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Author: Tinku Tara

Use-the-definition-of-the-limit-of-a-function-to-prove-that-lim-x-y-0-0-x-4-y-4-x-2-y-2-0-

Question Number 4596 by Yozzii last updated on 10/Feb/16 $${Use}\:{the}\:{definition}\:{of}\:{the}\:{limit}\:{of}\:{a}\:{function} \\ $$$${to}\:{prove}\:{that}\:\underset{\left({x},{y}\right)\rightarrow\left(\mathrm{0},\mathrm{0}\right)} {\mathrm{lim}}\frac{{x}^{\mathrm{4}} +{y}^{\mathrm{4}} }{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }=\mathrm{0}. \\ $$ Terms of Service Privacy Policy Contact:…

4x-2-5-2x-2-4-dx-x-0-

Question Number 4594 by alimyao last updated on 10/Feb/16 $$\int\mathrm{4}{x}^{\mathrm{2}} \:−\:\frac{\mathrm{5}}{\mathrm{2}{x}^{−\mathrm{2}} }\:+\:\mathrm{4}\:\:{dx},\:{x}\neq\mathrm{0} \\ $$$$ \\ $$ Answered by FilupSmith last updated on 10/Feb/16 $$=\mathrm{4}\int{x}^{\mathrm{2}} {dx}−\frac{\mathrm{5}}{\mathrm{2}}\int{x}^{\mathrm{2}}…

L-lim-i-1-i-1-i-i-1-L-

Question Number 4587 by FilupSmith last updated on 09/Feb/16 $${L}=\underset{{i}\rightarrow\infty} {\mathrm{lim}}\:\frac{\left(−\mathrm{1}\right)^{{i}+\mathrm{1}} {i}}{{i}+\mathrm{1}} \\ $$$${L}=? \\ $$ Commented by Yozzii last updated on 14/Feb/16 $${L}\:{does}\:{not}\:{exist}.\:{While}\:\mid{L}\mid=\underset{{i}\rightarrow\infty} {\mathrm{lim}}\frac{{i}}{{i}+\mathrm{1}}…

500-108-54-and-15-are-are-not-perfect-cubes-how-do-we-factorize-1-500X-3-108Y-3-2-54X-3-15Y-3-please-help-me-with-well-explained-steps-or-shortcut-thanks-

Question Number 135656 by otchereabdullai@gmail.com last updated on 14/Mar/21 $$\mathrm{500},\:\mathrm{108},\mathrm{54}\:\mathrm{and}\:\mathrm{15}\:\mathrm{are}\:\mathrm{are}\:\mathrm{not}\: \\ $$$$\mathrm{perfect}\:\mathrm{cubes}\:\mathrm{how}\:\mathrm{do}\:\mathrm{we}\:\mathrm{factorize} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{500X}^{\mathrm{3}} −\mathrm{108Y}^{\mathrm{3}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{54X}^{\mathrm{3}} +\mathrm{15Y}^{\mathrm{3}} \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{well}\:\mathrm{explained}\: \\ $$$$\mathrm{steps}\:\mathrm{or}\:\mathrm{shortcut}\:\mathrm{thanks} \\ $$ Commented…

Question-70121

Question Number 70121 by ahmadshahhimat775@gmail.com last updated on 01/Oct/19 Answered by mind is power last updated on 01/Oct/19 $${let}\:{a}\:{angle}\:{left}\:−,{c}\:{side}\:{of}\:{squar} \\ $$$$\Rightarrow{c}=\mathrm{6}{sin}\left({a}\right) \\ $$$$\frac{\mathrm{6}{sin}\left({a}\right)+\mathrm{6}{cos}\left({a}\right)}{{sin}\left(\mathrm{45}\right)}=\frac{\mathrm{10}}{{sin}\left(\mathrm{45}+{a}\right)} \\ $$$$\Rightarrow\mathrm{6}.\left({sin}\left({a}\right)+{cos}\left({a}\right)\right).{sin}\left(\mathrm{45}+{a}\right)=\mathrm{10}{sin}\left(\mathrm{45}\right)…