Question Number 65189 by arcana last updated on 26/Jul/19 $${all}\:{square}\:{is}\:{a}\:{rhombus}.\:{why}? \\ $$ Answered by MJS last updated on 26/Jul/19 $$\mathrm{a}\:\mathrm{rhombus}\:\mathrm{has}\:\mathrm{2}\:\mathrm{parallel}\:\mathrm{pairs}\:\mathrm{of}\:\mathrm{sides},\:\mathrm{all} \\ $$$$\mathrm{of}\:\mathrm{them}\:\mathrm{of}\:\mathrm{equal}\:\mathrm{length} \\ $$$$\mathrm{a}\:\mathrm{square}\:\mathrm{is}\:\mathrm{a}\:\mathrm{special}\:\mathrm{kind}\:\mathrm{of}\:\mathrm{rhombus} \\…
Question Number 130725 by mathmax by abdo last updated on 28/Jan/21 $$\mathrm{find}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{\mathrm{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{x}^{\mathrm{4}} +\mathrm{1}}}\mathrm{dx} \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 130719 by SLVR last updated on 28/Jan/21 $$ \\ $$ Commented by SLVR last updated on 28/Jan/21 Commented by SLVR last updated on…
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Question Number 130714 by greg_ed last updated on 28/Jan/21 $$\left.{f}\left.\::\:\right]\mathrm{0}\:,\:\pi\right]\:\rightarrow\:\left[\mathrm{0}\:,\:\mathrm{1}\right] \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{x}\:\:\:\: \:\:\:\mathrm{sin}\:{x} \\ $$$${f}\:\:\mathrm{injective}\:?\:{f}\:\mathrm{surjective}\:?\:{f}\:\mathrm{bijective}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130713 by harckinwunmy last updated on 28/Jan/21 Commented by EDWIN88 last updated on 28/Jan/21 $${ans}:\:{B} \\ $$ Answered by EDWIN88 last updated on…
Question Number 65170 by Rio Michael last updated on 25/Jul/19 $${three}\:{forces}\:{F}_{\mathrm{1}} ,\:{F}_{\mathrm{2}} \:{and}\:{F}_{\mathrm{3}} \:{acts}\:{through}\:{the}\:{points}\:{with}\:{position}\:{vectors} \\ $$$$\boldsymbol{{r}}_{\mathrm{1}} ,{r}_{\mathrm{2}} \:{and}\:{r}_{\mathrm{3}} \:{respectively}\:{where} \\ $$$$\:{F}_{\mathrm{1}} \:=\left(\mathrm{3}{i}\:−\mathrm{2}{j}−\mathrm{4}{k}\right){N},\:\:\:{r}_{\mathrm{1}} =\:\left({i}\:+{k}\right){m} \\ $$$${F}_{\mathrm{2}}…
Question Number 65168 by Rio Michael last updated on 25/Jul/19 $${z}\:=\:\mathrm{1}−\:\mathrm{i}\sqrt{\mathrm{3}} \\ $$$${express}\:{z}\:{in}\:{the}\:{form}\:\:{r}\left({cos}\theta\:+\mathrm{i}{sin}\theta\right)\:{also}\:{express}\:{z}^{\mathrm{7}} \:{in}\:{the}\:{form} \\ $$$${re}^{\mathrm{i}\theta} . \\ $$ Answered by mr W last updated…
Question Number 65166 by Rio Michael last updated on 25/Jul/19 $${Given}\:{that}\:\:{f}\left({x}\right)\:=\:\frac{\mathrm{2}}{{x}^{\mathrm{2}} −\mathrm{1}} \\ $$$$\left.{a}\right)\:{Express}\:{f}\left({x}\right)\:{in}\:{partial}\:{fraction}. \\ $$$${b}.{Evaluate}\:\:\int_{\mathrm{3}} ^{\mathrm{5}} {f}\:\left({x}\right)\:{dx} \\ $$ Commented by mathmax by abdo…
Question Number 130701 by mohammad17 last updated on 28/Jan/21 Answered by mathmax by abdo last updated on 28/Jan/21 $$\left.\mathrm{2}\right)\mathrm{f}\left(\mathrm{x},\mathrm{y}\right)=\mathrm{x}^{\mathrm{4}} \:\mathrm{y}^{\mathrm{4}} \:\mathrm{arcsin}\left(\frac{\mathrm{y}}{\mathrm{x}}\right)\:\Rightarrow\frac{\partial\mathrm{f}}{\partial\mathrm{x}}=\mathrm{4x}^{\mathrm{3}} \mathrm{y}^{\mathrm{4}} \:\mathrm{arcsin}\left(\frac{\mathrm{y}}{\mathrm{x}}\right) \\ $$$$+\mathrm{x}^{\mathrm{4}}…