Question Number 130109 by Adel last updated on 22/Jan/21 $$\mathrm{2}+\frac{\mathrm{3}}{\mathrm{2}^{\mathrm{3}} }+\frac{\mathrm{4}}{\mathrm{3}^{\mathrm{3}} }+\frac{\mathrm{5}}{\mathrm{4}^{\mathrm{3}} }+\frac{\mathrm{6}}{\mathrm{5}^{\mathrm{3}} }+\centerdot\centerdot\centerdot\centerdot\centerdot\centerdot\centerdot\centerdot\centerdot=? \\ $$ Answered by Olaf last updated on 22/Jan/21 $$\mathrm{S}\:=\:\underset{{n}=\mathrm{1}} {\overset{\infty}…
Question Number 130104 by mohammad17 last updated on 22/Jan/21 $${find}\:{the}\:{key}\:{value}\:\left[{Arg}\left({z}\right)\right]{for}\:\left(\mathrm{2}+{i}\right)^{\mathrm{1}−{i}} \\ $$ Answered by Olaf last updated on 22/Jan/21 $${z}\:=\:\left(\mathrm{2}+{i}\right)^{\mathrm{1}−{i}} \\ $$$$\mathrm{Z}\:=\:\mathrm{ln}{z}\:=\:\left(\mathrm{1}−{i}\right)\mathrm{ln}\left(\mathrm{2}+{i}\right) \\ $$$$\mathrm{Z}\:=\:\left(\mathrm{1}−{i}\right)\mathrm{ln}\left(\sqrt{\mathrm{5}}{e}^{{i}\mathrm{arctan}\frac{\mathrm{1}}{\mathrm{2}}} \right)…
Question Number 130102 by mohammad17 last updated on 22/Jan/21 $${if}\:{U}\left({x},{y}\right)=\mathrm{2}{x}−{x}^{\mathrm{3}} +\mathrm{3}{xy}^{\mathrm{2}} \:{construct}\:{a}\:{complex}\: \\ $$$${analytical}\:{function},\:{the}\:{expression} \\ $$$${of}\:{which}\:{is}\:{the}\:{true}\:{part}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130103 by mohammad17 last updated on 22/Jan/21 $${by}\:{using}\:{demover}\:{theorem}\:{prove}\:{that} \\ $$$$ \\ $$$${sin}\mathrm{2}\theta=\mathrm{2}{sin}\theta{cos}\theta \\ $$ Answered by Olaf last updated on 22/Jan/21 $$\left(\mathrm{cos}\theta+{i}\mathrm{sin}\theta\right)^{{n}} \:=\:\mathrm{cos}\left({n}\theta\right)+{i}\mathrm{sin}\left({n}\theta\right)…
Question Number 64564 by Tawa1 last updated on 19/Jul/19 Commented by Tony Lin last updated on 19/Jul/19 $${let}\:{cosx}={t} \\ $$$$\frac{{t}}{\mathrm{1}+\frac{\sqrt{\mathrm{1}−{t}^{\mathrm{2}} }}{{t}}}−\frac{\sqrt{\mathrm{1}−{t}^{\mathrm{2}} }}{\mathrm{1}+{t}} \\ $$$$=\frac{{t}^{\mathrm{2}} }{\mathrm{1}+\sqrt{\mathrm{1}−{t}^{\mathrm{2}}…
Question Number 64561 by aliesam last updated on 19/Jul/19 Commented by mathmax by abdo last updated on 20/Jul/19 $${let}\:{P}_{{n}} =\prod_{{k}=\mathrm{0}} ^{{n}} \left(\mathrm{1}+\sigma^{\mathrm{2}^{{k}} } \right)\:\Rightarrow{P}_{{n}} =\left(\mathrm{1}+\sigma\right)\left(\mathrm{1}+\sigma^{\mathrm{2}}…
Question Number 64559 by aliesam last updated on 19/Jul/19 Commented by mathmax by abdo last updated on 20/Jul/19 $${let}\:{I}\:=\int_{\frac{\mathrm{1}}{{e}}} ^{{e}} \sqrt{\frac{\mathrm{1}−\left({lnx}\right)^{\mathrm{2}} }{{x}}}{dx}\:\Rightarrow{I}\:=\int_{\frac{\mathrm{1}}{{e}}} ^{{e}} \sqrt{\mathrm{1}−\left({lnx}\right)^{\mathrm{2}} }\frac{{dx}}{\:\sqrt{{x}}}…
Question Number 130092 by Adel last updated on 22/Jan/21 Commented by 0731619177 last updated on 24/Jan/21 $${hhhh} \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 64557 by LPM last updated on 19/Jul/19 Commented by LPM last updated on 19/Jul/19 $$\mathrm{area}\:\mathrm{of}\:\bigtriangleup\:\mathrm{DBC}\: \\ $$$$ \\ $$ Commented by Tony Lin…
Question Number 130088 by stelor last updated on 22/Jan/21 $$\mathrm{hello}\:\mathrm{please}. \\ $$$$\:\:\int\frac{{dx}}{{a}^{\mathrm{2}} {cos}^{\mathrm{2}} {x}\:+\:{b}^{\mathrm{2}} {sin}^{\mathrm{2}} {x}} \\ $$ Answered by bobhans last updated on 22/Jan/21…