left({y}+\sqrt{\mathrm{1}+{y}^{\mathrm{2}} }\right)}{\:\sqrt{\mathrm{1}+{y}^{\mathrm{2}} }}…