Question Number 1750 by Lissy=ž=ždd
Question Number 1748 by Rasheed Ahmad last updated on 14/Sep/15 $${Why}\:\:\:{a}^{\mathrm{0}} =\mathrm{1}\:{and}\:\:{a}^{−\mathrm{3}} =\frac{\mathrm{1}}{{a}^{\mathrm{3}} } \\ $$ Answered by 123456 last updated on 14/Sep/15 $$\frac{{a}^{{x}} }{{a}^{{y}}…
Question Number 67281 by Tony Lin last updated on 25/Aug/19 Commented by mr W last updated on 25/Aug/19 $${I}\:{get}\:\mathrm{3}{C}_{\mathrm{2}} ^{\mathrm{5}} +\mathrm{3}{C}_{\mathrm{2}} ^{\mathrm{5}} +\mathrm{12}=\mathrm{72} \\ $$…
Question Number 1744 by Rasheed Ahmad last updated on 13/Sep/15 $${If}\:\boldsymbol{\mathrm{A}}\:{and}\:\boldsymbol{\mathrm{B}}\:{are}\:{two}\:{sets}\:{and}\:\mathbb{U}\:{is} \\ $$$${a}\:{universal}\:{set}\:{prove}\:{that} \\ $$$$\boldsymbol{\mathrm{A}}\:\subseteq\:\boldsymbol{\mathrm{B}}\:\:\Rightarrow\:\boldsymbol{\mathrm{B}}=\boldsymbol{\mathrm{A}}\:\cup\:\left(\boldsymbol{\mathrm{A}}'\:\cap\:\boldsymbol{\mathrm{B}}\right) \\ $$ Answered by Rasheed Ahmad last updated on 19/Sep/15…
Question Number 1743 by 123456 last updated on 12/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}=? \\ $$ Commented by Rasheed Ahmad last updated on 13/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}'{v}+{uv}'−{u}'{v}'=\mathrm{0}…
Question Number 1740 by tabrez8590@gmail last updated on 11/Sep/15 $${how}\:\:\mathrm{0}!=\mathrm{1} \\ $$ Commented by 123456 last updated on 11/Sep/15 $$\mathrm{1}!=\mathrm{1}\centerdot\mathrm{0}! \\ $$$$\mathrm{so}\:\mathrm{for}\:\mathrm{it}\:\mathrm{work}\:\mathrm{to}\:\mathrm{1}\:\mathrm{them}\:\mathrm{0}!=\mathrm{1} \\ $$ Answered…
Question Number 132809 by mr W last updated on 17/Feb/21 Commented by mr W last updated on 18/Feb/21 $${a}\:{mountain}\:{has}\:{the}\:{shape}\:{of}\:{a}\:{right} \\ $$$${circular}\:{cone}\:{as}\:{shown}\:\left({h}>\sqrt{\mathrm{3}}{r}\right). \\ $$$${from}\:{point}\:{A}\:{to}\:{point}\:{B}\:{two} \\ $$$${sightseeing}\:{roads}\:{one}\:{time}\:{around}…
Question Number 1738 by Rasheed Sindhi last updated on 08/Sep/15 $${Let}\:\boldsymbol{\mathrm{a}}\:{belongs}\:{to}\:{an}\:{interval}\:\boldsymbol{\mathrm{A}},\boldsymbol{\mathrm{k}}\:{is}\:{aconstant}\:{such}\:{that}\: \\ $$$$\boldsymbol{\mathrm{k}}\in\mathbb{R}^{+} \:{and}\:\boldsymbol{\mathrm{k}}<\boldsymbol{\mathrm{a}}\:. \\ $$$${Find}\:{out}\:\boldsymbol{\mathrm{A}}\:{in}\:{case}: \\ $$$$\:\:\:\:\:\:\:\:\left(\:\boldsymbol{\mathrm{a}}−\boldsymbol{\mathrm{k}}\right)^{\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{k}}} \geqslant\left(\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{k}}\right)^{\boldsymbol{\mathrm{a}}−\boldsymbol{\mathrm{k}}} \\ $$ Terms of Service Privacy…
Question Number 1736 by navajyoti.tamuli.tamuli@gmail. last updated on 04/Sep/15 $${Express}\:\mathrm{0}.\mathrm{999}…\:{as}\:\frac{{p}}{{q}} \\ $$ Answered by 123456 last updated on 04/Sep/15 $${x}=\mathrm{0}.\mathrm{999999}…. \\ $$$$\mathrm{10}{x}=\mathrm{9}.\mathrm{9999999}….. \\ $$$$\mathrm{9}{x}=\mathrm{9} \\…
Question Number 1734 by Rasheed Ahmad last updated on 07/Sep/15 $$\boldsymbol{\mathrm{a}}\:\:{belongs}\:{to}\:{an}\:{interval}\:\boldsymbol{\mathrm{A}}\:{and} \\ $$$$\boldsymbol{\mathrm{k}}\in\mathbb{R}^{+} \:\:{is}\:{a}\:{constant}.\:{Determine} \\ $$$$\boldsymbol{\mathrm{A}}\:{in}\:{case} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mid\boldsymbol{\mathrm{a}}−\boldsymbol{\mathrm{k}}\mid^{\mid\:\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{k}}\:\mid} \geqslant\:\mid\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{k}}\mid^{\mid\boldsymbol{\mathrm{a}}−\boldsymbol{\mathrm{k}}\mid} \: \\ $$$$ \\ $$ Terms…