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C-z-1-2i-Az-2-2z-A-dz-where-C-is-a-unit-circle-with-radius-1-

Question Number 131743 by frc2crc last updated on 08/Feb/21 $$\underset{{C}:\mid{z}\mid=\mathrm{1}} {\int}\frac{−\mathrm{2}{i}}{{Az}^{\mathrm{2}} +\mathrm{2}{z}+{A}}{dz}\:{where}\:{C}\:{is}\:{a}\:{unit}\:{circle}\:{with}\:{radius}\:\mathrm{1} \\ $$ Answered by mathmax by abdo last updated on 08/Feb/21 $$\mathrm{let}\:\varphi\left(\mathrm{z}\right)=\frac{−\mathrm{2i}}{\mathrm{az}^{\mathrm{2}} \:+\mathrm{2z}+\mathrm{a}}\:\mathrm{poles}\:\mathrm{of}\:\varphi?…

Given-only-the-standard-result-r-1-N-r-2-1-6-N-N-1-2N-1-is-applied-to-determining-the-series-1-2-2-2-2-3-2-2-4-2-5-2-2-6-2-7-2-2-n-1-2-n-2-where-n-is-odd-show-that-it-is-given

Question Number 669 by 112358 last updated on 21/Feb/15 $${Given}\:{only}\:{the}\:{standard}\:{result}\:\underset{{r}=\mathrm{1}} {\overset{{N}} {\sum}}{r}^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{6}}{N}\left({N}+\mathrm{1}\right)\left(\mathrm{2}{N}+\mathrm{1}\right)\: \\ $$$${is}\:{applied}\:{to}\:{determining}\:{the}\:{series} \\ $$$$\mathrm{1}^{\mathrm{2}} +\mathrm{2}×\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +\mathrm{2}×\mathrm{4}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} +\mathrm{2}×\mathrm{6}^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} +…+\mathrm{2}\left({n}−\mathrm{1}\right)^{\mathrm{2}} +{n}^{\mathrm{2}}…

find-the-minimum-distance-between-the-point-1-1-1-and-the-plane-x-2y-3z-6-

Question Number 131733 by LYKA last updated on 07/Feb/21 $$\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{minimum}}\:\boldsymbol{{distance}} \\ $$$$\boldsymbol{{between}}\:\boldsymbol{{the}}\:\boldsymbol{{point}}\:\left(\mathrm{1},\mathrm{1},\mathrm{1}\right)\:{and} \\ $$$$\boldsymbol{{the}}\:\boldsymbol{{plane}}\:\boldsymbol{{x}}+\mathrm{2}\boldsymbol{{y}}+\mathrm{3}\boldsymbol{{z}}=\mathrm{6} \\ $$$$ \\ $$ Answered by physicstutes last updated on 07/Feb/21…

prove-that-n-1-1-2n-1-e-2n-1-pi-e-2n-1-pi-ln-2-16-

Question Number 131732 by mnjuly1970 last updated on 07/Feb/21 $$\:\:\:{prove}\:{that}: \\ $$$$\:\: \\ $$$$\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{2}{n}−\mathrm{1}\right)\left({e}^{\left(\mathrm{2}{n}−\mathrm{1}\right)\pi} −{e}^{−\left(\mathrm{2}{n}−\mathrm{1}\right)\pi} \right)}=\frac{{ln}\left(\mathrm{2}\right)}{\mathrm{16}} \\ $$$$\: \\ $$ Terms of Service…

calculate-the-k-th-order-Taylor-polynomials-T-p-k-f-for-the-following-f-x-e-x-1-x-for-p-1-and-k-5-f-x-y-4sin-x-2-y-for-p-0-0-and-k-4-f-x-y-x-3-2xy-e-xy-for-p-1-1-and-k

Question Number 131735 by LYKA last updated on 07/Feb/21 $${calculate}\:{the}\:{k}-{th}\:{order}\:{Taylor} \\ $$$${polynomials}\:{T}_{{p}} ^{{k}} {f}\:{for}\:{the}\:{following} \\ $$$$ \\ $$$${f}\left({x}\right)=\frac{{e}^{−{x}} }{\mathrm{1}+{x}}\:\:\:{for}\:{p}=−\mathrm{1}\:{and}\:{k}=\mathrm{5} \\ $$$$ \\ $$$${f}\left({x}.{y}\right)=\:\mathrm{4}{sin}\left({x}^{\mathrm{2}} +{y}\right)\:{for}\:{p}=\left(\mathrm{0},\mathrm{0}\right)\:{and} \\…

given-the-function-f-x-y-xy-x-1-y-1-show-that-f-x-y-has-some-0-1-as-a-stationery-point-use-tylor-series-method-to-determine-whether-0-1-is-a-minima-maxima-or-saddle-point-

Question Number 131734 by LYKA last updated on 07/Feb/21 $$\boldsymbol{{given}}\:\boldsymbol{{the}}\:\boldsymbol{{function}} \\ $$$$\:\:\:\:\:\:\:\:\boldsymbol{{f}}\left(\boldsymbol{{x}}.\boldsymbol{{y}}\right)=\boldsymbol{{xy}}\left(\boldsymbol{{x}}−\mathrm{1}\right)\left(\boldsymbol{{y}}−\mathrm{1}\right) \\ $$$$\boldsymbol{{show}}\:\boldsymbol{{that}}\:\boldsymbol{{f}}\left(\boldsymbol{{x}}.\boldsymbol{{y}}\right)\:\boldsymbol{{has}}\:\boldsymbol{{some}}\:\left(\mathrm{0},\mathrm{1}\right) \\ $$$$\boldsymbol{{as}}\:\boldsymbol{{a}}\:\boldsymbol{{stationery}}\:\boldsymbol{{point}} \\ $$$$ \\ $$$$\boldsymbol{{use}}\:\boldsymbol{{tylor}}\:\boldsymbol{{series}}\:\boldsymbol{{method}}\:\boldsymbol{{to}}\: \\ $$$$\boldsymbol{{determine}}\:\boldsymbol{{whether}}\:\left(\mathrm{0}.\mathrm{1}\right)\:\boldsymbol{{is}}\:\boldsymbol{{a}} \\ $$$$\boldsymbol{{minima}}\:,\boldsymbol{{maxima}}\:\boldsymbol{{or}}\:\boldsymbol{{saddle}}\: \\…