Question Number 66794 by mathmax by abdo last updated on 19/Aug/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{cos}\left(\mathrm{2}{arctan}\left(\mathrm{2}{x}\right)\right)}{\mathrm{9}+{x}^{\mathrm{2}} }{dx} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 132328 by liberty last updated on 13/Feb/21 $$\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{p}−\mathrm{x}−\mathrm{x}^{\mathrm{2}} −\mathrm{x}^{\mathrm{3}} −…−\mathrm{x}^{\mathrm{p}} }{\mathrm{x}−\mathrm{1}}\:=? \\ $$ Answered by EDWIN88 last updated on 13/Feb/21 $$\:\mathrm{The}\:\mathrm{limit}\:\mathrm{is}\:\mathrm{form}\:\frac{\mathrm{0}}{\mathrm{0}} \\…
Question Number 66795 by mathmax by abdo last updated on 19/Aug/19 $${let}\:{f}\left({x}\right)\:={e}^{−{x}} {ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Commented by mathmax by…
Question Number 66792 by mathmax by abdo last updated on 19/Aug/19 $${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{cos}\left(\mathrm{2}\:{arctan}\left({x}\right)\right){dx} \\ $$ Commented by mathmax by abdo last updated on 20/Aug/19…
Question Number 66793 by mathmax by abdo last updated on 19/Aug/19 $${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{cos}\left(\mathrm{3}{arctanx}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 66790 by mathmax by abdo last updated on 19/Aug/19 $${find}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{x}}{{sh}\left({x}\right)}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1255 by e.nolley@ieee.org last updated on 18/Jul/15 $$\left(\mathrm{X},\mathrm{F}\left(\mathrm{X}\right)\right),\:\mathrm{X}\in{C},\:\mathrm{F}\left(\mathrm{X}\right)\in{C},\:\:\mathrm{can}\:\mathrm{be}\:\: \\ $$$$\mathrm{plotted}\:\mathrm{in}\:\mathrm{R}^{\mathrm{2}} \:\left(\mathrm{Im}\:\mathrm{on}\:\mathrm{Y},\:\mathrm{Real}\:\mathrm{on}\:\mathrm{X}\right. \\ $$$$\left.\mathrm{axes}\right)\:\mathrm{as}\:\mathrm{a}\:\mathrm{directed}\:\mathrm{line}\:\mathrm{segment}, \\ $$$$\overset{} {\:}\overset{} {\left(\mathrm{X}\right)−−\gg\left(\mathrm{F}\left(\mathrm{X}\right)\right)}.\:\mathrm{This}\:\mathrm{has} \\ $$$$\mathrm{the}\:\mathrm{advantage}\:\mathrm{of}\:\mathrm{showing}\:\mathrm{vector}\: \\ $$$$\mathrm{ffields},\:\mathrm{fixed}\:\mathrm{points}\:\mathrm{and}\:\mathrm{bifurcations}. \\ $$$$…
Question Number 132324 by mnjuly1970 last updated on 13/Feb/21 $$\:\:\:\:\:\:\:\:\:\:\:\:….{advanced}\:\:\:{calculus}… \\ $$$$\:\:\:{evaluation}\:: \\ $$$$\:\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}\:^{\:\:} } ^{\:\infty} \frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}\:{dx} \\ $$$$\:\:\:\:{solution}: \\ $$$$\:\:\boldsymbol{\phi}=\left[\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}{dx}=\boldsymbol{\phi}_{\mathrm{1}}…
Question Number 66791 by mathmax by abdo last updated on 19/Aug/19 $${let}\:\:{f}\left({x}\right)\:={cos}\left(\mathrm{2}{arctanx}\right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Commented by mathmax by abdo last…
Question Number 132327 by liberty last updated on 13/Feb/21 $$\:\mathrm{If}\:\mathrm{the}\:\mathrm{line}\:\begin{cases}{\frac{\mathrm{x}−\mathrm{1}}{\mathrm{2}}=\frac{\mathrm{y}+\mathrm{1}}{\mathrm{3}}=\frac{\mathrm{z}−\mathrm{1}}{\mathrm{4}}}\\{\frac{\mathrm{x}−\mathrm{3}}{\mathrm{1}}=\frac{\mathrm{y}−\mathrm{k}}{\mathrm{2}}=\frac{\mathrm{z}}{\mathrm{1}}}\end{cases} \\ $$$$\:\mathrm{intersect}\:.\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{is}\: \\ $$ Answered by Ar Brandon last updated on 13/Feb/21 $$\mathrm{L}_{\mathrm{1}} :\:\mathrm{i}−\mathrm{j}+\mathrm{k}+\lambda\left(\mathrm{2i}+\mathrm{3j}+\mathrm{4k}\right)=\left(\mathrm{1}+\mathrm{2}\lambda\right)\mathrm{i}+\left(\mathrm{3}\lambda−\mathrm{1}\right)\mathrm{j}+\left(\mathrm{4}\lambda+\mathrm{1}\right)\mathrm{k} \\…