Question Number 66656 by Tanmay chaudhury last updated on 18/Aug/19 Commented by Rahul Kumar last updated on 18/Aug/19 $${please}\:{answer}\:{the}\:{question}. \\ $$ Answered by mr W…
Question Number 132194 by aurpeyz last updated on 12/Feb/21 Commented by mr W last updated on 12/Feb/21 $$\frac{{d}\theta}{{dr}}=\mathrm{3}{r}^{\mathrm{2}} −\mathrm{1} \\ $$$$\Delta\theta\approx\left(\mathrm{3}{r}^{\mathrm{2}} −\mathrm{1}\right)\Delta{r}=\left(\mathrm{3}×\mathrm{1}^{\mathrm{2}} −\mathrm{1}\right)×\mathrm{0}.\mathrm{05}=\mathrm{0}.\mathrm{1} \\ $$…
Question Number 1120 by 123456 last updated on 17/Jun/15 $$\mathrm{given}\:{f}:\mathbb{R}\rightarrow\mathbb{R} \\ $$$${f}\left({x}\right)={a}_{{n}} {x}^{{n}} +\centerdot\centerdot\centerdot+{a}_{\mathrm{0}} \: \\ $$$$\mathrm{with}\:{a}_{{n}} \neq\mathrm{0},\:{a}_{{i}} \in\mathbb{R},{i}\in\left\{\mathrm{0},\mathrm{1},…,{n}\right\},{n}\in\mathbb{N}^{\ast} \\ $$$$\mathrm{supose}\:\mathrm{that}\:{x}_{\mathrm{1}} ,…,{x}_{{n}} \\ $$$$\mathrm{are}\:\mathrm{roots}\:\mathrm{the}\:{n}\:\mathrm{roots}\:\mathrm{of}\:{f}\left({x}\right) \\…
Question Number 132191 by rs4089 last updated on 12/Feb/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{log}_{{e}} \left({x}+\mathrm{1}\right)}{{x}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}{dx} \\ $$ Answered by mathmax by abdo last updated on 12/Feb/21…
Question Number 1117 by 123456 last updated on 17/Jun/15 $${a}_{\mathrm{0}} =\mathrm{1} \\ $$$${a}_{{n}} =\frac{\sqrt{{a}_{{n}−\mathrm{1}} }}{{a}_{{n}−\mathrm{1}} }+\mathrm{1} \\ $$$$\underset{{n}\rightarrow+\infty} {\mathrm{lim}}\:{a}_{{n}} =? \\ $$ Commented by 123456…
Question Number 1113 by 123456 last updated on 15/Jun/15 $$\mathrm{sin}^{−\mathrm{1}} \left[\frac{\sqrt{\mathrm{3}}}{\mathrm{8}}\left(\sqrt{\mathrm{13}}−\mathrm{1}\right)\right]+\mathrm{sin}^{−\mathrm{1}} \frac{\sqrt{\mathrm{3}}}{\mathrm{4}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1112 by malwaan last updated on 14/Jun/15 $${compare}\:\frac{\mathrm{1}}{{log}_{\mathrm{2}} \pi}\:+\:\frac{\mathrm{1}}{{log}_{\mathrm{5}} \pi}\:{and}\:\mathrm{2} \\ $$ Answered by prakash jain last updated on 15/Jun/15 $$\mathrm{log}_{\pi} \mathrm{2}+\mathrm{log}_{\pi} \mathrm{5}=\mathrm{log}_{\pi}…
Question Number 132181 by aurpeyz last updated on 12/Feb/21 Commented by aurpeyz last updated on 12/Feb/21 $$\boldsymbol{{no}}\:\mathrm{10}\:\boldsymbol{{pls}} \\ $$ Answered by ajfour last updated on…
Question Number 132180 by bounhome last updated on 12/Feb/21 $${solve}\:: \\ $$$$\mathrm{2}{sec}^{\mathrm{2}} {x}+\left(\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{3}\right){secx}−\mathrm{3}\sqrt{\mathrm{2}}=\mathrm{0}\:;\:\mathrm{0}\leqslant{x}\leqslant\frac{\pi}{\mathrm{4}} \\ $$ Answered by benjo_mathlover last updated on 12/Feb/21 $$\:\mathrm{3}\sqrt{\mathrm{2}}\:\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}−\left(\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{3}\right)\mathrm{cos}\:\mathrm{x}−\mathrm{2}=\mathrm{0} \\…
Question Number 1107 by rpatle69@gmail.com last updated on 14/Jun/15 $${a}\:{square}\:{is}\:{created}\:{inside}\:{the}\: \\ $$$${circle},{which}\:{side}\:{is}\:\mathrm{4}\:{cm}.{Then}\: \\ $$$${find}\:{out}\:{the}\:{area}\:{between}\:{square} \\ $$$${and}\:{circle}. \\ $$$$ \\ $$$$ \\ $$ Answered by prakash…