Menu Close

Author: Tinku Tara

7-4x-1-5-4x-1-

Question Number 64397 by rachelleazarcon last updated on 17/Jul/19 $$\frac{\mathrm{7}}{\mathrm{4x}−\mathrm{1}}−\frac{\mathrm{5}}{\mathrm{4x}−\mathrm{1}} \\ $$ Answered by MJS last updated on 17/Jul/19 $$\mathrm{again},\:\mathrm{seriously}? \\ $$$$\frac{{a}}{{b}}+\frac{{c}}{{b}}=\frac{{a}+{c}}{{b}} \\ $$$$\frac{{a}}{{b}}−\frac{{c}}{{b}}=\frac{{a}−{c}}{{b}} \\…

x-2-x-2-

Question Number 64396 by rachelleazarcon last updated on 17/Jul/19 $$\left(\mathrm{x}+\mathrm{2}\right)\left(\mathrm{x}−\mathrm{2}\right) \\ $$ Answered by MJS last updated on 17/Jul/19 $$\mathrm{are}\:\mathrm{you}\:\mathrm{serious}? \\ $$$$\mathrm{study}\:\mathrm{these}\:\mathrm{formulas} \\ $$$$\left({a}+{b}\right)^{\mathrm{2}} ={a}^{\mathrm{2}}…

1-calculate-A-n-0-sin-x-2n-x-2-1-2-dx-with-n-integr-natural-2-study-the-convergene-of-A-n-

Question Number 64392 by mathmax by abdo last updated on 17/Jul/19 $$\left.\mathrm{1}\right){calculate}\:{A}_{{n}} =\int_{\mathrm{0}} ^{\infty} \:\frac{{sin}\left({x}^{\mathrm{2}{n}} \right)}{\left({x}^{\mathrm{2}} \:+\mathrm{1}\right)^{\mathrm{2}} }{dx}\:\:\:{with}\:{n}\:{integr}\:{natural} \\ $$$$\left.\mathrm{2}\right)\:{study}\:{the}\:{convergene}\:{of}\:\Sigma\:{A}_{{n}} \\ $$ Commented by mathmax…

nice-calculus-evaluate-k-0-m-0-n-0-1-k-m-n-

Question Number 129926 by mnjuly1970 last updated on 20/Jan/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…{nice}\:\:\:{calculus}… \\ $$$$\:\:{evaluate}: \\ $$$$\:\:\:\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\:\underset{{m}=\mathrm{0}} {\overset{\infty} {\sum}}\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{1}}{\left({k}+{m}+{n}\right)!}\right)=? \\ $$$$ \\ $$ Answered…

6-a-5-4-a-5-

Question Number 64391 by rachelleazarcon last updated on 17/Jul/19 $$\frac{\mathrm{6}}{\mathrm{a}+\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{a}+\mathrm{5}} \\ $$ Commented by mathmax by abdo last updated on 17/Jul/19 $$=\frac{\mathrm{6}+\mathrm{4}}{{a}+\mathrm{5}}\:=\frac{\mathrm{10}}{{a}+\mathrm{5}} \\ $$ Terms…

Question-64384

Question Number 64384 by aliesam last updated on 17/Jul/19 Answered by MJS last updated on 17/Jul/19 $$\left({y}={x}\right)\cap\left({y}=\frac{{x}}{\mathrm{8}}\right)=\begin{pmatrix}{\mathrm{0}}\\{\mathrm{0}}\end{pmatrix} \\ $$$$\left({y}={x}\right)\cap\left({y}=\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)=\begin{pmatrix}{\mathrm{1}}\\{\mathrm{1}}\end{pmatrix} \\ $$$$\:\:\:\:\:\left[{x}=\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\:\Rightarrow\:{x}^{\mathrm{3}} =\mathrm{1}\:\Rightarrow\:{x}=\mathrm{1}\right] \\…