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Question Number 843 by prakash jain last updated on 05/Apr/15 $$\mathrm{There}\:\mathrm{are}\:\mathrm{2}\:\mathrm{doors}\:\mathrm{in}\:\mathrm{a}\:\mathrm{room}\:\mathrm{and}\:\mathrm{only} \\ $$$$\mathrm{one}\:\mathrm{of}\:\mathrm{them}\:\mathrm{leads}\:\mathrm{to}\:\mathrm{exit}.\:\mathrm{There}\:\mathrm{is}\:\mathrm{one} \\ $$$$\mathrm{watchman}\:\mathrm{who}\:\mathrm{tosses}\:\mathrm{a}\:\mathrm{coin}\:\mathrm{when}\:\mathrm{you} \\ $$$$\mathrm{ask}\:\mathrm{a}\:\mathrm{question}\:\mathrm{and}\:\mathrm{speaks}\:\mathrm{truly}\:\mathrm{or}\:\mathrm{falsely} \\ $$$$\mathrm{based}\:\mathrm{on}\:\mathrm{the}\:\mathrm{toss}.\:\mathrm{Also}\:\mathrm{watchman} \\ $$$$\mathrm{gives}\:\mathrm{answer}\:'\mathrm{da}'\:\mathrm{or}\:'\mathrm{ja}'\:\mathrm{one}\:\mathrm{of}\:\mathrm{which}\:\mathrm{means} \\ $$$$\mathrm{yes}\:\left(\mathrm{you}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{which}\:\mathrm{one}\:\mathrm{means}\:\mathrm{yes}\right). \\ $$$$…
Question Number 66379 by Sandy Suhendra last updated on 13/Aug/19 Commented by kaivan.ahmadi last updated on 13/Aug/19 $$={lim}_{{x}\rightarrow\frac{\pi}{\mathrm{2}}} \:\frac{\mathrm{3}{cosx}+\mathrm{5}{cos}\mathrm{3}{x}}{{cot}\mathrm{5}{x}}\:\overset{{hop}} {=} \\ $$$${lim}_{{x}\rightarrow\frac{.\pi}{\mathrm{2}}} \:\:\frac{−\mathrm{3}{sinx}−\mathrm{15}{sin}\mathrm{3}{x}}{−\mathrm{5}\left(\mathrm{1}+{cot}^{\mathrm{2}} \mathrm{5}{x}\right)}=\frac{−\mathrm{3}+\mathrm{15}}{−\mathrm{5}}=−\frac{\mathrm{12}}{\mathrm{5}} \\…
Question Number 131910 by mathlove last updated on 09/Feb/21 $${A}\:{devided}\:\:\left({x}^{\mathrm{3}} \right)\:\:\:\:{is}\:\:\mathrm{2}\:\:\:\:\:{Reminder}\:{is}\:\:\mathrm{24} \\ $$$${find}\:\:\:{min}\left({A}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 831 by malwaan last updated on 23/Mar/15 $${can}\:{you}\:{solve}\:{the}\:\:{hardest}\:{logic}\:{puzzle}\:{in}\:{the}\:{world} \\ $$ Commented by prakash jain last updated on 24/Mar/15 $$\mathrm{three}\:\mathrm{gods}\:\mathrm{and}\:\mathrm{three}\:\mathrm{questions}? \\ $$ Commented by…
Question Number 830 by prakash jain last updated on 20/Mar/15 $${f}\left({x}\right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{polynomial}\:\mathrm{such}\:\mathrm{that} \\ $$$${f}\left({x}^{\mathrm{2}} \right)={f}\left({x}\right){f}\left({x}−\mathrm{1}\right) \\ $$$$\mathrm{Find}\:{f}\left({x}\right)\:\mathrm{such}\:\mathrm{that}\:{f}\left({x}\right)\neq\mathrm{0}. \\ $$ Commented by 123456 last updated on 23/Mar/15…
Question Number 826 by 123456 last updated on 18/Mar/15 $${x}^{\mathrm{2}} =\underset{{y}=\mathrm{1}} {\overset{{x}} {\sum}}\underset{{z}=\mathrm{0}} {\overset{{y}−\mathrm{1}} {\prod}}\left({y}−{z}\right) \\ $$$${find}\:{x}\in\mathbb{N}^{\ast} \:{such}\:{that}\:{equation}\:{is} \\ $$$${true} \\ $$ Commented by 123456…
Question Number 131893 by SOMEDAVONG last updated on 09/Feb/21 $$\begin{cases}{\mathrm{x}+\mathrm{y}=\sqrt[{\mathrm{3}}]{\mathrm{a}+\mathrm{b}}}\\{\mathrm{x}^{\mathrm{4}} −\mathrm{y}^{\mathrm{4}} =\mathrm{ax}−\mathrm{by}}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 823 by 112358 last updated on 18/Mar/15 $${Solve}\:{the}\:{following}\:{d}.{e}\:{by}\:{using} \\ $$$${v}=\frac{{dy}}{{dx}},\:{where}\:{v}\:{is}\:{a}\:{function}\:{of}\:{x}. \\ $$$${x}^{\mathrm{2}} \frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }−\mathrm{2}\frac{{dy}}{{dx}}+{x}=\mathrm{0} \\ $$ Answered by 123456 last updated on…