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Author: Tinku Tara

solve-G-7x-y-dxdy-where-G-is-given-by-y-0-x-2y-3-x-y-2-i-want-to-know-if-the-integral-below-is-a-correct-representation-of-the-integral-above-0-3-2-0-9-4-7x-y-dxdy-

Question Number 130132 by bait last updated on 22/Jan/21 $${solve}\:\int\int_{{G}} \left(\mathrm{7}{x}−{y}\right){dxdy},\:{where}\:{G}\:{is}\:{given}\:{by}\:{y}=\mathrm{0} \\ $$$${x}+\mathrm{2}{y}=\mathrm{3},\:{x}={y}^{\mathrm{2}} \\ $$$$ \\ $$$${i}\:{want}\:{to}\:{know}\:{if}\:{the}\:{integral}\:{below}\:{is}\:{a}\:{correct} \\ $$$${representation}\:{of}\:{the}\:{integral}\:{above}. \\ $$$$\:\left(\underset{\mathrm{0}} {\overset{\frac{\mathrm{3}}{\mathrm{2}}} {\int}}\underset{\mathrm{0}} {\overset{\frac{\mathrm{9}}{\mathrm{4}}} {\int}}\left(\mathrm{7}{x}−{y}\right){dxdy}\right).…

solve-for-x-0-x-m-0-x-x-ln-m-1-dx-x-2-where-x-is-the-smallest-integer-greater-than-x-

Question Number 130133 by talminator2856791 last updated on 22/Jan/21 $$\: \\ $$$$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{solve}\:\mathrm{for}\:{x} \\ $$$$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:{x}} \underset{{m}=\mathrm{0}} {\overset{\lceil{x}\rceil} {\sum}}{x}^{\mathrm{ln}\:{m}+\mathrm{1}} \:{dx}\:=\:{x}^{\mathrm{2}} \:,\: \\…

lim-x-2-x-2-or-limit-has-

Question Number 130120 by Study last updated on 22/Jan/21 $${li}\underset{{x}\rightarrow\mathrm{2}} {{m}}\sqrt{{x}−\mathrm{2}}=?\:\:\:\:{or}\:{limit}\:{has}? \\ $$ Answered by Olaf last updated on 22/Jan/21 $$ \\ $$$$\underset{{x}\rightarrow\mathrm{2}^{−} } {\mathrm{lim}}\:\sqrt{{x}−\mathrm{2}}\:\mathrm{is}\:\mathrm{undefined}…

lim-x-15-log-x-15-or-limit-has-

Question Number 130119 by Study last updated on 22/Jan/21 $${li}\underset{{x}\rightarrow\mathrm{15}} {{m}log}\left({x}−\mathrm{15}\right)=??\:{or}\:{limit}\:{has}? \\ $$ Answered by Olaf last updated on 22/Jan/21 $$\underset{{x}\rightarrow\mathrm{15}^{−} } {\mathrm{lim}}\:\mathrm{ln}\left({x}−\mathrm{15}\right)\:\mathrm{is}\:\mathrm{undefined} \\ $$$$\mathrm{because}\:{x}−\mathrm{15}\:\mathrm{canno}'\mathrm{t}\:\mathrm{be}\:\mathrm{negative}…