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Author: Tinku Tara

solve-to-z-2-x-2-y-2-24-

Question Number 64153 by meme last updated on 14/Jul/19 $${solve}\:{to}\:{z}^{\mathrm{2}} \:\:\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} =\mathrm{24} \\ $$ Answered by mr W last updated on 15/Jul/19 $$\left({x}−{y}\right)\left({x}+{y}\right)=\mathrm{24}={a}×{b}=\mathrm{1}×\mathrm{24}=\mathrm{2}×\mathrm{12}=\mathrm{3}×\mathrm{8}=\mathrm{4}×\mathrm{6} \\…

Question-129679

Question Number 129679 by BHOOPENDRA last updated on 17/Jan/21 Answered by mathmax by abdo last updated on 18/Jan/21 $$\mathrm{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{x}\sqrt{\mathrm{tanx}}\mathrm{dx}\:\:\mathrm{changement}\:\sqrt{\mathrm{tanx}}=\mathrm{t}\:\mathrm{give}\:\mathrm{tanx}=\mathrm{t}^{\mathrm{2}} \:\Rightarrow\mathrm{x}=\mathrm{arctan}\left(\mathrm{t}^{\mathrm{2}} \right)\:\Rightarrow \\ $$$$\mathrm{I}=\int_{\mathrm{0}}…

Question-129677

Question Number 129677 by Adel last updated on 17/Jan/21 Commented by som(math1967) last updated on 17/Jan/21 $$\mathrm{3}^{\frac{\mathrm{1}}{{cscx}}×\frac{\mathrm{1}}{{sinx}}×\frac{\mathrm{1}}{{tanx}}×\frac{\mathrm{1}}{{cotx}}} =\mathrm{3}^{\mathrm{1}} =\mathrm{3} \\ $$ Commented by Adel last…

Question-64138

Question Number 64138 by Tawa1 last updated on 14/Jul/19 Answered by som(math1967) last updated on 14/Jul/19 $$\bigtriangleup{ADC}\sim\bigtriangleup{BAC} \\ $$$$\therefore\frac{{AC}}{{DC}}=\frac{{BC}}{{AC}}=\frac{{AB}}{{AD}} \\ $$$$\therefore\frac{{AC}}{{DC}}=\frac{{AB}}{{AD}}=\frac{\mathrm{14}}{\mathrm{7}}\:\:\therefore{AC}=\mathrm{2}{DC} \\ $$$${Again}\:\frac{{AC}}{{DC}}=\frac{{BC}}{{AC}}\:\Rightarrow{AC}^{\mathrm{2}} ={BC}×{DC} \\…