Question Number 64745 by mathmax by abdo last updated on 21/Jul/19 $${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{{sin}\left({lnx}\right)}{{lnx}}{dx} \\ $$ Commented by mathmax by abdo last updated on 21/Jul/19…
Question Number 64744 by mathmax by abdo last updated on 21/Jul/19 $${solve}\:^{\mathrm{3}} \sqrt{\mathrm{1}+{x}}+^{\mathrm{3}} \sqrt{\mathrm{1}−{x}}=\mathrm{2} \\ $$ Answered by MJS last updated on 21/Jul/19 $${a}^{\frac{\mathrm{1}}{\mathrm{3}}} +{b}^{\frac{\mathrm{1}}{\mathrm{3}}}…
Question Number 130272 by Aboafya19 last updated on 23/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130270 by ajfour last updated on 23/Jan/21 Commented by ajfour last updated on 23/Jan/21 $${Find}\:{maximum}\:{possible}\:{tension} \\ $$$${in}\:{the}\:{blue}\:{string}. \\ $$ Commented by mr W…
Question Number 64735 by mmkkmm000m last updated on 20/Jul/19 $$\int{tan}\theta/\mathrm{1}\overset{−} {+}{sin}\theta\:{d}\theta \\ $$ Commented by mr W last updated on 21/Jul/19 $${dear}\:{sir}: \\ $$$${in}\:{Q}\mathrm{64238}\:{i}\:{asked}\:{if}\:{you}\:{could}\:{use} \\…
Question Number 64733 by mmkkmm000m last updated on 20/Jul/19 $$\int\left({sec}\theta{tan}\theta\right){d}\theta/{sec}\theta\overset{−} {+}{tan}\theta \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64730 by Tanmay chaudhury last updated on 20/Jul/19 Answered by ajfour last updated on 20/Jul/19 $${E}=\rho{j} \\ $$$$\Rightarrow\:{E}=\frac{\rho{I}}{\mathrm{2}\pi{r}^{\mathrm{2}} } \\ $$$$\bigtriangleup{V}\:=\int{Eds}\:=\:\frac{\rho{I}}{\mathrm{2}\pi}\left(\frac{\mathrm{1}}{{D}}−\frac{\mathrm{1}}{{D}+{w}}\right) \\ $$$${i}=\frac{\bigtriangleup{V}}{{R}}=\:\frac{\rho{Iw}}{\mathrm{2}\pi{RD}\left({D}+{w}\right)}…
Question Number 64729 by Tanmay chaudhury last updated on 20/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64728 by Tanmay chaudhury last updated on 20/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130263 by pete last updated on 23/Jan/21 Answered by Olaf last updated on 23/Jan/21 $$\mathrm{B}\begin{pmatrix}{{x}_{\mathrm{B}} \:=\:\mathrm{12}−\mathrm{2}{y}_{\mathrm{B}} \:=\:\mathrm{12}}\\{\mathrm{0}}\end{pmatrix} \\ $$$$\mathrm{E}\begin{pmatrix}{\mathrm{0}}\\{\frac{\mathrm{1}}{\mathrm{2}}\:=\:\frac{{y}_{\mathrm{E}} }{{x}_{\mathrm{B}} }\:\Rightarrow\:{y}_{\mathrm{E}} \:=\:\mathrm{6}}\end{pmatrix} \\…