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Question-132007

Question Number 132007 by abdullahquwatan last updated on 10/Feb/21 Answered by bramlexs22 last updated on 10/Feb/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{cos}\:\mathrm{2x}+\mathrm{sin}\:\mathrm{3x}\left(\mathrm{cos}\:\mathrm{x}−\mathrm{cos}\:\mathrm{2x}\right)−\mathrm{cos}\:\mathrm{x}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}+\mathrm{cos}\:\mathrm{2x}−\mathrm{1}} \\ $$$$=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{cos}\:\mathrm{2x}−\mathrm{cos}\:\mathrm{x}\right)\left(\mathrm{1}−\mathrm{sin}\:\mathrm{3x}\right)}{\mathrm{cos}\:\mathrm{2x}−\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}} \\ $$$$=\:\underset{{x}\rightarrow\mathrm{0}}…

Given-2-cos-A-cos-B-cos-3-B-2-sin-A-sin-B-sin-3-B-what-is-the-value-of-sin-A-B-

Question Number 132006 by bramlexs22 last updated on 10/Feb/21 $$\:\mathrm{Given}\:\begin{cases}{\sqrt{\mathrm{2}}\:\mathrm{cos}\:\mathrm{A}=\mathrm{cos}\:\mathrm{B}+\mathrm{cos}\:^{\mathrm{3}} \mathrm{B}}\\{\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{A}=\mathrm{sin}\:\mathrm{B}−\mathrm{sin}\:^{\mathrm{3}} \mathrm{B}}\end{cases} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sin}\:\left(\mathrm{A}−\mathrm{B}\right). \\ $$ Answered by EDWIN88 last updated on 10/Feb/21 $$\:\begin{cases}{\mathrm{2cos}\:^{\mathrm{2}} \mathrm{A}=\mathrm{cos}\:^{\mathrm{2}}…

find-f-a-b-0-cos-ax-cos-bx-x-2-a-2-x-2-b-2-dx-with-a-gt-0-and-b-gt-0-2-calculate-0-cos-x-cos-2x-x-2-1-x-2-4-dx-

Question Number 66466 by mathmax by abdo last updated on 15/Aug/19 $${find}\:\:{f}\left({a},{b}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\:\frac{{cos}\left({ax}\right){cos}\left({bx}\right)}{\left({x}^{\mathrm{2}} +{a}^{\mathrm{2}} \right)\left({x}^{\mathrm{2}} \:+{b}^{\mathrm{2}} \right)}{dx}\:\:{with}\:{a}>\mathrm{0}\:{and}\:{b}>\mathrm{0} \\ $$$$\left.\mathrm{2}\right){calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{cos}\left({x}\right){cos}\left(\mathrm{2}{x}\right)}{\left({x}^{\mathrm{2}} \:+\mathrm{1}\right)\left({x}^{\mathrm{2}} \:+\mathrm{4}\right)}{dx} \\…