Question Number 131925 by mathlove last updated on 09/Feb/21 Commented by kaivan.ahmadi last updated on 09/Feb/21 $$\mathrm{2}{x}^{\mathrm{3}} +\mathrm{24}={A} \\ $$$${x}^{\mathrm{3}} >\mathrm{24}\Rightarrow{min}\left({x}^{\mathrm{3}} \right)=\mathrm{25} \\ $$$$\Rightarrow{min}\left({A}\right)=\mathrm{2}\left(\mathrm{25}\right)+\mathrm{24}=\mathrm{74} \\…
Question Number 855 by 112358 last updated on 26/Mar/15 $${Find}\:{the}\:{number}\:{of}\:{terms}\:{in} \\ $$$$\left(\mathrm{1}+{x}\right)^{\mathrm{101}} \left(\mathrm{1}+{x}^{\mathrm{2}} −{x}\right)^{\mathrm{100}} . \\ $$ Answered by prakash jain last updated on 26/Mar/15…
Question Number 131924 by aurpeyz last updated on 09/Feb/21 $${is}\:{there}\:{any}\:{diffrence}\:{btw}\:\mathrm{060}\:{and}\:\mathrm{60}^{\mathrm{0}} \\ $$ Answered by physicstutes last updated on 10/Feb/21 $$\mathrm{I}\:\mathrm{think}:\:\mathrm{one}\:\mathrm{just}\:\mathrm{specifies}\:\mathrm{that}\:\mathrm{you}'\mathrm{ve}\:\mathrm{taken}\:\mathrm{it}\:\mathrm{clockwise} \\ $$$$\mathrm{from}\:\mathrm{0}°\:\mathrm{to}\:\mathrm{60}°\:\mathrm{while}\:\mathrm{the}\:\mathrm{other}\:\mathrm{doesn}'\mathrm{t} \\ $$$$\mathrm{60}°\:\mathrm{could}\:\mathrm{mean}\:\mathrm{clockwise}\:\mathrm{or}\:\mathrm{counter}\:\mathrm{clockwise}\:\mathrm{but}\:\mathrm{if}\:\mathrm{you}\:\mathrm{mean} \\…
Question Number 854 by 123456 last updated on 26/Mar/15 $$\mathrm{there}\:\mathrm{a}\:\mathrm{room}\:\mathrm{with}\:\mathrm{3}\:\mathrm{doors},\:\mathrm{only}\:\mathrm{one} \\ $$$$\mathrm{to}\:\mathrm{exit},\:\mathrm{there}\:\mathrm{are}\:\mathrm{one}\:\mathrm{people},\:\mathrm{you}\:\mathrm{can} \\ $$$$\mathrm{talk}\:\mathrm{to}\:\mathrm{her}\:\mathrm{3}\:\mathrm{question}\:\mathrm{and}\:\mathrm{he}\:\mathrm{only}\:\mathrm{will} \\ $$$$\mathrm{answer}\:\mathrm{you}\:\mathrm{truth}\:\mathrm{in}\:\mathrm{only}\:\mathrm{one}\:\mathrm{question} \\ $$$$\mathrm{talking}\:\mathrm{a}\:\mathrm{lie}\:\mathrm{in}\:\mathrm{the}\:\mathrm{other}\:\mathrm{two}\:\mathrm{question}, \\ $$$$\mathrm{but}\:\mathrm{you}\:\mathrm{dont}\:\mathrm{know}\:\mathrm{what}\:\mathrm{the}\:\mathrm{question} \\ $$$$\mathrm{wich}\:\mathrm{he}\:\mathrm{sayed}\:\mathrm{the}\:\mathrm{truth},\:\mathrm{how}\:\mathrm{a}\:\mathrm{people} \\ $$$$\mathrm{exit}\:\mathrm{this}\:\mathrm{room}\:\mathrm{if}\:\mathrm{possible}? \\…
Question Number 850 by sagarwal last updated on 25/Mar/15 $$\mathrm{Solve}\:\mid\mathrm{2}{x}+\mathrm{4}\mid\geqslant\mathrm{14} \\ $$ Answered by 123456 last updated on 25/Mar/15 $$\mid\mathrm{2}{x}+\mathrm{4}\mid\geqslant\mathrm{14} \\ $$$$\mathrm{2}{x}+\mathrm{4}\leqslant−\mathrm{14}\vee\mathrm{2}{x}+\mathrm{4}\geqslant\mathrm{14} \\ $$$$\mathrm{2}{x}\leqslant−\mathrm{18}\vee\mathrm{2}{x}\geqslant\mathrm{10} \\…
Question Number 848 by 123456 last updated on 25/Mar/15 $$\mathrm{in}\:\mathrm{a}\:\mathrm{street}\:\mathrm{was}\:\mathrm{two}\:\mathrm{way}\:\mathrm{road}\:\mathrm{that}\:\mathrm{leads}\:\mathrm{to} \\ $$$$\mathrm{city}\:\mathrm{A}\:\mathrm{and}\:\mathrm{city}\:\mathrm{B},\:\mathrm{at}\:\mathrm{the}\:\mathrm{street}\:\mathrm{you}\:\mathrm{find} \\ $$$$\mathrm{two}\:\mathrm{people},\:\mathrm{one}\:\mathrm{lie}\:\mathrm{and}\:\mathrm{one}\:\mathrm{tell}\:\mathrm{truth} \\ $$$$\mathrm{if}\:\mathrm{you}\:\mathrm{can}\:\mathrm{talk}\:\mathrm{one}\:\mathrm{question}\:\mathrm{to}\:\mathrm{each} \\ $$$$\mathrm{people}\:\mathrm{only},\:\mathrm{how}\:\mathrm{you}\:\mathrm{go}\:\mathrm{to}\:\mathrm{city}\:\mathrm{A}? \\ $$ Answered by prakash jain last…
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Question Number 66382 by ajfour last updated on 13/Aug/19 $${Give}\:{me}\:{any}\:{Quintic},\:{i}\:{shall}\:{solve} \\ $$$${it}.\:{For}\:{sure}! \\ $$$${At}^{\mathrm{5}} +{Bt}^{\mathrm{4}} +{Ct}^{\mathrm{3}} +{Dt}^{\mathrm{2}} +{Et}+{F}=\mathrm{0} \\ $$$${wont}\:{even}\:{assume}\:{A}=\mathrm{1},\:{or}\:{B}=\mathrm{0}. \\ $$$${but}\:{if}\:{A}+{C}+{E}={B}+{D}+{F}\: \\ $$$${then}\:{my}\:{formula}\:{dont}\:{work} \\…
Question Number 131919 by Algoritm last updated on 09/Feb/21 Answered by Dwaipayan Shikari last updated on 09/Feb/21 $${x}={u}^{\mathrm{6}} \\ $$$$=\mathrm{6}\int\frac{{u}^{\mathrm{5}} }{{u}^{\mathrm{2}} +{u}^{\mathrm{3}} }{du}=\mathrm{6}\int\frac{{u}^{\mathrm{3}} }{{u}+\mathrm{1}}{du}=\mathrm{6}\int\left({u}^{\mathrm{2}} −{u}+\mathrm{1}\right){du}−\mathrm{6}{log}\left({u}\right)…
Question Number 66381 by aliesam last updated on 13/Aug/19 Terms of Service Privacy Policy Contact: info@tinkutara.com