Menu Close

Author: Tinku Tara

Question-223896

Question Number 223896 by MASANJAJJ last updated on 08/Aug/25 Commented by mr W last updated on 08/Aug/25 $${y}=\mathrm{81}° \\ $$$${x}\:{can}\:{not}\:{be}\:{determined},\:{because}\:{it} \\ $$$${is}\:{not}\:{clear}\:{what}\:{you}\:{mean}\:{with}\:{the} \\ $$$${angle}\:\angle{AOB}.\:{do}\:{you}\:{mean}\: \\…

Question-223881

Question Number 223881 by fantastic last updated on 08/Aug/25 Answered by som(math1967) last updated on 08/Aug/25 $${let}\:{CP}={x},\:{SP}={y} \\ $$$$\:\frac{\mathrm{15}{x}}{\mathrm{100}}=\frac{\mathrm{25}{y}}{\mathrm{100}} \\ $$$$\Rightarrow\:\frac{{x}}{{y}}=\frac{\mathrm{25}}{\mathrm{15}}=\frac{\mathrm{5}}{\mathrm{3}} \\ $$$$\:\therefore{CP}:{SP}=\mathrm{5}:\mathrm{3} \\ $$$$\:{loss\%}=\frac{\mathrm{2}}{\mathrm{5}}×\mathrm{100}=\mathrm{40\%}…