Question Number 132117 by aurpeyz last updated on 11/Feb/21 $${Express}\:{P}=\left(\mathrm{6}{N}\:\mathrm{060}^{\mathrm{0}} \right)\:{in}\:{the}\:{form} \\ $$$${ai}+{sj}\:{where}\:{a}\:{and}\:{s}\:{are}\:{scalers}. \\ $$$$\left({a}\right)\:\mathrm{3}\sqrt{\mathrm{3}}{i}+\mathrm{3}{j}\:\left({b}\right)\:\mathrm{3}\sqrt{\mathrm{3}}{i}−\mathrm{3}{j}\:\left({c}\right)\:\mathrm{3}{i}+\mathrm{3}{j} \\ $$$$\left({d}\right)\:\mathrm{3}{i}−\mathrm{3}{j} \\ $$ Commented by aurpeyz last updated on…
Question Number 1047 by 112358 last updated on 23/May/15 $${Simplify}\:{the}\:{following} \\ $$$${expression}\:{using}\:{the}\:{laws}\:{of}\: \\ $$$${Boolean}\:{algebra}: \\ $$$$\left({x}\wedge\backsim{y}\right)\vee\left(\backsim{y}\wedge\backsim{z}\right)\vee\left(\backsim{x}\wedge\backsim{z}\right)\:. \\ $$$$ \\ $$ Commented by prakash jain last…
Question Number 132116 by aurpeyz last updated on 11/Feb/21 $${find}\:{the}\:{magnitude}\:{and}\:{direction}\:{of} \\ $$$${the}\:{vector}\:{r}=\mathrm{3}{i}−\mathrm{4}{j}\:{to}\:{the}\:{nearest}\: \\ $$$${degree} \\ $$$$\left({a}\right)\:\mathrm{7}{N}\:\mathrm{143}^{\mathrm{0}} \:\left({b}\right)\:\mathrm{5}{N}\:\mathrm{143}^{\mathrm{0}} \:\left({c}\right)\:\mathrm{5}{N}\:\mathrm{127}^{\mathrm{0}} \\ $$$$\left({d}\right)\:\mathrm{7}{N}\:\mathrm{127}^{\mathrm{0}} \\ $$ Answered by Olaf…
Question Number 132119 by Hamid52 last updated on 11/Feb/21 $$\begin{cases}{ {x}+ {y}= }\\{ {x}− {y}= }\end{cases} \\ $$$$ \\ $$ Answered by Raxreedoroid last updated…
Question Number 1041 by tera last updated on 22/May/15 $${if}\:{the}\:{roots}\:{of}\:{the}\:{equation}\:{ax}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{2}=\mathrm{0}\:{is}\:\mathrm{2}\:{and}\:{b}. \\ $$$$ \\ $$$${then}\:\mathrm{4}{a}^{\mathrm{2}} −\mathrm{4}{ab}+{b}^{\mathrm{2}} =… \\ $$ Answered by prakash jain last updated…
Question Number 1039 by tera last updated on 22/May/15 $${jumlah}\:{akar}−{akar}\:{persamaan}\:\left[{x}\right]^{\mathrm{2}} −\mathrm{2}\left[{x}\right]−\mathrm{3}=\mathrm{0}\:{sama}\:{dengan} \\ $$$${a}.−\mathrm{10}\:\:\:\:\:\:\:\:\:\:{b}.−\mathrm{3}\:\:\:\:\:\:{e}.\mathrm{4} \\ $$$${c}.−\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:{d}.\mathrm{0} \\ $$ Commented by prakash jain last updated on 22/May/15…
Question Number 132110 by Raxreedoroid last updated on 11/Feb/21 $$\int\frac{\mathrm{1}}{\mathrm{ln}\:{x}}{dx}=? \\ $$ Answered by Olaf last updated on 11/Feb/21 $$\mathrm{F}\left({x}\right)\:=\:\int\frac{{dx}}{\mathrm{ln}{x}} \\ $$$$\mathrm{Let}\:{x}\:=\:{e}^{{u}} \\ $$$$\mathrm{F}\left({e}^{{u}} \right)\:=\:\int\frac{{d}\left({e}^{{u}}…
Question Number 132104 by mnjuly1970 last updated on 11/Feb/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…\:{calculus}\:\left(\mathrm{1}\right)… \\ $$$$\:\:{if}\:\:{y}=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{{sin}\left({x}\right)+{cos}\left({x}\right)}}\:\:{then}\:: \\ $$$$\:\:\:\:\mathrm{3}{y}''−\mathrm{12}\left({y}'\right)^{\mathrm{2}} −{y}^{\mathrm{2}} =\:??? \\ $$$$\:\:\:\:\:……… \\ $$ Answered by mnjuly1970 last updated…
Question Number 1034 by 123456 last updated on 21/May/15 $${x}={i}+{f},{i}\in\mathbb{N},{f}\in\left[\mathrm{0},\mathrm{1}\right) \\ $$$${x}^{\mathrm{2}} =\left({i}+{f}\right)^{\mathrm{2}} ={i}^{\mathrm{2}} +\mathrm{2}{if}+{f}^{\mathrm{2}} \\ $$$${x}\in\mathbb{R}_{+} \\ $$$${i}+\mathrm{2}{f}=\mathrm{2}\Rightarrow{x}^{\mathrm{2}} =\mathrm{2}{i}+{f}^{\mathrm{2}} \\ $$$$\mathrm{2}{if}=\mathrm{0}\Rightarrow{x}^{\mathrm{2}} ={i}^{\mathrm{2}} +{f}^{\mathrm{2}} \\…
Question Number 132107 by weltr last updated on 11/Feb/21 $$\left({arcsin}\mid\mathrm{ln}^{\mathrm{3}} \left({cot}\mathrm{4}\:−\:{x}\right)\mid\:+\:\mathrm{4}!\right)^{\frac{\mathrm{1}}{\mathrm{19}}} \:=\:\mathrm{5} \\ $$ Answered by Olaf last updated on 11/Feb/21 $$\left(\mathrm{arcsin}\mid\mathrm{ln}^{\mathrm{3}} \left(\mathrm{cot4}−{x}\right)\mid+\mathrm{4}!\right)^{\frac{\mathrm{1}}{\mathrm{19}}} \:=\:\mathrm{5} \\…