Question Number 65492 by Masumsiddiqui399@gmail.com last updated on 30/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 65491 by mr W last updated on 30/Jul/19 Commented by mr W last updated on 30/Jul/19 $$\left[{Q}\mathrm{65312}\:{reposted}\right] \\ $$$${find}\:{x}=? \\ $$ Answered by…
Question Number 131027 by Algoritm last updated on 31/Jan/21 Answered by mathmax by abdo last updated on 31/Jan/21 $$\mathrm{cos}^{\mathrm{2m}} \mathrm{x}\:=\left(\frac{\mathrm{e}^{\mathrm{ix}} +\mathrm{e}^{−\mathrm{ix}} }{\mathrm{2}}\right)^{\mathrm{2m}} \:=\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2m}} }\sum_{\mathrm{k}=\mathrm{0}} ^{\mathrm{2m}}…
Question Number 65490 by Masumsiddiqui399@gmail.com last updated on 30/Jul/19 Commented by mathmax by abdo last updated on 31/Jul/19 $${hospital}\:{method}\:\:{let}\:{u}\left({x}\right)\:={ln}\left({x}\right)\:{and}\:{v}\left({x}\right)={cos}\left(\frac{\pi}{\mathrm{2}^{{x}} }\right) \\ $$$${we}\:{have}\:{lim}_{{x}\rightarrow\mathrm{1}} {u}\left({x}\right)={lim}_{{x}\rightarrow\mathrm{1}} {v}\left({x}\right)\:=\mathrm{0} \\…
Question Number 65489 by mathmax by abdo last updated on 30/Jul/19 $${U}_{{n}} \:{is}\:{a}\:{sequence}\:{wich}\:{verify}\:\:{U}_{{n}} \:+{U}_{{n}+\mathrm{1}} =\frac{\mathrm{1}}{{n}^{\mathrm{2}} } \\ $$$$\left.\mathrm{1}\right)\:{find}\:{U}_{{n}} \:{interms}\:{of}\:{n} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{lim}_{{n}\rightarrow+\infty} \:{U}_{{n}} \\ $$ Commented…
Question Number 65488 by mathmax by abdo last updated on 30/Jul/19 $${U}_{{n}} {is}\:{a}\:{sequence}\:{wich}\:{verify}\:\:\forall{n}\in{N}^{\bigstar} \\ $$$${U}_{{n}} \:+{U}_{{n}+\mathrm{1}} =\frac{\mathrm{1}}{{n}} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:\:{U}_{{n}} \:{interms}\:{of}\:{n} \\ $$$$\left.\mathrm{2}\right)\:{is}\:{the}\:{sequence}\:{U}_{{n}} {convergent}? \\ $$…
Question Number 65486 by aliesam last updated on 30/Jul/19 Answered by MJS last updated on 31/Jul/19 $$\int\mathrm{arctan}\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} −{x}+\mathrm{1}}\:{dx}= \\ $$$$\:\:\:\:\:{u}'=\mathrm{1}\:\rightarrow\:{u}={x} \\ $$$$\:\:\:\:\:{v}=\mathrm{arctan}\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} −{x}+\mathrm{1}}\:\rightarrow\:{v}'=−\frac{\mathrm{2}{x}−\mathrm{1}}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{2}\right)}…
Question Number 65485 by aliesam last updated on 30/Jul/19 $$\int{e}^{{cos}^{−\mathrm{1}} \left({x}\right)} \:{dx} \\ $$ Answered by MJS last updated on 31/Jul/19 $$\int\mathrm{e}^{\mathrm{arccos}\:{x}} {dx}= \\ $$$$\:\:\:\:\:\left[{t}=\mathrm{arccos}\:{x}\:\rightarrow\:{dx}=−\mathrm{sin}\:{t}\:{dt}\right]…
Question Number 131021 by mohammad17 last updated on 31/Jan/21 $${solve} \\ $$$$ \\ $$$$\left(\mathrm{1}\right):\left(\mathrm{1}+{i}\right)^{{i}} \\ $$$$ \\ $$$$\left(\mathrm{2}\right):\:{log}\left(\mathrm{1}+{i}\right)^{\pi{i}} \\ $$ Answered by Dwaipayan Shikari last…
Question Number 131016 by ajfour last updated on 31/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com