Question Number 132257 by Salman_Abir last updated on 12/Feb/21 Answered by bemath last updated on 12/Feb/21 $$\left(\mathrm{i}\right)\mathrm{E}\left(\mathrm{0},\mathrm{0},\mathrm{8}\right),\:\mathrm{C}\left(\mathrm{3},\mathrm{3},\mathrm{0}\right)\:\mathrm{vector}\: \\ $$$$\:\mathrm{EC}\:=\:\mathrm{3}\hat {\mathrm{i}}+\mathrm{3}\hat {\mathrm{j}}−\mathrm{8}\hat {\mathrm{k}}\:;\:\mid\mathrm{EC}\mid=\sqrt{\mathrm{9}+\mathrm{9}+\mathrm{64}}\:=\sqrt{\mathrm{82}} \\ $$$$\:\mathrm{H}\left(\mathrm{0},\mathrm{3},\mathrm{8}\right)\:,\mathrm{B}\left(\mathrm{3},\mathrm{0},\mathrm{0}\right)\:\mathrm{vector}\: \\…
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Question Number 66718 by otchereabdullai@gmail.com last updated on 18/Aug/19 Commented by Tony Lin last updated on 19/Aug/19 Commented by Tony Lin last updated on 19/Aug/19…
Question Number 132252 by aurpeyz last updated on 12/Feb/21 $$ \\ $$$$\mathrm{A}\:\mathrm{rectangular}\:\mathrm{glass}\:\mathrm{block}\:\left(\mathrm{n}=\mathrm{1}.\mathrm{52}\right)\:\mathrm{is} \\ $$$$\mathrm{pla}{c}\mathrm{ed}\:\mathrm{inside}\:\mathrm{a}\:\mathrm{clean}\:\mathrm{water}\:\mathrm{contained}\: \\ $$$$\mathrm{in}\:\mathrm{a}\:\mathrm{basin}.\:\mathrm{A}\:\mathrm{layer}\:\mathrm{of}\:\mathrm{oil}\:\left(\mathrm{n}=\mathrm{1}.\mathrm{44}\right)\:\mathrm{floats} \\ $$$$\mathrm{o}{n}\:\mathrm{the}\:\mathrm{water}\:\mathrm{surface}.\:\mathrm{A}\:\mathrm{ray}\:\mathrm{of}\:\mathrm{light}\: \\ $$$$\mathrm{from}\:\mathrm{air}\:\mathrm{strikes}\:\mathrm{the}\:\mathrm{oil}\:\mathrm{surface}\:\mathrm{at}\:\mathrm{an} \\ $$$$\mathrm{ange}\:\mathrm{of}\:\mathrm{incidence}\:\mathrm{of}\:\mathrm{28}^{\mathrm{0}} .\:\mathrm{Calculate}\:\mathrm{the} \\ $$$$\mathrm{a}{n}\mathrm{gle}\:\mathrm{of}\:\mathrm{refraction}\:\mathrm{at}\:\mathrm{the}\:\mathrm{water}−\mathrm{glass}…
Question Number 132255 by aurpeyz last updated on 12/Feb/21 $${A}\:{ray}\:{of}\:{light}\:{is}\:{incident}\:{at}\:\mathrm{60}^{\mathrm{0}} \:{at}\:{an} \\ $$$${air}−{glass}\:{plane}\:{surface}.\:{find}\:{the}\: \\ $$$${angle}\:{of}\:{refraction}\:{in}\:{the}\:{glass}\left(\right. \\ $$$$\left.{refractive}\:{index}\:{for}\:{glass}=\mathrm{1}.\mathrm{5}\right) \\ $$$$\left({a}\right)\:\mathrm{25}.\mathrm{3}\:\left({b}\right)\:\mathrm{35}.\mathrm{3}\:\left({c}\right)\:\mathrm{15}.\mathrm{3}\:\left({d}\right)\mathrm{30} \\ $$ Commented by Dwaipayan Shikari…
Question Number 1181 by 22 last updated on 11/Jul/15 $$\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}}=? \\ $$ Answered by Rasheed Ahmad last updated on 24/Jul/15 $${In}\:{certain}\:{cases}\:\sqrt{{a}+{b}\sqrt{{c}}\:}\:{can}\:{be} \\ $$$${simplified}\:{into}\:{p}+{q}\sqrt{{c}}\:{form}\left({not}\right. \\ $$$$\left.{in}\:{all}\:{cases}\right).\:{The}\:{procedure}\:{is}\:{as}…
Question Number 1180 by 934111 last updated on 11/Jul/15 $${f}\left({x}^{\mathrm{2}} \right)−{f}\left({x}\right)=\mathrm{1} \\ $$ Commented by 123456 last updated on 11/Jul/15 $$\left\{\mathrm{0},\mathrm{1}\right\}\notin\mathrm{D}\left({f}\right) \\ $$ Answered by…
Question Number 132248 by aurpeyz last updated on 12/Feb/21 $$ \\ $$$${In}\:{a}\:\mathrm{60}^{\mathrm{0}} \:{prism}\:{of}\:{refractive}\:{index}\:\mathrm{1}.\mathrm{5} \\ $$$${calculate}\:{the}\:{angle}\:{of}\:{minimum}\: \\ $$$${deviation}\:{when}\:{light}\:{is}\:{refracted} \\ $$$${throuh}\:{the}\:{prism} \\ $$$$\left({a}\right)\:\mathrm{40}.\mathrm{2}\:\left({b}\right)\:\mathrm{37}.\mathrm{5}\:\left({c}\right)\:\mathrm{37}.\mathrm{2}\:\left({d}\right)\:\mathrm{40}.\mathrm{5}\:\left({e}\right)\mathrm{40}.\mathrm{6} \\ $$ Commented by…
Question Number 66715 by mr W last updated on 18/Aug/19 $${if}\:{f}\left({x}\right)=\frac{\mathrm{ln}\:\left({x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\right)}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }} \\ $$$${f}^{−\mathrm{1}} \left({x}\right)=? \\ $$ Commented by Tony Lin last updated on…
Question Number 132251 by Arijit last updated on 12/Feb/21 Terms of Service Privacy Policy Contact: info@tinkutara.com