Question Number 65480 by ajfour last updated on 30/Jul/19 $${x}^{\mathrm{4}} −\mathrm{15}{x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{24}=\mathrm{0}\:\:\: \\ $$$${solve}\:{for}\:{x}. \\ $$ Commented by Prithwish sen last updated on 30/Jul/19 $$\mathrm{x}^{\mathrm{3}}…
Question Number 65478 by smz last updated on 30/Jul/19 Commented by MJS last updated on 31/Jul/19 $$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{it}'\mathrm{s}\:\mathrm{possible} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 131012 by mohammad17 last updated on 31/Jan/21 Commented by mohammad17 last updated on 31/Jan/21 $${help}\:{me}\:{sir} \\ $$ Answered by mr W last updated…
Question Number 131010 by Boucatchou last updated on 31/Jan/21 $$\:\:\:\:\:\:{Determine}\:\:{integers}\:\:{a},\:{b}\:{such}\:{that}\:\:\begin{cases}{{a}+{b}=\mathrm{182}}\\{{a}\vee{b}=\mathrm{13}}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 65473 by Tawa1 last updated on 30/Jul/19 Commented by mathmax by abdo last updated on 30/Jul/19 $${let}\:\:{A}\left({x}\right)\:=\sqrt{\frac{{x}^{\mathrm{3}} −\mathrm{1}}{{x}+\mathrm{1}}}−^{\mathrm{3}} \sqrt{\frac{{x}^{\mathrm{5}} +\mathrm{1}}{{x}^{\mathrm{2}} −\mathrm{2}{x}}}\:\Rightarrow{for}\:{x}>\mathrm{0} \\ $$$${A}\left({x}\right)\:=\sqrt{\frac{{x}^{\mathrm{3}}…
Question Number 65472 by Masumsiddiqui399@gmail.com last updated on 30/Jul/19 $$ \\ $$$$ \\ $$$$\:\:\:{solve}\:\: \\ $$$$\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left[\left(\mathrm{2}+{x}\right)^{{n}} −\mathrm{2}^{{n}} \right]}{{x}} \\ $$$$ \\ $$ Commented by…
Question Number 131006 by Study last updated on 31/Jan/21 $${if}\:{a}_{\mathrm{1}} =\frac{\mathrm{4}{n}+\mathrm{3}}{\mathrm{2}{n}−\mathrm{1}}\:\:\:\:\:\:,\:\:\:{a}_{\mathrm{10}} =\frac{\mathrm{6}{n}+\mathrm{5}}{\mathrm{2}{n}−\mathrm{1}}\:\:\:\:;\:\:\:{a}_{\mathrm{30}} =? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 131007 by Study last updated on 31/Jan/21 $$\frac{{d}}{{dx}}\left(\infty\right)=?\:\:\:\:\:{or}\:\:\:\left(\infty\right)'=? \\ $$ Answered by Boucatchou last updated on 31/Jan/21 $$\infty\:{is}\:{unknown},\:{so}\:\:{they}\:\:{can}'{t}\:\:{do}\:\:{such}\:\:{operations}.. \\ $$ Answered by MJS_new…
Question Number 131004 by Algoritm last updated on 31/Jan/21 Commented by Algoritm last updated on 31/Jan/21 $$\mathrm{prove}\:\mathrm{that} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 65468 by $@ty@m123 last updated on 30/Jul/19 $${To} \\ $$$${The}\:{app}\:{developer}\:{Tinkutara}…. \\ $$$${I}\:{cannot}\:{use}\:{the}\:{bottom}\:{line} \\ $$$${features}\:{of}\:{this}\:{app}. \\ $$$${Kindly}\:{resolve}\:{this}\:{issue}. \\ $$ Commented by $@ty@m123 last updated…