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Author: Tinku Tara

Question-224150

Question Number 224150 by behi834171 last updated on 23/Aug/25 Commented by behi834171 last updated on 23/Aug/25 $$\boldsymbol{{x}};\:\boldsymbol{{in}}\:\boldsymbol{{terms}}\:\boldsymbol{{of}}:\:\left(\boldsymbol{{a}}\:\boldsymbol{{and}}\:\boldsymbol{{b}}\right)\in\boldsymbol{{R}} \\ $$ Commented by Ghisom_ last updated on…

Question-224144

Question Number 224144 by mr W last updated on 23/Aug/25 Commented by mr W last updated on 23/Aug/25 $${find}\:{the}\:{normal}\:{force}\:\boldsymbol{{N}}\:{between}\: \\ $$$${two}\:{solid}\:{cylinders}\:{with}\:{masses} \\ $$$$\boldsymbol{{m}}_{\mathrm{1}} ,\:\boldsymbol{{m}}_{\mathrm{2}} \:{and}\:{radii}\:\boldsymbol{{r}}_{\mathrm{1}}…

a-12-223-7-56-19-25-what-is-the-last-digit-of-the-number-

Question Number 224146 by hardmath last updated on 22/Aug/25 $$\boldsymbol{\mathrm{a}}\:=\:\mathrm{12}^{\mathrm{223}} \:\centerdot\:\mathrm{7}^{\mathrm{56}} \:+\:\mathrm{19}^{\mathrm{25}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{of}\:\mathrm{the}\:\mathrm{number}? \\ $$ Answered by Ghisom_ last updated on 23/Aug/25 $$\mathrm{12}^{\mathrm{223}} \:\mathrm{has}\:\mathrm{the}\:\mathrm{same}\:\mathrm{last}\:\mathrm{digit}\:\mathrm{as}\:\mathrm{2}^{\mathrm{223}}…

2-2-x-3-cos-x-2-1-2-4-x-2-

Question Number 224124 by klipto last updated on 21/Aug/25 $$\int_{−\mathrm{2}} ^{\mathrm{2}} \frac{\boldsymbol{\mathrm{x}}^{\mathrm{3}} \boldsymbol{\mathrm{cos}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)+\frac{\mathrm{1}}{\mathrm{2}}}{\:\sqrt{\mathrm{4}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} }} \\ $$ Answered by klipto last updated on 21/Aug/25 $$ \\…

Question-224108

Question Number 224108 by MirHasibulHossain last updated on 21/Aug/25 Answered by mr W last updated on 21/Aug/25 $${i}\:{think}\:{if}\:{the}\:{three}\:{big}\:{blue}\:{circles}\: \\ $$$${have}\:{different}\:{radii}\:{a}_{\mathrm{1}} ,\:{a}_{\mathrm{2}} ,\:{a}_{\mathrm{3}} ,\: \\ $$$${generally}\:{we}\:{have}…

Question-224121

Question Number 224121 by fantastic last updated on 21/Aug/25 Answered by mr W last updated on 21/Aug/25 $${R}=\frac{\mathrm{1}}{\mathrm{2}\sqrt{\frac{\mathrm{1}}{\mathrm{10}×\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}×\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}×\mathrm{10}}}−\frac{\mathrm{1}}{\mathrm{10}}−\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{2}}}=\mathrm{15} \\ $$$$\pi{R}^{\mathrm{2}} =\mathrm{225}\pi\:\checkmark \\ $$ Commented by…

Question-224122

Question Number 224122 by fantastic last updated on 21/Aug/25 Commented by fantastic last updated on 21/Aug/25 $${Three}\:{circles}\:{in}\:{a}\:{big}\:{circle} \\ $$$${A}\:{pointed}\:{circle}\:{r}_{\mathrm{1}} \\ $$$${B}\:{pointed}\:{circle}\:{r}_{\mathrm{2}} \\ $$$${C}\:{pointed}\:{circle}\:{r}_{\mathrm{3}} \\ $$$${R}=?…