Question Number 129801 by bramlexs22 last updated on 19/Jan/21 $$\:\mathrm{cot}\:\mathrm{15}°\:\mathrm{cot}\:\mathrm{16}°\:\mathrm{cot}\:\mathrm{17}°…\:\mathrm{cot}\:\mathrm{75}°= \\ $$ Answered by EDWIN88 last updated on 19/Jan/21 $$=\mathrm{1} \\ $$$$\:\left[\:\mathrm{cot}\:\mathrm{15}°=\mathrm{tan}\:\mathrm{75}°\:\mathrm{etc}\:\right]\: \\ $$ Terms…
Question Number 129794 by bramlexs22 last updated on 19/Jan/21 $$\:\:\int\:\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)\left(\mathrm{x}+\mathrm{1}\right)^{−\mathrm{2}/\mathrm{3}} \:\mathrm{dx}\:? \\ $$ Answered by EDWIN88 last updated on 19/Jan/21 $$\:\int\:\left(\mathrm{x}−\mathrm{1}\right)\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{1}/\mathrm{3}} \:\mathrm{dx}\:=\:\left(\mathrm{x}−\mathrm{1}\right)\left(\frac{\mathrm{3}}{\mathrm{4}}\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{4}/\mathrm{3}} \right)−\frac{\mathrm{3}}{\mathrm{4}}\int\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{4}/\mathrm{3}} \:\mathrm{dx}…
Question Number 129795 by ajfour last updated on 19/Jan/21 Commented by ajfour last updated on 19/Jan/21 $${Q}.\mathrm{129660}\:\:\:\left({Revisit}\right) \\ $$ Answered by ajfour last updated on…
Question Number 129788 by bramlexs22 last updated on 19/Jan/21 $$\:\int\:\left(\mathrm{1}+\mathrm{3}{x}^{\mathrm{3}} \right){e}^{{x}^{\mathrm{3}} } \:{dx}\: \\ $$ Answered by EDWIN88 last updated on 19/Jan/21 $$\:\mathrm{let}\:\mathrm{z}\:=\:{xe}^{{x}^{\mathrm{3}} } \:\Rightarrow\:{dz}\:=\:\left({e}^{{x}^{\mathrm{3}}…
Question Number 64253 by Jameel Ahmad last updated on 16/Jul/19 Commented by ajfour last updated on 16/Jul/19 $${Nobel}\:{laurettes},\:{i}\:{think}! \\ $$ Terms of Service Privacy Policy…
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Question Number 129787 by EDWIN88 last updated on 19/Jan/21 $$\:\int\:{x}^{\mathrm{7}} \:\sqrt{\mathrm{1}+{x}^{\mathrm{4}} }\:{dx}\: \\ $$ Answered by bramlexs22 last updated on 19/Jan/21 Commented by MJS_new last…
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Question Number 129785 by bramlexs22 last updated on 19/Jan/21 $$\:\sqrt[{\mathrm{3}}]{\mathrm{2}+\sqrt{\mathrm{5}}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{2}−\sqrt{\mathrm{5}}}\:=? \\ $$$$\:\frac{\mathrm{9}^{\mathrm{x}} −\mathrm{5}.\mathrm{12}^{\mathrm{x}} +\:\mathrm{4}^{\mathrm{2x}+\mathrm{1}} }{\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{6x}^{\mathrm{2}} −\mathrm{11x}+\mathrm{4}\right)}\:\leqslant\:\mathrm{0}\: \\ $$ Answered by EDWIN88 last updated on…
Question Number 64246 by mr W last updated on 16/Jul/19 Answered by mr W last updated on 16/Jul/19 $${x}=\frac{\mathrm{1}}{\mathrm{sin}\:\theta} \\ $$$$\mathrm{tan}\:\frac{\theta}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{sin}\:\theta=\frac{\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}+\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\mathrm{4}}{\mathrm{5}} \\…