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Author: Tinku Tara

Find-the-first-four-terms-in-the-series-expansion-of-1-3x-5-ascending-power-x-and-state-the-set-of-values-of-x-for-which-this-expansion-is-valid-

Question Number 131054 by benjo_mathlover last updated on 01/Feb/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{first}\:\mathrm{four}\:\mathrm{terms}\:\mathrm{in}\:\mathrm{the}\:\mathrm{series}\: \\ $$$$\mathrm{expansion}\:\mathrm{of}\:\frac{\mathrm{1}}{\mathrm{3x}+\mathrm{5}}\:\mathrm{ascending}\:\mathrm{power} \\ $$$$\mathrm{x}\:\mathrm{and}\:\mathrm{state}\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of}\:\mathrm{x}\:\mathrm{for} \\ $$$$\mathrm{which}\:\mathrm{this}\:\mathrm{expansion}\:\mathrm{is}\:\mathrm{valid}\:. \\ $$ Answered by EDWIN88 last updated on 01/Feb/21…

x-2-2-x-4-4-dx-

Question Number 131053 by pipin last updated on 01/Feb/21 $$\int\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2}}{\mathrm{x}^{\mathrm{4}} +\mathrm{4}}\mathrm{dx} \\ $$ Answered by Ar Brandon last updated on 01/Feb/21 $$\mathcal{I}=\int\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{2}}{\mathrm{x}^{\mathrm{4}} +\mathrm{4}}\mathrm{dx}=\int\frac{\mathrm{1}+\frac{\mathrm{2}}{\mathrm{x}^{\mathrm{2}}…

let-f-x-0-tsin-xt-x-2-t-2-2-dt-x-gt-0-calculate-f-x-

Question Number 131050 by mathmax by abdo last updated on 31/Jan/21 $$\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)=\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{tsin}\left(\mathrm{xt}\right)}{\left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{t}^{\mathrm{2}} \right)^{\mathrm{2}} }\mathrm{dt}\:\:\:\left(\mathrm{x}>\mathrm{0}\right) \\ $$$$\mathrm{calculate}\:\mathrm{f}^{'} \left(\mathrm{x}\right) \\ $$ Answered by mathmax…

let-f-x-0-cos-xt-x-2-t-2-dt-calculate-0-1-f-x-dx-

Question Number 131049 by mathmax by abdo last updated on 31/Jan/21 $$\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)=\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{cos}\left(\mathrm{xt}\right)}{\mathrm{x}^{\mathrm{2}} \:+\mathrm{t}^{\mathrm{2}} }\mathrm{dt}\:\:\mathrm{calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{f}\left(\mathrm{x}\right)\mathrm{dx} \\ $$ Answered by mindispower last updated…

lim-x-0-x-tan-x-x-tan-2-x-

Question Number 131033 by greg_ed last updated on 31/Jan/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}−\mathrm{tan}\:{x}}{{x}\:\mathrm{tan}^{\mathrm{2}} {x}}\:=\:? \\ $$ Commented by greg_ed last updated on 02/Feb/21 $$\boldsymbol{\mathrm{without}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{limited}}\:\boldsymbol{\mathrm{development}}\:\boldsymbol{\mathrm{method}}\:! \\ $$ Answered…

a-b-b-a-b-3-b-a-a-a-b-2-a-b-R-

Question Number 65495 by behi83417@gmail.com last updated on 30/Jul/19 $$\begin{cases}{\frac{\boldsymbol{\mathrm{a}}}{\boldsymbol{\mathrm{b}}}+\frac{\boldsymbol{\mathrm{b}}}{\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}}=\sqrt{\mathrm{3}}}\\{\frac{\boldsymbol{\mathrm{b}}}{\boldsymbol{\mathrm{a}}}+\frac{\boldsymbol{\mathrm{a}}}{\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}}=\sqrt{\mathrm{2}}}\end{cases}\:\:\:\left[\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}}\in\boldsymbol{\mathrm{R}}\right] \\ $$ Answered by MJS last updated on 31/Jul/19 $${b}={at} \\ $$$$\begin{cases}{\frac{{t}^{\mathrm{2}} +{t}+\mathrm{1}}{{t}\left({t}+\mathrm{1}\right)}=\sqrt{\mathrm{3}}}\\{\frac{{t}^{\mathrm{2}} +{t}+\mathrm{1}}{{t}+\mathrm{1}}=\sqrt{\mathrm{2}}}\end{cases} \\…