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Author: Tinku Tara

calculate-0-cos-abx-x-2-ax-1-x-2-bx-1-with-a-and-b-real-and-a-lt-2-b-lt-2-

Question Number 130387 by Bird last updated on 25/Jan/21 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{cos}\left({abx}\right)}{\left({x}^{\mathrm{2}} +{ax}+\mathrm{1}\right)\left({x}^{\mathrm{2}} +{bx}+\mathrm{1}\right)} \\ $$$${with}\:{a}\:{and}\:{b}\:{real}\:{and}\:\mid{a}\mid<\mathrm{2},\mid{b}\mid<\mathrm{2} \\ $$ Commented by mathmax by abdo last updated…

let-A-0-pi-dx-cosx-sinx-R-1-find-a-explicit-form-of-A-2-find-also-B-0-pi-dx-cosx-sinx-2-3-calculate-0-pi-dx-2-cosx-sinx-and-0-pi-dx

Question Number 64850 by mathmax by abdo last updated on 22/Jul/19 $${let}\:{A}_{\lambda} \:=\int_{\mathrm{0}} ^{\pi} \:\:\:\frac{{dx}}{\lambda\:\:+{cosx}\:+{sinx}}\:\:\:\:\left(\lambda\:\in\:{R}\right) \\ $$$$\left.\mathrm{1}\right)\:{find}\:{a}\:{explicit}\:{form}\:{of}\:{A}_{\lambda} \\ $$$$\left.\mathrm{2}\right)\:\:{find}\:{also}\:{B}_{\lambda} \:=\int_{\mathrm{0}} ^{\pi} \:\:\frac{{dx}}{\left(\lambda\:+{cosx}\:+{sinx}\right)^{\mathrm{2}} } \\ $$$$\left.\mathrm{3}\right)\:{calculate}\:\int_{\mathrm{0}}…

If-a-2-3i-5-bi-then-a-b-

Question Number 130383 by MrHusseinElmasry last updated on 25/Jan/21 $${If}\:\left({a}−\mathrm{2}\right)+\mathrm{3}{i}=\mathrm{5}−{bi}\:{then}\:{a}+{b}= \\ $$ Answered by mathmax by abdo last updated on 25/Jan/21 $$\mathrm{a}−\mathrm{2}+\mathrm{3i}=\mathrm{5}−\mathrm{bi}\:\Rightarrow\mathrm{a}−\mathrm{2}+\mathrm{3i}−\mathrm{5}+\mathrm{bi}=\mathrm{0}\:\Rightarrow\mathrm{a}−\mathrm{7}+\mathrm{i}\left(\mathrm{3}+\mathrm{b}\right)=\mathrm{0}\:\Rightarrow \\ $$$$\begin{cases}{\mathrm{a}−\mathrm{7}=\mathrm{0}}\\{\mathrm{3}+\mathrm{b}=\mathrm{0}\:\:\:\Rightarrow\begin{cases}{\mathrm{a}=\mathrm{7}}\\{\mathrm{b}=−\mathrm{3}\:}\end{cases}}\end{cases} \\…

Question-130370

Question Number 130370 by gowsalya last updated on 24/Jan/21 Answered by TheSupreme last updated on 24/Jan/21 $${z}={e}^{{i}\theta} \\ $$$$\mid{dz}\mid=\mid{ie}^{{i}\theta} {d}\theta\mid={d}\theta \\ $$$$\int_{\mathrm{0}} ^{\mathrm{2}\pi} \mid{e}^{{i}\theta} −\mathrm{1}\mid{d}\theta…