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Author: Tinku Tara

Question-65113

Question Number 65113 by rajesh4661kumar@gamil.com last updated on 25/Jul/19 Commented by Prithwish sen last updated on 25/Jul/19 $$\mathrm{No}.\:\mathrm{of}\:\mathrm{term}\:\mathrm{on}\:\mathrm{n}^{\mathrm{tn}} \mathrm{group}\:=\:\mathrm{2n}−\mathrm{1} \\ $$$$\mathrm{The}\:\mathrm{1}^{\mathrm{st}\:} \mathrm{term}\:\mathrm{of}\:\mathrm{the}\:\mathrm{n}^{\mathrm{th}\:} \mathrm{group} \\ $$$$=\:\frac{\left(\mathrm{n}−\mathrm{1}\right)}{\mathrm{2}}\left[\mathrm{2}+\left(\mathrm{n}−\mathrm{2}\right)\mathrm{2}\right]\:+\mathrm{1}\:=\:\left(\mathrm{n}−\mathrm{1}\right)^{\mathrm{2}}…

Question-130649

Question Number 130649 by muneer0o0 last updated on 27/Jan/21 Answered by MJS_new last updated on 27/Jan/21 $$\int\frac{{dx}}{\:\sqrt{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{2}}}=\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\int\frac{{dx}}{\:\sqrt{{x}^{\mathrm{2}} +\frac{\mathrm{3}}{\mathrm{2}}{x}−\mathrm{1}}}= \\ $$$$\:\:\:\:\:\left[{t}={x}+\frac{\mathrm{3}}{\mathrm{4}}\:\rightarrow\:{dx}={dt}\right] \\ $$$$=\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\int\frac{{dt}}{\:\sqrt{{t}^{\mathrm{2}} −\frac{\mathrm{25}}{\mathrm{16}}}}= \\…

Question-130634

Question Number 130634 by EDWIN88 last updated on 27/Jan/21 Answered by liberty last updated on 27/Jan/21 $$\mathrm{coefficient}\:\mathrm{of}\:\mathrm{x}^{\mathrm{8}} \:\mathrm{from}\:\left(\mathrm{1}+\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}!}+\frac{\mathrm{x}^{\mathrm{4}} }{\mathrm{4}!}+\frac{\mathrm{x}^{\mathrm{6}} }{\mathrm{6}!}+\frac{\mathrm{x}^{\mathrm{8}} }{\mathrm{8}!}\right)^{\mathrm{2}} \\ $$$$\mathrm{is}\:\frac{\mathrm{2}}{\mathrm{8}!}+\frac{\mathrm{2}}{\mathrm{2}!\mathrm{6}!}+\frac{\mathrm{1}}{\mathrm{4}!\mathrm{4}!}=\frac{\mathrm{1}}{\mathrm{315}} \\…

Question-130632

Question Number 130632 by bramlexs22 last updated on 27/Jan/21 Answered by EDWIN88 last updated on 27/Jan/21 $$\mathrm{cos}\:\mathrm{4095}°\:=\:\mathrm{cos}\:\left(\mathrm{360}°×\mathrm{11}+\mathrm{135}°\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:−\frac{\sqrt{\mathrm{2}}}{\mathrm{2}} \\ $$$${then}\:\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{cos}\:\mathrm{4095}°\right)=\mathrm{sin}\:\left(−\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right) \\ $$$$\:=−\frac{\pi}{\mathrm{4}} \\…

y-sgn-x-y-

Question Number 130629 by Khalmohmmad last updated on 27/Jan/21 $${y}={sgn}\left({x}\right) \\ $$$$\acute {{y}}=? \\ $$ Answered by MJS_new last updated on 27/Jan/21 $$\mathrm{sgn}\:{x}\::=\begin{cases}{−\mathrm{1};\:{x}<\mathrm{0}}\\{\mathrm{0};\:{x}=\mathrm{0}\:^{\left(\mathrm{1}\right)} }\\{\mathrm{1};\:{x}>\mathrm{0}}\end{cases} \\…