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Author: Tinku Tara

Given-f-x-x-x-2-1-27-1-3-x-x-2-1-27-1-3-g-x-x-3-x-1-Find-0-4-g-f-g-x-dx-

Question Number 133973 by liberty last updated on 26/Feb/21 $$\:\mathrm{Given}\:\begin{cases}{\mathrm{f}\left(\mathrm{x}\right)=\sqrt[{\mathrm{3}}]{\mathrm{x}+\sqrt{\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{27}}}}+\sqrt[{\mathrm{3}}]{\mathrm{x}−\sqrt{\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{27}}}}}\\{\mathrm{g}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{3}} +\mathrm{x}+\mathrm{1}}\end{cases} \\ $$$$\mathrm{Find}\:\underset{\mathrm{0}} {\overset{\mathrm{4}} {\int}}\:\left(\mathrm{g}\circ\mathrm{f}\circ\mathrm{g}\right)\left(\mathrm{x}\right)\:\mathrm{dx}\:. \\ $$ Answered by EDWIN88 last updated on…

H-2x-1-7-2x-1-9-dx-

Question Number 133972 by liberty last updated on 26/Feb/21 $$\mathscr{H}\:=\:\int\:\frac{\left(\mathrm{2x}−\mathrm{1}\right)^{\mathrm{7}} }{\left(\mathrm{2x}+\mathrm{1}\right)^{\mathrm{9}} }\:\mathrm{dx}\: \\ $$ Answered by EDWIN88 last updated on 26/Feb/21 $$\:\mathscr{H}\:=\:\int\:\left(\frac{\mathrm{2x}−\mathrm{1}}{\mathrm{2x}+\mathrm{1}}\right)^{\mathrm{7}} .\frac{\mathrm{dx}}{\left(\mathrm{2x}+\mathrm{1}\right)^{\mathrm{2}} } \\…

Question-68434

Question Number 68434 by mhmd last updated on 10/Sep/19 Answered by mind is power last updated on 10/Sep/19 $$\int_{{a}} ^{{b}} {f}\left({x}\right){dx}=\int_{{a}} ^{{b}} {f}\left({a}+\mathrm{b}−\mathrm{x}\right)\mathrm{dx} \\ $$$$\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{3sin}\left(\mathrm{x}\right)−\mathrm{2sin}^{\mathrm{2}}…

hello-i-search-som-lectur-about-hypergeometric-fonction2F-1-a-b-c-x-c-a-b-n-0-a-n-b-n-c-n-n-x-n-

Question Number 68433 by mind is power last updated on 10/Sep/19 $${hello} \\ $$$${i}\:{search}\:{som}\:{lectur}\:{about}\:{hypergeometric}\:{fonction}\mathrm{2}{F}_{\mathrm{1}} \left({a},{b},{c},{x}\right)=\frac{\Gamma\left({c}\right)}{\Gamma\left({a}\right)\Gamma\left({b}\right)}\sum_{{n}\geqslant\mathrm{0}} \frac{\Gamma\left({a}+{n}\right)\Gamma\left({b}+{n}\right)}{\Gamma\left({c}+{n}\right){n}!}{x}^{{n}} \\ $$$$ \\ $$ Terms of Service Privacy Policy…

Question-133961

Question Number 133961 by Ahmed1hamouda last updated on 25/Feb/21 Answered by mathmax by abdo last updated on 27/Feb/21 $$\mathrm{y}^{'} \:+\mathrm{sinx}\:\mathrm{y}=−\mathrm{x}^{\mathrm{3}} \\ $$$$\mathrm{h}\rightarrow\mathrm{y}^{'} \:+\mathrm{sinxy}=\mathrm{0}\:\Rightarrow\mathrm{y}^{'} \:=−\mathrm{sinxy}\:\Rightarrow\frac{\mathrm{y}^{'} }{\mathrm{y}}=−\mathrm{sinx}\:\Rightarrow\mathrm{ln}\mid\mathrm{y}\mid=\mathrm{cosx}\:+\mathrm{c}\:\Rightarrow…

given-z-lim-n-n-z-z-1-z-n-n-z-proof-that-i-z-1-z-z-ii-wiertrass-definition-of-gamma-function-1-z-ze-z-m-1-1-z-m-e-z-m-is-euler-macheroni-con

Question Number 2891 by 123456 last updated on 29/Nov/15 $$\mathrm{given} \\ $$$$\Gamma\left({z}\right)=\underset{{n}\rightarrow+\infty} {\mathrm{lim}}\:\frac{{n}!}{{z}\left({z}+\mathrm{1}\right)\centerdot\centerdot\centerdot\left({z}+{n}\right)}{n}^{{z}} \\ $$$$\mathrm{proof}\:\mathrm{that} \\ $$$$\left.{i}\right) \\ $$$$\Gamma\left({z}+\mathrm{1}\right)={z}\Gamma\left({z}\right) \\ $$$$\left.{ii}\right)\:\mathrm{wiertrass}\:\mathrm{definition}\:\mathrm{of}\:\mathrm{gamma}\:\mathrm{function} \\ $$$$\frac{\mathrm{1}}{\Gamma\left({z}\right)}={ze}^{{z}\gamma} \underset{{m}=\mathrm{1}} {\overset{+\infty}…

Y-dx-1-x-6-1-6-

Question Number 133963 by bobhans last updated on 25/Feb/21 $$\mathcal{Y}\:=\:\int\:\frac{{dx}}{\:\sqrt[{\mathrm{6}}]{\mathrm{1}+{x}^{\mathrm{6}} }}? \\ $$ Answered by EDWIN88 last updated on 26/Feb/21 $$\mathbb{Y}=\:\int\:\frac{\mathrm{dx}}{\mathrm{x}\:\sqrt[{\mathrm{6}}]{\mathrm{1}+\mathrm{x}^{−\mathrm{6}} }}\:=\:\int\:\frac{\mathrm{x}^{\mathrm{6}} }{\mathrm{x}^{\mathrm{7}} \:\sqrt[{\mathrm{6}}]{\mathrm{1}+\mathrm{x}^{−\mathrm{6}} }}\:\mathrm{dx}\:…

Question-68425

Question Number 68425 by mr W last updated on 10/Sep/19 Commented by Prithwish sen last updated on 10/Sep/19 $$\mathrm{AB}=\mathrm{2x}\:\:\mathrm{AC}=\mathrm{x} \\ $$$$\mathrm{3x}×\mathrm{100}×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\mathrm{2x}^{\mathrm{2}} ×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\mathrm{2x}^{\mathrm{2}} −\mathrm{300x}=\mathrm{0}\:\Rightarrow\mathrm{x}=\mathrm{150}…