Menu Close

Author: Tinku Tara

n-1-sin-n-n-2-

Question Number 132162 by Dwaipayan Shikari last updated on 11/Feb/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{sin}\left({n}\right)}{{n}^{\mathrm{2}} } \\ $$ Answered by mnjuly1970 last updated on 11/Feb/21 $$\frac{\mathrm{1}}{\mathrm{2}{i}}\left[{li}_{\mathrm{2}} \left({e}^{{i}}…

I-0-pi-x-pi-x-sin-x-dx-

Question Number 1085 by 123456 last updated on 10/Jun/15 $$\mathrm{I}=\underset{\mathrm{0}} {\overset{\pi} {\int}}\frac{{x}\left(\pi−{x}\right)}{\mathrm{sin}\:{x}}{dx} \\ $$ Commented by 123456 last updated on 10/Jun/15 $${f}\left({x}\right)=\frac{{x}\left(\pi−{x}\right)}{\mathrm{sin}\:{x}} \\ $$$${f}\left(\mathrm{0}^{+} \right)\overset{?}…

Let-a-b-c-p-be-rational-numbers-such-that-p-is-not-a-perfect-cube-If-a-bp-1-3-cp-2-3-0-then-prove-that-a-b-c-0-

Question Number 1083 by Vishal last updated on 08/Jun/15 $${Let}\:{a},{b},{c},{p}\:{be}\:{rational}\:{numbers}\:{such}\:{that}\:{p}\:{is}\:{not}\:{a}\:{perfect}\:{cube}. \\ $$$${If}\:{a}+{bp}^{\frac{\mathrm{1}}{\mathrm{3}}} +{cp}^{\frac{\mathrm{2}}{\mathrm{3}}} =\mathrm{0},\:{then}\:{prove}\:{that}\:{a}={b}={c}=\mathrm{0}. \\ $$ Answered by prakash jain last updated on 08/Jun/15 $${p}^{\mathrm{1}/\mathrm{3}}…

Find-the-smallest-number-which-leaves-remainders-8-and-12-when-divided-by-28-and-32-respectively-

Question Number 1077 by Vishal last updated on 07/Jun/15 $${Find}\:{the}\:{smallest}\:{number}\:{which}\:{leaves}\:{remainders}\:\mathrm{8}\:{and}\:\mathrm{12}\: \\ $$$${when}\:{divided}\:{by}\:\mathrm{28}\:{and}\:\mathrm{32}\:{respectively}. \\ $$ Commented by prakash jain last updated on 07/Jun/15 $$\mathrm{I}\:\mathrm{assume}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{smallest}\:+\mathrm{ve}\:\mathrm{integer}. \\ $$…

Solve-x-2-x-4-1-x-

Question Number 132150 by mohammad17 last updated on 11/Feb/21 $${Solve}:\frac{\mid{x}+\mathrm{2}\mid}{{x}−\mathrm{4}}\leqslant\frac{\mathrm{1}}{\mid{x}\mid} \\ $$ Answered by benjo_mathlover last updated on 11/Feb/21 $$\mathrm{case}\left(\mathrm{1}\right)\:\mathrm{x}>\mathrm{0}\:\Rightarrow\:\frac{\mathrm{x}+\mathrm{2}}{\mathrm{x}−\mathrm{4}}\:−\frac{\mathrm{1}}{\mathrm{x}}\leqslant\mathrm{0} \\ $$$$\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{x}+\mathrm{4}}{\mathrm{x}\left(\mathrm{x}−\mathrm{4}\right)}\leqslant\mathrm{0}\:;\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{4}}{\mathrm{x}\left(\mathrm{x}−\mathrm{4}\right)}\leqslant\mathrm{0} \\…