Question Number 130331 by ayoubbacmath0 last updated on 24/Jan/21 $$\mathrm{f}\left(\mathrm{x}\right)={a}\mathrm{x}^{\mathrm{3}} +\mathrm{bx}^{\mathrm{2}} +\mathrm{c} \\ $$$$\mathrm{f}\:'\left(\mathrm{x}\right)=\mathrm{3}{a}\mathrm{x}^{\mathrm{2}} +\mathrm{2bx} \\ $$$$\mathrm{f}\left(\mathrm{0}\right)=−\mathrm{2} \\ $$$$\Rightarrow{a}\left(\mathrm{0}\right)^{\mathrm{3}} +\mathrm{b}\left(\mathrm{0}\right)^{\mathrm{2}} +\mathrm{c}=−\mathrm{2} \\ $$$$\Rightarrow\mathrm{c}=−\mathrm{2} \\ $$$$\mathrm{f}\left(−\mathrm{2}\right)=\mathrm{2}…
Question Number 130326 by rs4089 last updated on 24/Jan/21 Answered by Lordose last updated on 24/Jan/21 $$ \\ $$$$\Omega\left(\mathrm{p}\right)\:=\:\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{sin}\left(\mathrm{px}\right)}{\mathrm{x}\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)}\mathrm{dx} \\ $$$$\Omega'\left(\mathrm{p}\right)\:=\:\int_{\mathrm{0}} ^{\:\infty}…
Question Number 64791 by Tawa1 last updated on 21/Jul/19 Commented by Tawa1 last updated on 21/Jul/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\mathrm{x} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 130327 by n0y0n last updated on 24/Jan/21 $$\mathrm{proof}\:\mathrm{that}\:\mathrm{laplace}\:\mathrm{transform}\:\:\mathrm{is}\:\mathrm{an}\:\mathrm{one}\:\mathrm{to} \\ $$$$\mathrm{one}\:\mathrm{transform}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130324 by mohammad17 last updated on 24/Jan/21 $${prove}\:{that}\:{lim}_{{z}\rightarrow\mathrm{0}} \:\frac{{z}^{\mathrm{2}} }{\mid{z}\overset{\:\:\mathrm{2}} {\mid}}\:=−\mathrm{1}\:{since}\:{z}={x}+{iy} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64788 by Rio Michael last updated on 21/Jul/19 $${two}\:{consercutive}\:{integers}\:{between}\:{which}\:{a}\:{root}\:{of}\:{the}\:{equation}\:{lie}\:{are}: \\ $$$${x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{2}=\mathrm{0} \\ $$ Commented by MJS last updated on 21/Jul/19 $$\mathrm{the}\:\mathrm{roots}\:\mathrm{are}\:{x}=−\mathrm{2}\:\mathrm{and}\:{x}=−\mathrm{1}\:\mathrm{so}\:\mathrm{there}'\mathrm{s}\:\mathrm{no} \\…
Question Number 130322 by mr W last updated on 24/Jan/21 $${to}\:{TinkuTara} \\ $$$${dear}\:{sir}: \\ $$$${can}\:{you}\:{please}\:{check}\:{following}\:{issue}: \\ $$$${what}\:{could}\:{be}\:{the}\:{reason}\:{that}\:{i}\:{can}'{t} \\ $$$${access}\:{to}\:{my}\:{old}\:{bookmarked}\:{posts} \\ $$$${before}\:{a}\:{special}\:{date}? \\ $$ Commented by…
Question Number 130320 by benjo_mathlover last updated on 24/Jan/21 $$\:\int\:\frac{\mathrm{x}−\mathrm{1}}{\left(\mathrm{x}−\mathrm{2}\right)\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{2}\right)^{\mathrm{2}} }\:\mathrm{dx}\: \\ $$ Answered by EDWIN88 last updated on 24/Jan/21 $$\mathrm{Let}\:\mathcal{E}\:=\:\int\:\frac{{x}−\mathrm{1}}{\left({x}−\mathrm{2}\right)\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{2}\right)^{\mathrm{2}} }\:{dx} \\…
Question Number 64785 by Rio Michael last updated on 21/Jul/19 Answered by LPM last updated on 21/Jul/19 $$\left.\mathrm{1}\right)\:\mathrm{x}_{\mathrm{n}} \leqslant\:\mathrm{2}\:,\forall\:\mathrm{n}\geqslant\mathrm{1} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{x}_{\mathrm{n}} \leqslant\mathrm{x}_{\mathrm{n}+\mathrm{1}} ,\:\forall\:\mathrm{n}\geqslant\mathrm{1} \\ $$$$\:\Rightarrow\:\mathrm{x}_{\mathrm{n}}…
Question Number 130317 by stelor last updated on 24/Jan/21 Answered by mathmax by abdo last updated on 24/Jan/21 $$\mathrm{I}=\int_{−\infty} ^{+\infty} \:\mathrm{x}\:\mathrm{e}^{−\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}} \mathrm{dx}\:\:\mathrm{we}\:\mathrm{do}\:\mathrm{the}\:\mathrm{changement}\:\frac{\mathrm{x}}{\:\sqrt{\mathrm{2}}}=\mathrm{t}\:\Rightarrow \\ $$$$\mathrm{I}=\int_{−\infty}…