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Author: Tinku Tara

What-is-the-set-Z-8-0-I-met-this-notation-in-a-question-asking-whether-or-not-the-set-Z-8-0-forms-a-group-under-multiplication-mod-8-

Question Number 1171 by 112358 last updated on 09/Jul/15 $${What}\:{is}\:{the}\:{set}\:\mathbb{Z}_{\mathrm{8}} −\left\{\mathrm{0}\right\}?\:{I}\:{met} \\ $$$${this}\:{notation}\:{in}\:{a}\:{question}\:{asking} \\ $$$${whether}\:{or}\:{not}\:{the}\:{set}\:\mathbb{Z}_{\mathrm{8}} −\left\{\mathrm{0}\right\} \\ $$$${forms}\:{a}\:{group}\:{under}\: \\ $$$${multiplication}\:\left({mod}\:\mathrm{8}\right). \\ $$ Answered by 123456…

lim-x-0-tan-2x-pi-4-2tan-x-pi-4-tan-pi-4-sin-2x-pi-4-2sin-x-pi-4-sin-pi-4-

Question Number 132240 by bemath last updated on 12/Feb/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{tan}\:\left(\mathrm{2x}+\frac{\pi}{\mathrm{4}}\right)−\mathrm{2tan}\:\left(\mathrm{x}+\frac{\pi}{\mathrm{4}}\right)+\mathrm{tan}\:\frac{\pi}{\mathrm{4}}}{\mathrm{sin}\:\left(\mathrm{2x}+\frac{\pi}{\mathrm{4}}\right)−\mathrm{2sin}\:\left(\mathrm{x}+\frac{\pi}{\mathrm{4}}\right)+\mathrm{sin}\:\frac{\pi}{\mathrm{4}}}\:? \\ $$$$ \\ $$ Answered by EDWIN88 last updated on 13/Feb/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2sec}\:^{\mathrm{2}} \left(\mathrm{2x}+\frac{\pi}{\mathrm{4}}\right)−\mathrm{2sec}\:^{\mathrm{2}}…

Question-66697

Question Number 66697 by naka3546 last updated on 18/Aug/19 Commented by kaivan.ahmadi last updated on 18/Aug/19 $${lim}_{{x}\rightarrow\frac{\pi}{\mathrm{4}}} \:\frac{−{sin}\left({x}−\frac{\pi}{\mathrm{4}}\right)−\left(\mathrm{1}+{tan}^{\mathrm{2}} {x}\right)}{{cos}\left({x}−\frac{\pi}{\mathrm{4}}\right)}=\frac{\mathrm{0}−\left(\mathrm{1}+\mathrm{1}\right)}{\mathrm{1}}=−\mathrm{2} \\ $$ Answered by Cmr 237…

let-f-a-dx-x-4-x-2-a-with-a-1-4-1-calculate-f-a-2-find-also-g-a-dx-x-4-x-2-a-2-3-find-the-value-of-integrals-0-dx-x-4-x-2-3-

Question Number 66694 by mathmax by abdo last updated on 18/Aug/19 $$\left.{let}\:{f}\left({a}\right)\:=\int_{−\infty} ^{+\infty} \:\:\frac{{dx}}{\left({x}^{\mathrm{4}} +{x}^{\mathrm{2}} \:+{a}\right)}\:{with}\:{a}\in\right]\frac{\mathrm{1}}{\mathrm{4}},+\infty\left[\right. \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}\left({a}\right) \\ $$$$\left.\mathrm{2}\right){find}\:{also}\:{g}\left({a}\right)\:=\int_{−\infty} ^{+\infty} \:\frac{{dx}}{\left({x}^{\mathrm{4}} \:+{x}^{\mathrm{2}} +{a}\right)^{\mathrm{2}} }…